The number of intense detective thriller in Northwood Movie Festival equals 3 times the sum of the total number of movies in Golden Banana Movie Festival and the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 4. The number of futuristic sci-fi movie in Northwood Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 4 times the number of solemn period drama in Golden Banana Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 2 plus the difference between the total number of movies in Northwood Movie Festival and the number of futuristic sci-fi movie in Golden Banana Movie Festival.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define solemn period drama in Golden Banana Movie Festival as M; so M = 4. Define futuristic sci-fi movie in Golden Banana Movie Festival as m; q = M = 4; so m = 4 * q = 4 * 4 = 16. Define total number of movies in Golden Banana Movie Festival as e; so e = M + m = 4 + 16 = 20. Define intense detective thriller in Northwood Movie Festival as d; h = e + M = 20 + 4 = 24; so d = 3 * h = 3 * 24 = 72. Define futuristic sci-fi movie in Northwood Movie Festival as g; so g = e = 20. Define total number of movies in Northwood Movie Festival as X; so X = g + d = 20 + 72 = 92. Define intense detective thriller in Taylor Movie Festival as O; J = X - m = 92 - 16 = 76; so O = 2 + J = 2 + 76 = 78. Define total number of movies in Taylor Movie Festival as x; so x = O = 78. Answer: 78.


The number of culinarian school in Glenfield City equals 4 times the number of regional medical school in Glenfield City. The number of regional medical school in Hawkesbury equals the sum of the number of private middle school in Evervale City and the number of regional medical school in Glenfield City. The number of private middle school in Hawkesbury equals 4. The number of regional medical school in Glenfield City equals 1 plus the number of culinarian school in Hawkesbury. The number of culinarian school in Evervale City equals the number of culinarian school in Glenfield City. The number of regional medical school in Evervale City equals the number of culinarian school in Hawkesbury. The number of culinarian school in Hawkesbury equals 1. The number of private middle school in Evervale City equals 4 times the difference between the total number of schools in Glenfield City and the number of regional medical school in Glenfield City.

Question: What is the total number of schools in Evervale City?

Solution: Define culinarian school in Hawkesbury as E; so E = 1. Define regional medical school in Glenfield City as J; j = E = 1; so J = 1 + j = 1 + 1 = 2. Define culinarian school in Glenfield City as p; M = J = 2; so p = 4 * M = 4 * 2 = 8. Define total number of schools in Glenfield City as r; so r = J + p = 2 + 8 = 10. Define private middle school in Evervale City as c; F = r - J = 10 - 2 = 8; so c = 4 * F = 4 * 8 = 32. Define regional medical school in Evervale City as n; so n = E = 1. Define culinarian school in Evervale City as b; so b = p = 8. Define total number of schools in Evervale City as q; R = n + c = 1 + 32 = 33; so q = R + b = 33 + 8 = 41. Answer: 41.


The number of adult blue jay in Beverly Forest equals 2 times the sum of the number of adult owl in Beverly Forest and the total number of adult animals in Maple Creek. The number of adult blue jay in Maple Creek equals 3. The number of adult owl in Beverly Forest equals 3 times the total number of adult animals in Oakridge Riverside. The number of adult parrot in Oakridge Riverside equals 2. The number of adult owl in Oakridge Riverside equals 3 plus the difference between the total number of adult animals in Maple Creek and the number of adult blue jay in Maple Creek.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult blue jay in Maple Creek as s; so s = 3. Define total number of adult animals in Maple Creek as P; so P = s = 3. Define adult owl in Oakridge Riverside as X; S = P - s = 3 - 3 = 0; so X = 3 + S = 3 + 0 = 3. Define adult parrot in Oakridge Riverside as o; so o = 2. Define total number of adult animals in Oakridge Riverside as r; so r = o + X = 2 + 3 = 5. Define adult owl in Beverly Forest as J; i = r = 5; so J = 3 * i = 3 * 5 = 15. Define adult blue jay in Beverly Forest as B; V = J + P = 15 + 3 = 18; so B = 2 * V = 2 * 18 = 36. Define total number of adult animals in Beverly Forest as u; so u = B + J = 36 + 15 = 51. Answer: 51.


The number of adult parrot in Mayer Aquarium equals the number of adult crow in Hamilton Farm. The number of adult eagle in Jefferson Circus equals 2. The number of adult eagle in Bundle Ranch equals the number of adult blue jay in Hamilton Farm. The number of adult blue jay in Hamilton Farm equals 3. The number of adult owl in Bundle Ranch equals 2 times the number of adult blue jay in Hamilton Farm. The number of adult crow in Jefferson Circus equals the total number of adult animals in Bundle Ranch. The number of adult owl in South Zoo equals 2 plus the number of adult blue jay in Jefferson Circus. The number of adult crow in Hamilton Farm equals the number of adult crow in Jefferson Circus. The number of adult owl in Mayer Aquarium equals the number of adult eagle in Jefferson Circus. The number of adult parrot in Bundle Ranch equals the number of adult blue jay in Hamilton Farm. The number of adult blue jay in Jefferson Circus equals the number of adult parrot in Mayer Aquarium.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult blue jay in Hamilton Farm as R; so R = 3. Define adult owl in Bundle Ranch as l; t = R = 3; so l = 2 * t = 2 * 3 = 6. Define adult parrot in Bundle Ranch as v; so v = R = 3. Define adult eagle in Bundle Ranch as H; so H = R = 3. Define total number of adult animals in Bundle Ranch as g; S = l + H = 6 + 3 = 9; so g = S + v = 9 + 3 = 12. Define adult crow in Jefferson Circus as V; so V = g = 12. Define adult crow in Hamilton Farm as W; so W = V = 12. Define adult parrot in Mayer Aquarium as x; so x = W = 12. Define adult blue jay in Jefferson Circus as h; so h = x = 12. Define adult owl in South Zoo as Z; b = h = 12; so Z = 2 + b = 2 + 12 = 14. Define total number of adult animals in South Zoo as e; so e = Z = 14. Answer: 14.


The number of adult racoon in Cedar Valley equals 4. The number of adult bear in Cedar Valley equals 4. The number of adult racoon in Beverly Forest equals 4 plus the difference between the total number of adult animals in Beverly Forest and the number of adult bear in Maple Creek. The number of adult bear in Beverly Forest equals 3. The number of adult fox in Maple Creek equals 4. The number of adult fox in Beverly Forest equals 3 times the sum of the number of adult fox in Cedar Valley and the total number of adult animals in Maple Creek. The number of adult fox in Cedar Valley equals 4 times the difference between the total number of adult animals in Maple Creek and the number of adult racoon in Maple Creek. The number of adult bear in Maple Creek equals 4 times the number of adult fox in Maple Creek. The number of adult racoon in Maple Creek equals 2 times the difference between the number of adult bear in Maple Creek and the number of adult fox in Maple Creek.

Question: How many adult fox does Beverly Forest have?

Solution: Define adult fox in Maple Creek as S; so S = 4. Define adult bear in Maple Creek as t; P = S = 4; so t = 4 * P = 4 * 4 = 16. Define adult racoon in Maple Creek as r; s = t - S = 16 - 4 = 12; so r = 2 * s = 2 * 12 = 24. Define total number of adult animals in Maple Creek as Q; z = S + r = 4 + 24 = 28; so Q = z + t = 28 + 16 = 44. Define adult fox in Cedar Valley as v; l = Q - r = 44 - 24 = 20; so v = 4 * l = 4 * 20 = 80. Define adult fox in Beverly Forest as j; X = v + Q = 80 + 44 = 124; so j = 3 * X = 3 * 124 = 372. Answer: 372.


The number of futuristic sci-fi movie in Taylor Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals the total number of movies in Verdi Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 4. The number of solemn period drama in Northwood Movie Festival equals 2 times the total number of movies in West Sahara Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the total number of movies in Taylor Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define solemn period drama in Verdi Movie Festival as m; so m = 4. Define calm road movie in Verdi Movie Festival as t; so t = m = 4. Define total number of movies in Verdi Movie Festival as W; so W = t + m = 4 + 4 = 8. Define intense detective thriller in Golden Banana Movie Festival as y; so y = W = 8. Define total number of movies in Golden Banana Movie Festival as c; so c = y = 8. Define intense detective thriller in Taylor Movie Festival as l; so l = c = 8. Define futuristic sci-fi movie in Taylor Movie Festival as p; so p = m = 4. Define total number of movies in Taylor Movie Festival as E; so E = l + p = 8 + 4 = 12. Define upbeat metropolis comedy in West Sahara Movie Festival as Y; so Y = E = 12. Define total number of movies in West Sahara Movie Festival as C; so C = Y = 12. Define solemn period drama in Northwood Movie Festival as O; Q = C = 12; so O = 2 * Q = 2 * 12 = 24. Define total number of movies in Northwood Movie Festival as v; so v = O = 24. Answer: 24.


The number of calm road movie in Festival de Clairmont equals 4 times the sum of the total number of movies in Rêves de Belleville and the number of solemn period drama in Rêves de Belleville. The number of intense detective thriller in Cinéma de Montreval equals the sum of the total number of movies in Rêves de Belleville, the number of calm road movie in Festival de Clairmont, the number of calm road movie in Cinéma de Montreval, and the total number of movies in Festival de Clairmont. The number of calm road movie in Rêves de Belleville equals the total number of movies in Festival Lumière de Valmont. The number of solemn period drama in Rêves de Belleville equals 4 plus the number of calm road movie in Rêves de Belleville. The number of futuristic sci-fi movie in Cinéma de Montreval equals the number of intense detective thriller in Festival de Saint-Rivage. The number of calm road movie in Cinéma de Montreval equals 1. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the sum of the number of calm road movie in Cinéma de Montreval and the number of upbeat metropolis comedy in Festival Lumière de Valmont. The number of intense detective thriller in Festival de Saint-Rivage equals the number of calm road movie in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 4. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the number of upbeat metropolis comedy in Festival Lumière de Valmont. The number of solemn period drama in Festival de Clairmont equals 3.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define upbeat metropolis comedy in Festival Lumière de Valmont as g; so g = 4. Define futuristic sci-fi movie in Festival Lumière de Valmont as V; so V = g = 4. Define total number of movies in Festival Lumière de Valmont as O; so O = g + V = 4 + 4 = 8. Define calm road movie in Rêves de Belleville as M; so M = O = 8. Define solemn period drama in Rêves de Belleville as T; D = M = 8; so T = 4 + D = 4 + 8 = 12. Define total number of movies in Rêves de Belleville as h; so h = M + T = 8 + 12 = 20. Define calm road movie in Festival de Clairmont as d; Z = h + T = 20 + 12 = 32; so d = 4 * Z = 4 * 32 = 128. Define solemn period drama in Festival de Clairmont as e; so e = 3. Define total number of movies in Festival de Clairmont as N; so N = d + e = 128 + 3 = 131. Answer: 131.


The number of adult racoon in Jefferson Circus equals 4. The number of adult wolf in Bundle Ranch equals 2 plus the number of adult deer in Jefferson Circus. The number of adult bear in Bundle Ranch equals the sum of the number of adult wolf in Bundle Ranch and the number of adult racoon in Bundle Ranch. The number of adult bear in Mayer Aquarium equals 4 times the number of adult racoon in Mayer Aquarium. The number of adult racoon in Bundle Ranch equals the number of adult deer in Jefferson Circus. The number of adult deer in Mayer Aquarium equals 3. The number of adult wolf in South Zoo equals the total number of adult animals in Jefferson Circus. The number of adult bear in South Zoo equals 2. The number of adult racoon in Mayer Aquarium equals 3. The number of adult deer in Bundle Ranch equals the sum of the number of adult racoon in Bundle Ranch, the number of adult wolf in Bundle Ranch, and the number of adult deer in Jefferson Circus. The number of adult deer in Jefferson Circus equals 2. The number of adult wolf in Jefferson Circus equals the difference between the total number of adult animals in Bundle Ranch and the number of adult bear in Bundle Ranch.

Question: How many adult wolf does Jefferson Circus have?

Solution: Define adult deer in Jefferson Circus as Y; so Y = 2. Define adult wolf in Bundle Ranch as k; h = Y = 2; so k = 2 + h = 2 + 2 = 4. Define adult racoon in Bundle Ranch as o; so o = Y = 2. Define adult deer in Bundle Ranch as X; x = o + k = 2 + 4 = 6; so X = x + Y = 6 + 2 = 8. Define adult bear in Bundle Ranch as s; so s = k + o = 4 + 2 = 6. Define total number of adult animals in Bundle Ranch as W; i = X + o = 8 + 2 = 10; G = i + s = 10 + 6 = 16; so W = G + k = 16 + 4 = 20. Define adult wolf in Jefferson Circus as p; so p = W - s = 20 - 6 = 14. Answer: 14.


The number of adult owl in Cedar Valley equals 3 times the difference between the number of adult blue jay in Cedar Valley and the number of adult owl in Pine Ridge. The number of adult owl in Pine Ridge equals 4. The number of adult crow in Maple Creek equals 4 plus the number of adult owl in Cedar Valley. The number of adult blue jay in Maple Creek equals the number of adult blue jay in Cedar Valley. The number of adult eagle in Beverly Forest equals 4 plus the difference between the total number of adult animals in Maple Creek and the number of adult owl in Pine Ridge. The number of adult blue jay in Cedar Valley equals 3 plus the number of adult owl in Pine Ridge.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult owl in Pine Ridge as t; so t = 4. Define adult blue jay in Cedar Valley as H; k = t = 4; so H = 3 + k = 3 + 4 = 7. Define adult owl in Cedar Valley as c; G = H - t = 7 - 4 = 3; so c = 3 * G = 3 * 3 = 9. Define adult crow in Maple Creek as E; V = c = 9; so E = 4 + V = 4 + 9 = 13. Define adult blue jay in Maple Creek as X; so X = H = 7. Define total number of adult animals in Maple Creek as S; so S = E + X = 13 + 7 = 20. Define adult eagle in Beverly Forest as l; h = S - t = 20 - 4 = 16; so l = 4 + h = 4 + 16 = 20. Define total number of adult animals in Beverly Forest as K; so K = l = 20. Answer: 20.


The number of public highschool in Riverton City equals the total number of schools in Clearwater Bay. The number of regional medical school in Oakbridge City equals 4 times the sum of the total number of schools in Riverton City and the number of public highschool in Riverton City. The number of culinarian school in Clearwater Bay equals 4. The number of public highschool in Clearwater Bay equals 4 times the number of culinarian school in Clearwater Bay. The number of culinarian school in Riverton City equals 4 plus the difference between the total number of schools in Clearwater Bay and the number of culinarian school in Clearwater Bay.

Question: What is the total number of schools in Oakbridge City?

Solution: Define culinarian school in Clearwater Bay as N; so N = 4. Define public highschool in Clearwater Bay as B; w = N = 4; so B = 4 * w = 4 * 4 = 16. Define total number of schools in Clearwater Bay as r; so r = N + B = 4 + 16 = 20. Define culinarian school in Riverton City as S; t = r - N = 20 - 4 = 16; so S = 4 + t = 4 + 16 = 20. Define public highschool in Riverton City as X; so X = r = 20. Define total number of schools in Riverton City as D; so D = S + X = 20 + 20 = 40. Define regional medical school in Oakbridge City as W; c = D + X = 40 + 20 = 60; so W = 4 * c = 4 * 60 = 240. Define total number of schools in Oakbridge City as z; so z = W = 240. Answer: 240.


The number of adult eagle in Jefferson Circus equals the number of adult blue jay in Jefferson Circus. The number of adult eagle in Hamilton Farm equals the number of adult blue jay in Mayer Aquarium. The number of adult parrot in Jefferson Circus equals 4. The number of adult blue jay in Jefferson Circus equals 2 times the sum of the number of adult blue jay in Hamilton Farm and the number of adult parrot in Mayer Aquarium. The number of adult eagle in Mayer Aquarium equals 3. The number of adult blue jay in Hamilton Farm equals 1 plus the number of adult parrot in Mayer Aquarium. The number of adult blue jay in Mayer Aquarium equals 1 plus the sum of the total number of adult animals in Jefferson Circus, the number of adult blue jay in Jefferson Circus, and the number of adult blue jay in Hamilton Farm. The number of adult parrot in Hamilton Farm equals the number of adult eagle in Mayer Aquarium. The number of adult parrot in Mayer Aquarium equals 4.

Question: How many adult blue jay does Mayer Aquarium have?

Solution: Define adult parrot in Mayer Aquarium as R; so R = 4. Define adult blue jay in Hamilton Farm as D; z = R = 4; so D = 1 + z = 1 + 4 = 5. Define adult blue jay in Jefferson Circus as k; Z = D + R = 5 + 4 = 9; so k = 2 * Z = 2 * 9 = 18. Define adult eagle in Jefferson Circus as e; so e = k = 18. Define adult parrot in Jefferson Circus as G; so G = 4. Define total number of adult animals in Jefferson Circus as h; M = e + G = 18 + 4 = 22; so h = M + k = 22 + 18 = 40. Define adult blue jay in Mayer Aquarium as f; C = h + k = 40 + 18 = 58; T = C + D = 58 + 5 = 63; so f = 1 + T = 1 + 63 = 64. Answer: 64.


The number of solemn period drama in Taylor Movie Festival equals 4 times the number of futuristic sci-fi movie in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 3. The number of futuristic sci-fi movie in Taylor Movie Festival equals the sum of the number of intense detective thriller in Verdi Movie Festival, the number of solemn period drama in Taylor Movie Festival, and the number of futuristic sci-fi movie in Verdi Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals the difference between the number of intense detective thriller in Verdi Movie Festival and the number of futuristic sci-fi movie in Northwood Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4 plus the total number of movies in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the number of intense detective thriller in Verdi Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 4. The number of intense detective thriller in Verdi Movie Festival equals 1. The number of futuristic sci-fi movie in Verdi Movie Festival equals 2 times the number of futuristic sci-fi movie in Northwood Movie Festival.

Question: How many solemn period drama does Northwood Movie Festival have?

Solution: Define futuristic sci-fi movie in Northwood Movie Festival as m; so m = 4. Define futuristic sci-fi movie in Verdi Movie Festival as J; B = m = 4; so J = 2 * B = 2 * 4 = 8. Define solemn period drama in Taylor Movie Festival as e; w = J = 8; so e = 4 * w = 4 * 8 = 32. Define intense detective thriller in Verdi Movie Festival as O; so O = 1. Define futuristic sci-fi movie in Taylor Movie Festival as x; E = O + e = 1 + 32 = 33; so x = E + J = 33 + 8 = 41. Define intense detective thriller in Taylor Movie Festival as o; so o = O = 1. Define total number of movies in Taylor Movie Festival as L; j = x + e = 41 + 32 = 73; so L = j + o = 73 + 1 = 74. Define solemn period drama in Northwood Movie Festival as a; S = L = 74; so a = 4 + S = 4 + 74 = 78. Answer: 78.


The number of regional medical school in Evervale City equals the number of elementary school in Brightford. The number of regional medical school in Hawkesbury equals 2 times the total number of schools in Westhaven City. The number of private middle school in Westhaven City equals 2 times the total number of schools in Brightford. The number of private middle school in Evervale City equals the total number of schools in Hawkesbury. The number of elementary school in Brightford equals 4. The number of public highschool in Evervale City equals 1 plus the total number of schools in Hawkesbury.

Question: What is the total number of schools in Evervale City?

Solution: Define elementary school in Brightford as g; so g = 4. Define total number of schools in Brightford as Q; so Q = g = 4. Define private middle school in Westhaven City as O; w = Q = 4; so O = 2 * w = 2 * 4 = 8. Define total number of schools in Westhaven City as M; so M = O = 8. Define regional medical school in Hawkesbury as N; A = M = 8; so N = 2 * A = 2 * 8 = 16. Define total number of schools in Hawkesbury as V; so V = N = 16. Define private middle school in Evervale City as u; so u = V = 16. Define public highschool in Evervale City as l; f = V = 16; so l = 1 + f = 1 + 16 = 17. Define regional medical school in Evervale City as I; so I = g = 4. Define total number of schools in Evervale City as S; i = I + l = 4 + 17 = 21; so S = i + u = 21 + 16 = 37. Answer: 37.


The number of adult wolf in Pine Ridge equals 4. The number of adult deer in Maple Creek equals the sum of the total number of adult animals in Pine Ridge, the number of adult fox in Pine Ridge, and the number of adult deer in Pine Ridge. The number of adult bear in Pine Ridge equals the number of adult fox in Pine Ridge. The number of adult fox in Maple Creek equals 3 plus the difference between the total number of adult animals in Cedar Valley and the total number of adult animals in Oakridge Riverside. The number of adult fox in Pine Ridge equals 2 times the number of adult wolf in Pine Ridge. The number of adult deer in Pine Ridge equals the number of adult wolf in Pine Ridge. The number of adult fox in Oakridge Riverside equals the difference between the number of adult bear in Oakridge Riverside and the number of adult wolf in Maple Creek. The number of adult wolf in Maple Creek equals 4. The number of adult bear in Maple Creek equals the sum of the number of adult fox in Pine Ridge, the number of adult fox in Cedar Valley, and the total number of adult animals in Cedar Valley. The number of adult bear in Oakridge Riverside equals the number of adult wolf in Maple Creek. The number of adult wolf in Oakridge Riverside equals 4. The number of adult wolf in Cedar Valley equals 4. The number of adult fox in Cedar Valley equals 4 times the difference between the number of adult deer in Maple Creek and the number of adult bear in Pine Ridge.

Question: How many adult fox does Cedar Valley have?

Solution: Define adult wolf in Pine Ridge as X; so X = 4. Define adult fox in Pine Ridge as u; C = X = 4; so u = 2 * C = 2 * 4 = 8. Define adult deer in Pine Ridge as F; so F = X = 4. Define adult bear in Pine Ridge as x; so x = u = 8. Define total number of adult animals in Pine Ridge as A; r = X + x = 4 + 8 = 12; T = r + u = 12 + 8 = 20; so A = T + F = 20 + 4 = 24. Define adult deer in Maple Creek as m; L = A + u = 24 + 8 = 32; so m = L + F = 32 + 4 = 36. Define adult fox in Cedar Valley as H; a = m - x = 36 - 8 = 28; so H = 4 * a = 4 * 28 = 112. Answer: 112.


The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 4 plus the number of futuristic sci-fi movie in Rêves de Belleville. The number of upbeat metropolis comedy in Cinéma de Montreval equals 3. The number of futuristic sci-fi movie in Rêves de Belleville equals 4 times the number of solemn period drama in Rêves de Belleville. The number of upbeat metropolis comedy in Rêves de Belleville equals 3 plus the number of futuristic sci-fi movie in Rêves de Belleville. The number of futuristic sci-fi movie in Cinéma de Montreval equals the total number of movies in Rêves de Belleville. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 4 plus the number of solemn period drama in Festival Lumière de Valmont. The number of solemn period drama in Rêves de Belleville equals 2. The number of solemn period drama in Festival Lumière de Valmont equals 4. The number of solemn period drama in Cinéma de Montreval equals 4 times the number of futuristic sci-fi movie in Cinéma de Montreval.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define solemn period drama in Rêves de Belleville as K; so K = 2. Define futuristic sci-fi movie in Rêves de Belleville as W; H = K = 2; so W = 4 * H = 4 * 2 = 8. Define upbeat metropolis comedy in Rêves de Belleville as S; x = W = 8; so S = 3 + x = 3 + 8 = 11. Define total number of movies in Rêves de Belleville as d; i = W + K = 8 + 2 = 10; so d = i + S = 10 + 11 = 21. Define futuristic sci-fi movie in Cinéma de Montreval as v; so v = d = 21. Define solemn period drama in Cinéma de Montreval as M; O = v = 21; so M = 4 * O = 4 * 21 = 84. Define upbeat metropolis comedy in Cinéma de Montreval as E; so E = 3. Define total number of movies in Cinéma de Montreval as w; T = M + v = 84 + 21 = 105; so w = T + E = 105 + 3 = 108. Answer: 108.