The number of adult blue jay in South Zoo equals the difference between the total number of adult animals in Mayer Aquarium and the number of adult blue jay in Mayer Aquarium. The number of adult blue jay in Bundle Ranch equals 1. The number of adult crow in Jefferson Circus equals 3. The number of adult crow in South Zoo equals the sum of the number of adult blue jay in Mayer Aquarium and the number of adult crow in Mayer Aquarium. The number of adult blue jay in Mayer Aquarium equals 3. The number of adult crow in Mayer Aquarium equals the number of adult blue jay in Mayer Aquarium. The number of adult parrot in Bundle Ranch equals the number of adult blue jay in South Zoo.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult blue jay in Mayer Aquarium as M; so M = 3. Define adult crow in Mayer Aquarium as t; so t = M = 3. Define total number of adult animals in Mayer Aquarium as s; so s = t + M = 3 + 3 = 6. Define adult blue jay in South Zoo as V; so V = s - M = 6 - 3 = 3. Define adult crow in South Zoo as a; so a = M + t = 3 + 3 = 6. Define total number of adult animals in South Zoo as b; so b = a + V = 6 + 3 = 9. Answer: 9.


The number of public highschool in Clearwater Bay equals 4. The number of private middle school in Clearwater Bay equals the sum of the total number of schools in Oakbridge City, the number of private middle school in Oakbridge City, and the number of public highschool in Oakbridge City. The number of public highschool in Oakbridge City equals 1. The number of private middle school in Oakbridge City equals the number of public highschool in Oakbridge City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define public highschool in Oakbridge City as D; so D = 1. Define private middle school in Oakbridge City as V; so V = D = 1. Define total number of schools in Oakbridge City as c; so c = V + D = 1 + 1 = 2. Define private middle school in Clearwater Bay as r; B = c + V = 2 + 1 = 3; so r = B + D = 3 + 1 = 4. Define public highschool in Clearwater Bay as n; so n = 4. Define total number of schools in Clearwater Bay as X; so X = r + n = 4 + 4 = 8. Answer: 8.


The number of culinarian school in Evervale City equals 4 times the number of private middle school in Evervale City. The number of regional medical school in Glenfield City equals 4 times the sum of the total number of schools in Evervale City, the number of private middle school in Evervale City, and the number of culinarian school in Evervale City. The number of private middle school in Evervale City equals 4.

Question: What is the total number of schools in Glenfield City?

Solution: Define private middle school in Evervale City as m; so m = 4. Define culinarian school in Evervale City as e; I = m = 4; so e = 4 * I = 4 * 4 = 16. Define total number of schools in Evervale City as c; so c = m + e = 4 + 16 = 20. Define regional medical school in Glenfield City as l; O = c + m = 20 + 4 = 24; a = O + e = 24 + 16 = 40; so l = 4 * a = 4 * 40 = 160. Define total number of schools in Glenfield City as E; so E = l = 160. Answer: 160.


The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 3. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the sum of the total number of movies in Festival Lumière de Valmont and the number of upbeat metropolis comedy in Festival Lumière de Valmont. The number of calm road movie in Festival Lumière de Valmont equals 3. The number of calm road movie in Festival de Saint-Rivage equals the sum of the number of upbeat metropolis comedy in Festival de Saint-Rivage and the number of calm road movie in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define calm road movie in Festival Lumière de Valmont as u; so u = 3. Define upbeat metropolis comedy in Festival Lumière de Valmont as d; so d = 3. Define total number of movies in Festival Lumière de Valmont as g; so g = d + u = 3 + 3 = 6. Define upbeat metropolis comedy in Festival de Saint-Rivage as z; so z = g + d = 6 + 3 = 9. Define calm road movie in Festival de Saint-Rivage as T; so T = z + u = 9 + 3 = 12. Define total number of movies in Festival de Saint-Rivage as n; so n = z + T = 9 + 12 = 21. Answer: 21.


The number of regional medical school in Westhaven City equals 3. The number of private middle school in Westhaven City equals 2 times the number of regional medical school in Westhaven City. The number of public highschool in Hawkesbury equals 2 times the sum of the total number of schools in Westhaven City, the number of regional medical school in Westhaven City, and the number of private middle school in Westhaven City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define regional medical school in Westhaven City as b; so b = 3. Define private middle school in Westhaven City as S; a = b = 3; so S = 2 * a = 2 * 3 = 6. Define total number of schools in Westhaven City as I; so I = S + b = 6 + 3 = 9. Define public highschool in Hawkesbury as n; T = I + b = 9 + 3 = 12; H = T + S = 12 + 6 = 18; so n = 2 * H = 2 * 18 = 36. Define total number of schools in Hawkesbury as x; so x = n = 36. Answer: 36.


The number of regional medical school in Riverton City equals the number of private middle school in Oakbridge City. The number of regional medical school in Oakbridge City equals 2. The number of private middle school in Oakbridge City equals the number of regional medical school in Oakbridge City. The number of private middle school in Riverton City equals the sum of the total number of schools in Oakbridge City, the number of private middle school in Oakbridge City, and the number of regional medical school in Oakbridge City.

Question: What is the total number of schools in Riverton City?

Solution: Define regional medical school in Oakbridge City as W; so W = 2. Define private middle school in Oakbridge City as V; so V = W = 2. Define total number of schools in Oakbridge City as Y; so Y = W + V = 2 + 2 = 4. Define private middle school in Riverton City as g; R = Y + V = 4 + 2 = 6; so g = R + W = 6 + 2 = 8. Define regional medical school in Riverton City as H; so H = V = 2. Define total number of schools in Riverton City as o; so o = H + g = 2 + 8 = 10. Answer: 10.


The number of solemn period drama in Verdi Movie Festival equals 4. The number of futuristic sci-fi movie in Verdi Movie Festival equals 2 times the number of solemn period drama in Verdi Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 3 plus the sum of the total number of movies in Verdi Movie Festival, the number of solemn period drama in Verdi Movie Festival, and the number of futuristic sci-fi movie in Verdi Movie Festival.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define solemn period drama in Verdi Movie Festival as p; so p = 4. Define futuristic sci-fi movie in Verdi Movie Festival as S; R = p = 4; so S = 2 * R = 2 * 4 = 8. Define total number of movies in Verdi Movie Festival as T; so T = S + p = 8 + 4 = 12. Define solemn period drama in West Sahara Movie Festival as z; b = T + p = 12 + 4 = 16; B = b + S = 16 + 8 = 24; so z = 3 + B = 3 + 24 = 27. Define total number of movies in West Sahara Movie Festival as x; so x = z = 27. Answer: 27.


The number of solemn period drama in Festival Lumière de Valmont equals 4 plus the total number of movies in Rêves de Belleville. The number of futuristic sci-fi movie in Rêves de Belleville equals 4 times the number of solemn period drama in Rêves de Belleville. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 1. The number of solemn period drama in Rêves de Belleville equals 1.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define solemn period drama in Rêves de Belleville as s; so s = 1. Define futuristic sci-fi movie in Rêves de Belleville as L; e = s = 1; so L = 4 * e = 4 * 1 = 4. Define total number of movies in Rêves de Belleville as x; so x = s + L = 1 + 4 = 5. Define futuristic sci-fi movie in Festival Lumière de Valmont as S; so S = 1. Define solemn period drama in Festival Lumière de Valmont as X; q = x = 5; so X = 4 + q = 4 + 5 = 9. Define total number of movies in Festival Lumière de Valmont as m; so m = S + X = 1 + 9 = 10. Answer: 10.


The number of culinarian school in Hawkesbury equals 3 times the number of elementary school in Hawkesbury. The number of elementary school in Brightford equals the sum of the total number of schools in Hawkesbury and the number of elementary school in Hawkesbury. The number of elementary school in Hawkesbury equals 4. The number of culinarian school in Brightford equals the total number of schools in Hawkesbury.

Question: What is the total number of schools in Brightford?

Solution: Define elementary school in Hawkesbury as G; so G = 4. Define culinarian school in Hawkesbury as O; j = G = 4; so O = 3 * j = 3 * 4 = 12. Define total number of schools in Hawkesbury as U; so U = G + O = 4 + 12 = 16. Define culinarian school in Brightford as Y; so Y = U = 16. Define elementary school in Brightford as H; so H = U + G = 16 + 4 = 20. Define total number of schools in Brightford as R; so R = H + Y = 20 + 16 = 36. Answer: 36.


The number of adult owl in Oakridge Riverside equals 3 plus the number of adult owl in Cedar Valley. The number of adult owl in Beverly Forest equals 2. The number of adult owl in Pine Ridge equals the number of adult blue jay in Pine Ridge. The number of adult crow in Cedar Valley equals 4 plus the sum of the total number of adult animals in Beverly Forest, the number of adult blue jay in Pine Ridge, and the number of adult owl in Pine Ridge. The number of adult parrot in Cedar Valley equals 2. The number of adult crow in Pine Ridge equals 2 plus the number of adult parrot in Pine Ridge. The number of adult crow in Oakridge Riverside equals the total number of adult animals in Beverly Forest. The number of adult parrot in Pine Ridge equals 4. The number of adult blue jay in Beverly Forest equals the total number of adult animals in Pine Ridge. The number of adult blue jay in Cedar Valley equals the sum of the number of adult owl in Beverly Forest and the number of adult crow in Cedar Valley. The number of adult blue jay in Pine Ridge equals the number of adult parrot in Pine Ridge. The number of adult owl in Cedar Valley equals 3.

Question: How many adult blue jay does Beverly Forest have?

Solution: Define adult parrot in Pine Ridge as M; so M = 4. Define adult crow in Pine Ridge as U; D = M = 4; so U = 2 + D = 2 + 4 = 6. Define adult blue jay in Pine Ridge as C; so C = M = 4. Define adult owl in Pine Ridge as t; so t = C = 4. Define total number of adult animals in Pine Ridge as Q; Y = C + U = 4 + 6 = 10; H = Y + t = 10 + 4 = 14; so Q = H + M = 14 + 4 = 18. Define adult blue jay in Beverly Forest as S; so S = Q = 18. Answer: 18.


The number of private middle school in Brightford equals 3. The number of regional medical school in Hawkesbury equals 3 plus the sum of the total number of schools in Brightford and the number of private middle school in Brightford. The number of private middle school in Hawkesbury equals 2 plus the sum of the number of private middle school in Brightford and the total number of schools in Brightford.

Question: What is the total number of schools in Hawkesbury?

Solution: Define private middle school in Brightford as u; so u = 3. Define total number of schools in Brightford as C; so C = u = 3. Define regional medical school in Hawkesbury as f; q = C + u = 3 + 3 = 6; so f = 3 + q = 3 + 6 = 9. Define private middle school in Hawkesbury as X; L = u + C = 3 + 3 = 6; so X = 2 + L = 2 + 6 = 8. Define total number of schools in Hawkesbury as O; so O = f + X = 9 + 8 = 17. Answer: 17.


The number of adult deer in Oakridge Riverside equals 4. The number of adult deer in Maple Creek equals 3 times the sum of the total number of adult animals in Beverly Forest, the number of adult racoon in Beverly Forest, and the number of adult fox in Beverly Forest. The number of adult fox in Beverly Forest equals 3 times the number of adult racoon in Beverly Forest. The number of adult racoon in Beverly Forest equals 3. The number of adult deer in Pine Ridge equals 4. The number of adult fox in Cedar Valley equals the difference between the number of adult racoon in Beverly Forest and the number of adult bear in Cedar Valley. The number of adult bear in Cedar Valley equals 3. The number of adult bear in Pine Ridge equals the number of adult deer in Maple Creek. The number of adult wolf in Oakridge Riverside equals the difference between the number of adult deer in Pine Ridge and the number of adult deer in Oakridge Riverside.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult racoon in Beverly Forest as Y; so Y = 3. Define adult fox in Beverly Forest as d; q = Y = 3; so d = 3 * q = 3 * 3 = 9. Define total number of adult animals in Beverly Forest as s; so s = Y + d = 3 + 9 = 12. Define adult deer in Maple Creek as c; R = s + Y = 12 + 3 = 15; i = R + d = 15 + 9 = 24; so c = 3 * i = 3 * 24 = 72. Define total number of adult animals in Maple Creek as h; so h = c = 72. Answer: 72.


The number of regional medical school in Brightford equals 2. The number of culinarian school in Evervale City equals 3. The number of culinarian school in Hawkesbury equals the sum of the total number of schools in Glenfield City and the number of culinarian school in Evervale City. The number of private middle school in Glenfield City equals 1 plus the total number of schools in Evervale City. The number of elementary school in Hawkesbury equals 4. The number of culinarian school in Brightford equals 3.

Question: What is the total number of schools in Hawkesbury?

Solution: Define culinarian school in Evervale City as N; so N = 3. Define total number of schools in Evervale City as E; so E = N = 3. Define private middle school in Glenfield City as f; n = E = 3; so f = 1 + n = 1 + 3 = 4. Define total number of schools in Glenfield City as o; so o = f = 4. Define culinarian school in Hawkesbury as c; so c = o + N = 4 + 3 = 7. Define elementary school in Hawkesbury as k; so k = 4. Define total number of schools in Hawkesbury as C; so C = k + c = 4 + 7 = 11. Answer: 11.


The number of public highschool in Oakbridge City equals 4 plus the number of elementary school in Oakbridge City. The number of elementary school in Riverton City equals 1 plus the sum of the total number of schools in Oakbridge City, the number of elementary school in Oakbridge City, and the number of public highschool in Oakbridge City. The number of elementary school in Oakbridge City equals 3.

Question: What is the total number of schools in Riverton City?

Solution: Define elementary school in Oakbridge City as N; so N = 3. Define public highschool in Oakbridge City as S; j = N = 3; so S = 4 + j = 4 + 3 = 7. Define total number of schools in Oakbridge City as G; so G = S + N = 7 + 3 = 10. Define elementary school in Riverton City as E; I = G + N = 10 + 3 = 13; L = I + S = 13 + 7 = 20; so E = 1 + L = 1 + 20 = 21. Define total number of schools in Riverton City as t; so t = E = 21. Answer: 21.


The number of adult deer in Jefferson Circus equals 2 plus the number of adult bear in Jefferson Circus. The number of adult wolf in Mayer Aquarium equals 3. The number of adult deer in South Zoo equals the difference between the number of adult bear in Jefferson Circus and the number of adult wolf in Hamilton Farm. The number of adult fox in South Zoo equals 2. The number of adult bear in Jefferson Circus equals 2. The number of adult wolf in Hamilton Farm equals 2 plus the sum of the total number of adult animals in Jefferson Circus, the number of adult bear in Jefferson Circus, and the number of adult deer in Jefferson Circus.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult bear in Jefferson Circus as q; so q = 2. Define adult deer in Jefferson Circus as M; K = q = 2; so M = 2 + K = 2 + 2 = 4. Define total number of adult animals in Jefferson Circus as Y; so Y = M + q = 4 + 2 = 6. Define adult wolf in Hamilton Farm as c; n = Y + q = 6 + 2 = 8; G = n + M = 8 + 4 = 12; so c = 2 + G = 2 + 12 = 14. Define total number of adult animals in Hamilton Farm as I; so I = c = 14. Answer: 14.


The number of calm road movie in West Sahara Movie Festival equals the total number of movies in Taylor Movie Festival. The number of calm road movie in Taylor Movie Festival equals 2. The number of futuristic sci-fi movie in Taylor Movie Festival equals the sum of the number of futuristic sci-fi movie in West Sahara Movie Festival and the number of calm road movie in Taylor Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 3 plus the number of calm road movie in Taylor Movie Festival.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define calm road movie in Taylor Movie Festival as q; so q = 2. Define futuristic sci-fi movie in West Sahara Movie Festival as H; u = q = 2; so H = 3 + u = 3 + 2 = 5. Define futuristic sci-fi movie in Taylor Movie Festival as W; so W = H + q = 5 + 2 = 7. Define total number of movies in Taylor Movie Festival as r; so r = q + W = 2 + 7 = 9. Define calm road movie in West Sahara Movie Festival as V; so V = r = 9. Define total number of movies in West Sahara Movie Festival as z; so z = V + H = 9 + 5 = 14. Answer: 14.


The number of private middle school in Oakbridge City equals 2. The number of private middle school in Shoreline City equals 3 times the total number of schools in Oakbridge City. The number of private middle school in Clearwater Bay equals the total number of schools in Shoreline City. The number of private middle school in Ruby Bay equals 3 times the total number of schools in Clearwater Bay.

Question: What is the total number of schools in Ruby Bay?

Solution: Define private middle school in Oakbridge City as g; so g = 2. Define total number of schools in Oakbridge City as c; so c = g = 2. Define private middle school in Shoreline City as N; V = c = 2; so N = 3 * V = 3 * 2 = 6. Define total number of schools in Shoreline City as A; so A = N = 6. Define private middle school in Clearwater Bay as w; so w = A = 6. Define total number of schools in Clearwater Bay as d; so d = w = 6. Define private middle school in Ruby Bay as W; J = d = 6; so W = 3 * J = 3 * 6 = 18. Define total number of schools in Ruby Bay as y; so y = W = 18. Answer: 18.


The number of adult racoon in Jefferson Circus equals 2 plus the difference between the total number of adult animals in Mayer Aquarium and the number of adult wolf in Mayer Aquarium. The number of adult fox in South Zoo equals the sum of the total number of adult animals in Jefferson Circus, the number of adult wolf in Mayer Aquarium, and the total number of adult animals in Mayer Aquarium. The number of adult wolf in Mayer Aquarium equals 4.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult wolf in Mayer Aquarium as R; so R = 4. Define total number of adult animals in Mayer Aquarium as d; so d = R = 4. Define adult racoon in Jefferson Circus as G; y = d - R = 4 - 4 = 0; so G = 2 + y = 2 + 0 = 2. Define total number of adult animals in Jefferson Circus as W; so W = G = 2. Define adult fox in South Zoo as n; D = W + R = 2 + 4 = 6; so n = D + d = 6 + 4 = 10. Define total number of adult animals in South Zoo as e; so e = n = 10. Answer: 10.


The number of adult deer in Pine Ridge equals 1 plus the number of adult wolf in Pine Ridge. The number of adult wolf in Pine Ridge equals 2. The number of adult wolf in Cedar Valley equals 4 plus the sum of the total number of adult animals in Pine Ridge, the number of adult wolf in Pine Ridge, and the number of adult deer in Pine Ridge.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult wolf in Pine Ridge as R; so R = 2. Define adult deer in Pine Ridge as H; n = R = 2; so H = 1 + n = 1 + 2 = 3. Define total number of adult animals in Pine Ridge as B; so B = H + R = 3 + 2 = 5. Define adult wolf in Cedar Valley as O; p = B + R = 5 + 2 = 7; W = p + H = 7 + 3 = 10; so O = 4 + W = 4 + 10 = 14. Define total number of adult animals in Cedar Valley as r; so r = O = 14. Answer: 14.


The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the total number of movies in Festival de Clairmont. The number of intense detective thriller in Festival Lumière de Valmont equals 4 times the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of intense detective thriller in Festival de Clairmont equals 3 times the number of futuristic sci-fi movie in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Clairmont equals 2.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define futuristic sci-fi movie in Festival de Clairmont as X; so X = 2. Define intense detective thriller in Festival de Clairmont as y; m = X = 2; so y = 3 * m = 3 * 2 = 6. Define total number of movies in Festival de Clairmont as x; so x = X + y = 2 + 6 = 8. Define futuristic sci-fi movie in Festival Lumière de Valmont as n; so n = x = 8. Define intense detective thriller in Festival Lumière de Valmont as t; h = n = 8; so t = 4 * h = 4 * 8 = 32. Define total number of movies in Festival Lumière de Valmont as c; so c = t + n = 32 + 8 = 40. Answer: 40.


The number of adult crow in Cedar Valley equals 2 times the sum of the total number of adult animals in Beverly Forest and the number of adult crow in Beverly Forest. The number of adult blue jay in Beverly Forest equals 1. The number of adult crow in Beverly Forest equals the number of adult blue jay in Beverly Forest. The number of adult blue jay in Cedar Valley equals the number of adult crow in Beverly Forest.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult blue jay in Beverly Forest as l; so l = 1. Define adult crow in Beverly Forest as K; so K = l = 1. Define total number of adult animals in Beverly Forest as m; so m = l + K = 1 + 1 = 2. Define adult crow in Cedar Valley as v; w = m + K = 2 + 1 = 3; so v = 2 * w = 2 * 3 = 6. Define adult blue jay in Cedar Valley as j; so j = K = 1. Define total number of adult animals in Cedar Valley as d; so d = j + v = 1 + 6 = 7. Answer: 7.


The number of adult deer in Bundle Ranch equals 4 times the sum of the total number of adult animals in South Zoo and the number of adult racoon in South Zoo. The number of adult racoon in South Zoo equals 3. The number of adult racoon in Bundle Ranch equals the sum of the number of adult racoon in South Zoo, the total number of adult animals in South Zoo, and the number of adult deer in Bundle Ranch.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult racoon in South Zoo as a; so a = 3. Define total number of adult animals in South Zoo as b; so b = a = 3. Define adult deer in Bundle Ranch as L; u = b + a = 3 + 3 = 6; so L = 4 * u = 4 * 6 = 24. Define adult racoon in Bundle Ranch as o; J = a + b = 3 + 3 = 6; so o = J + L = 6 + 24 = 30. Define total number of adult animals in Bundle Ranch as x; so x = L + o = 24 + 30 = 54. Answer: 54.


The number of adult eagle in Cedar Valley equals 2 times the number of adult blue jay in Cedar Valley. The number of adult eagle in Pine Ridge equals 2 times the total number of adult animals in Maple Creek. The number of adult blue jay in Cedar Valley equals 4. The number of adult eagle in Maple Creek equals the total number of adult animals in Cedar Valley.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult blue jay in Cedar Valley as X; so X = 4. Define adult eagle in Cedar Valley as d; v = X = 4; so d = 2 * v = 2 * 4 = 8. Define total number of adult animals in Cedar Valley as r; so r = X + d = 4 + 8 = 12. Define adult eagle in Maple Creek as y; so y = r = 12. Define total number of adult animals in Maple Creek as j; so j = y = 12. Define adult eagle in Pine Ridge as t; a = j = 12; so t = 2 * a = 2 * 12 = 24. Define total number of adult animals in Pine Ridge as B; so B = t = 24. Answer: 24.


The number of adult deer in Cedar Valley equals the sum of the total number of adult animals in Oakridge Riverside and the number of adult deer in Oakridge Riverside. The number of adult deer in Oakridge Riverside equals 2. The number of adult bear in Oakridge Riverside equals 3 times the number of adult deer in Oakridge Riverside. The number of adult bear in Cedar Valley equals the total number of adult animals in Oakridge Riverside.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult deer in Oakridge Riverside as S; so S = 2. Define adult bear in Oakridge Riverside as J; R = S = 2; so J = 3 * R = 3 * 2 = 6. Define total number of adult animals in Oakridge Riverside as B; so B = J + S = 6 + 2 = 8. Define adult bear in Cedar Valley as P; so P = B = 8. Define adult deer in Cedar Valley as V; so V = B + S = 8 + 2 = 10. Define total number of adult animals in Cedar Valley as c; so c = P + V = 8 + 10 = 18. Answer: 18.


The number of futuristic sci-fi movie in Rêves de Belleville equals 4. The number of calm road movie in Rêves de Belleville equals 4 plus the number of futuristic sci-fi movie in Rêves de Belleville. The number of calm road movie in Festival de Clairmont equals the sum of the total number of movies in Rêves de Belleville and the number of calm road movie in Rêves de Belleville. The number of futuristic sci-fi movie in Festival de Clairmont equals the number of calm road movie in Festival de Clairmont.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define futuristic sci-fi movie in Rêves de Belleville as Z; so Z = 4. Define calm road movie in Rêves de Belleville as D; f = Z = 4; so D = 4 + f = 4 + 4 = 8. Define total number of movies in Rêves de Belleville as a; so a = Z + D = 4 + 8 = 12. Define calm road movie in Festival de Clairmont as i; so i = a + D = 12 + 8 = 20. Define futuristic sci-fi movie in Festival de Clairmont as T; so T = i = 20. Define total number of movies in Festival de Clairmont as u; so u = T + i = 20 + 20 = 40. Answer: 40.


The number of regional medical school in Brightford equals the number of private middle school in Brightford. The number of regional medical school in Westhaven City equals 1 plus the total number of schools in Brightford. The number of private middle school in Westhaven City equals 2 plus the number of regional medical school in Brightford. The number of private middle school in Brightford equals 3.

Question: What is the total number of schools in Westhaven City?

Solution: Define private middle school in Brightford as W; so W = 3. Define regional medical school in Brightford as N; so N = W = 3. Define total number of schools in Brightford as w; so w = N + W = 3 + 3 = 6. Define regional medical school in Westhaven City as K; J = w = 6; so K = 1 + J = 1 + 6 = 7. Define private middle school in Westhaven City as i; H = N = 3; so i = 2 + H = 2 + 3 = 5. Define total number of schools in Westhaven City as d; so d = K + i = 7 + 5 = 12. Answer: 12.