The number of public highschool in Oakbridge City equals 1 plus the number of elementary school in Oakbridge City. The number of public highschool in Ruby Bay equals 3 times the sum of the number of elementary school in Shoreline City and the number of regional medical school in Ruby Bay. The number of elementary school in Clearwater Bay equals the number of regional medical school in Shoreline City. The number of elementary school in Shoreline City equals 2. The number of regional medical school in Ruby Bay equals 4 plus the number of elementary school in Shoreline City. The number of regional medical school in Riverton City equals 1 plus the number of regional medical school in Ruby Bay. The number of elementary school in Oakbridge City equals the total number of schools in Clearwater Bay. The number of regional medical school in Clearwater Bay equals 2 times the number of regional medical school in Shoreline City. The number of regional medical school in Oakbridge City equals the number of elementary school in Oakbridge City. The number of elementary school in Ruby Bay equals the number of regional medical school in Riverton City. The number of regional medical school in Shoreline City equals 4. The number of public highschool in Clearwater Bay equals the number of regional medical school in Shoreline City. The number of public highschool in Riverton City equals the difference between the number of elementary school in Ruby Bay and the number of elementary school in Oakbridge City. The number of public highschool in Shoreline City equals 3.

Question: What is the total number of schools in Oakbridge City?

Solution: Define regional medical school in Shoreline City as x; so x = 4. Define elementary school in Clearwater Bay as O; so O = x = 4. Define regional medical school in Clearwater Bay as A; h = x = 4; so A = 2 * h = 2 * 4 = 8. Define public highschool in Clearwater Bay as C; so C = x = 4. Define total number of schools in Clearwater Bay as E; v = A + O = 8 + 4 = 12; so E = v + C = 12 + 4 = 16. Define elementary school in Oakbridge City as s; so s = E = 16. Define regional medical school in Oakbridge City as N; so N = s = 16. Define public highschool in Oakbridge City as W; b = s = 16; so W = 1 + b = 1 + 16 = 17. Define total number of schools in Oakbridge City as P; J = N + s = 16 + 16 = 32; so P = J + W = 32 + 17 = 49. Answer: 49.


The number of intense detective thriller in Verdi Movie Festival exists, and its number is greater than 0. The total number of movies in Northwood Movie Festival equals 42. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 1. The number of solemn period drama in Verdi Movie Festival equals 2 plus the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals the total number of movies in Verdi Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals the total number of movies in Verdi Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals the total number of movies in Verdi Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 3. The number of solemn period drama in Northwood Movie Festival equals the sum of the total number of movies in Verdi Movie Festival, the number of solemn period drama in Verdi Movie Festival, and the number of upbeat metropolis comedy in Verdi Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 1 plus the number of intense detective thriller in West Sahara Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 2.

Question: How many intense detective thriller does Verdi Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Verdi Movie Festival as F; so F = 3. Define solemn period drama in Verdi Movie Festival as V; n = F = 3; so V = 2 + n = 2 + 3 = 5. Define intense detective thriller in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Verdi Movie Festival as W; so W = V = 5. Define total number of movies in Verdi Movie Festival as q; v = x + W = x + 5 = x + 5; h = v + V = x + 5 + 5 = x + 10; so q = h + F = x + 10 + 3 = x + 13. Define solemn period drama in Northwood Movie Festival as r; e = q + V = x + 13 + 5 = x + 18; so r = e + W = x + 18 + 5 = x + 23. Define upbeat metropolis comedy in Northwood Movie Festival as K; so K = q = x + 13. Define total number of movies in Northwood Movie Festival as M; so M = r + K = x + 23 + x + 13 = 2*x + 36. We know M = 42, so we have 2*x + 36 = 42 and we solve it through the following steps: Simplifying the equation: 2*x + 36 = 42. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of regional medical school in Ruby Bay equals 3 plus the number of private middle school in Ruby Bay. The number of private middle school in Riverton City equals the number of regional medical school in Riverton City. The number of private middle school in Ruby Bay equals 4. The number of private middle school in Shoreline City equals 1. The number of regional medical school in Riverton City equals 2 times the total number of schools in Ruby Bay. The number of regional medical school in Shoreline City equals the difference between the total number of schools in Riverton City and the number of regional medical school in Riverton City.

Question: What is the total number of schools in Shoreline City?

Solution: Define private middle school in Ruby Bay as c; so c = 4. Define regional medical school in Ruby Bay as W; T = c = 4; so W = 3 + T = 3 + 4 = 7. Define total number of schools in Ruby Bay as N; so N = c + W = 4 + 7 = 11. Define regional medical school in Riverton City as y; l = N = 11; so y = 2 * l = 2 * 11 = 22. Define private middle school in Riverton City as Z; so Z = y = 22. Define total number of schools in Riverton City as g; so g = Z + y = 22 + 22 = 44. Define regional medical school in Shoreline City as P; so P = g - y = 44 - 22 = 22. Define private middle school in Shoreline City as G; so G = 1. Define total number of schools in Shoreline City as K; so K = G + P = 1 + 22 = 23. Answer: 23.


The number of intense detective thriller in Rêves de Belleville equals the total number of movies in Festival de Saint-Rivage. The number of calm road movie in Rêves de Belleville equals the number of upbeat metropolis comedy in Cinéma de Montreval. The number of upbeat metropolis comedy in Cinéma de Montreval equals 2. The number of solemn period drama in Rêves de Belleville equals the number of intense detective thriller in Rêves de Belleville. The number of upbeat metropolis comedy in Festival de Clairmont equals 1 plus the difference between the total number of movies in Cinéma de Montreval and the number of upbeat metropolis comedy in Cinéma de Montreval. The number of solemn period drama in Festival de Saint-Rivage equals 2 times the total number of movies in Festival de Clairmont.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define upbeat metropolis comedy in Cinéma de Montreval as H; so H = 2. Define total number of movies in Cinéma de Montreval as Y; so Y = H = 2. Define upbeat metropolis comedy in Festival de Clairmont as k; l = Y - H = 2 - 2 = 0; so k = 1 + l = 1 + 0 = 1. Define total number of movies in Festival de Clairmont as V; so V = k = 1. Define solemn period drama in Festival de Saint-Rivage as i; t = V = 1; so i = 2 * t = 2 * 1 = 2. Define total number of movies in Festival de Saint-Rivage as m; so m = i = 2. Define intense detective thriller in Rêves de Belleville as x; so x = m = 2. Define solemn period drama in Rêves de Belleville as X; so X = x = 2. Define calm road movie in Rêves de Belleville as u; so u = H = 2. Define total number of movies in Rêves de Belleville as o; N = X + x = 2 + 2 = 4; so o = N + u = 4 + 2 = 6. Answer: 6.


The number of adult fox in Beverly Forest equals 4 times the total number of adult animals in Maple Creek. The number of adult wolf in Maple Creek equals 2 times the sum of the number of adult racoon in Maple Creek and the number of adult fox in Maple Creek. The number of adult racoon in Cedar Valley equals 3 times the total number of adult animals in Beverly Forest. The number of adult fox in Maple Creek equals 4. The number of adult racoon in Maple Creek equals 2 times the number of adult fox in Maple Creek.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult fox in Maple Creek as m; so m = 4. Define adult racoon in Maple Creek as P; b = m = 4; so P = 2 * b = 2 * 4 = 8. Define adult wolf in Maple Creek as G; j = P + m = 8 + 4 = 12; so G = 2 * j = 2 * 12 = 24. Define total number of adult animals in Maple Creek as Y; D = m + P = 4 + 8 = 12; so Y = D + G = 12 + 24 = 36. Define adult fox in Beverly Forest as y; H = Y = 36; so y = 4 * H = 4 * 36 = 144. Define total number of adult animals in Beverly Forest as E; so E = y = 144. Define adult racoon in Cedar Valley as p; e = E = 144; so p = 3 * e = 3 * 144 = 432. Define total number of adult animals in Cedar Valley as T; so T = p = 432. Answer: 432.


The number of regional medical school in Brightford equals the number of culinarian school in Brightford. The number of culinarian school in Hawkesbury equals the number of regional medical school in Hawkesbury. The total number of schools in Brightford equals 56. The number of regional medical school in Hawkesbury equals 2 times the sum of the number of private middle school in Evervale City and the number of regional medical school in Evervale City. The number of culinarian school in Evervale City equals 2 plus the number of private middle school in Hawkesbury. The number of private middle school in Hawkesbury equals 2 plus the number of culinarian school in Hawkesbury. The number of private middle school in Evervale City equals 2 times the number of regional medical school in Evervale City. The number of regional medical school in Evervale City exists, and its number is greater than 0. The number of culinarian school in Brightford equals the number of culinarian school in Evervale City.

Question: How many regional medical school does Evervale City have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Evervale City as x; we don't know its value yet but will find it out later. Define private middle school in Evervale City as k; M = x = x; so k = 2 * M = (2) * (x) = 2*x. Define regional medical school in Hawkesbury as O; z = k + x = 2*x + x = 3*x; so O = 2 * z = (2) * (3*x) = 6*x. Define culinarian school in Hawkesbury as g; so g = O = 6*x. Define private middle school in Hawkesbury as q; G = g = 6*x; so q = 2 + G = 2 + 6*x = 6*x + 2. Define culinarian school in Evervale City as B; i = q = 6*x + 2; so B = 2 + i = 2 + 6*x + 2 = 6*x + 4. Define culinarian school in Brightford as n; so n = B = 6*x + 4. Define regional medical school in Brightford as w; so w = n = 6*x + 4. Define total number of schools in Brightford as y; so y = w + n = 6*x + 4 + 6*x + 4 = 12*x + 8. We know y = 56, so we have 12*x + 8 = 56 and we solve it through the following steps: Simplifying the equation: 12*x + 8 = 56. Move all terms to one side: 12*x - 48 = 0. Isolate the term with x: 12*x = 48. Divide both sides by 12: x = 48 / 12. Solution: x = 4. Answer: 4.


The number of intense detective thriller in Taylor Movie Festival equals 1. The number of calm road movie in Verdi Movie Festival equals the sum of the total number of movies in Taylor Movie Festival, the number of solemn period drama in Taylor Movie Festival, and the number of intense detective thriller in Northwood Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 3. The number of solemn period drama in Taylor Movie Festival equals the sum of the total number of movies in Northwood Movie Festival, the number of intense detective thriller in Taylor Movie Festival, and the number of solemn period drama in Northwood Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 4 plus the number of solemn period drama in Northwood Movie Festival.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define intense detective thriller in Taylor Movie Festival as k; so k = 1. Define solemn period drama in Northwood Movie Festival as T; so T = 3. Define intense detective thriller in Northwood Movie Festival as a; o = T = 3; so a = 4 + o = 4 + 3 = 7. Define total number of movies in Northwood Movie Festival as Z; so Z = a + T = 7 + 3 = 10. Define solemn period drama in Taylor Movie Festival as G; H = Z + k = 10 + 1 = 11; so G = H + T = 11 + 3 = 14. Define total number of movies in Taylor Movie Festival as n; so n = k + G = 1 + 14 = 15. Define calm road movie in Verdi Movie Festival as V; r = n + G = 15 + 14 = 29; so V = r + a = 29 + 7 = 36. Define total number of movies in Verdi Movie Festival as N; so N = V = 36. Answer: 36.


The number of adult crow in Maple Creek equals the sum of the total number of adult animals in Cedar Valley, the number of adult owl in Cedar Valley, and the number of adult crow in Oakridge Riverside. The number of adult parrot in Oakridge Riverside equals 4. The number of adult owl in Maple Creek equals 2 plus the total number of adult animals in Oakridge Riverside. The number of adult parrot in Cedar Valley equals the number of adult owl in Maple Creek. The number of adult owl in Cedar Valley equals 4. The number of adult crow in Oakridge Riverside equals 2.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult crow in Oakridge Riverside as i; so i = 2. Define adult parrot in Oakridge Riverside as v; so v = 4. Define total number of adult animals in Oakridge Riverside as W; so W = v + i = 4 + 2 = 6. Define adult owl in Maple Creek as n; k = W = 6; so n = 2 + k = 2 + 6 = 8. Define adult parrot in Cedar Valley as U; so U = n = 8. Define adult owl in Cedar Valley as F; so F = 4. Define total number of adult animals in Cedar Valley as R; so R = U + F = 8 + 4 = 12. Define adult crow in Maple Creek as X; H = R + F = 12 + 4 = 16; so X = H + i = 16 + 2 = 18. Define total number of adult animals in Maple Creek as o; so o = n + X = 8 + 18 = 26. Answer: 26.


The number of solemn period drama in West Sahara Movie Festival equals 2 times the difference between the number of calm road movie in Golden Banana Movie Festival and the number of solemn period drama in Golden Banana Movie Festival. The total number of movies in Taylor Movie Festival equals 184. The number of solemn period drama in Taylor Movie Festival equals 3 times the sum of the total number of movies in West Sahara Movie Festival and the number of calm road movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals the sum of the number of solemn period drama in Taylor Movie Festival, the number of calm road movie in Golden Banana Movie Festival, and the number of solemn period drama in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 3 times the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival exists, and its number is greater than 0.

Question: How many solemn period drama does Golden Banana Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define calm road movie in Golden Banana Movie Festival as d; t = x = x; so d = 3 * t = (3) * (x) = 3*x. Define solemn period drama in West Sahara Movie Festival as a; p = d - x = (3*x) - (x) = 2*x; so a = 2 * p = (2) * (2*x) = 4*x. Define total number of movies in West Sahara Movie Festival as J; so J = a = 4*x. Define solemn period drama in Taylor Movie Festival as D; A = J + d = 4*x + 3*x = 7*x; so D = 3 * A = (3) * (7*x) = 21*x. Define futuristic sci-fi movie in Taylor Movie Festival as s; R = D + d = 21*x + 3*x = 24*x; so s = R + x = 24*x + x = 25*x. Define total number of movies in Taylor Movie Festival as e; so e = D + s = 21*x + 25*x = 46*x. We know e = 184, so we have 46*x = 184 and we solve it through the following steps: Simplifying the equation: 46*x = 184. Move all terms to one side: 46*x - 184 = 0. Isolate the term with x: 46*x = 184. Divide both sides by 46: x = 184 / 46. Solution: x = 4. Answer: 4.


The total number of adult animals in Hamilton Farm equals 10. The number of adult fox in Hamilton Farm equals 4 plus the difference between the number of adult bear in Jefferson Circus and the number of adult fox in Bundle Ranch. The number of adult bear in Bundle Ranch equals 3 plus the number of adult fox in Bundle Ranch. The number of adult bear in Jefferson Circus exists, and its number is greater than 0. The number of adult racoon in Jefferson Circus equals 1. The number of adult fox in Bundle Ranch equals 3 times the number of adult racoon in Jefferson Circus. The number of adult bear in Hamilton Farm equals the difference between the total number of adult animals in Bundle Ranch and the number of adult fox in Bundle Ranch.

Question: How many adult bear does Jefferson Circus have?

Solution: The question is difficult, so we use equations to solve it. Define adult racoon in Jefferson Circus as I; so I = 1. Define adult fox in Bundle Ranch as T; h = I = 1; so T = 3 * h = (3) * (1) = 3. Define adult bear in Bundle Ranch as W; M = T = 3; so W = 3 + M = 3 + 3 = 6. Define total number of adult animals in Bundle Ranch as o; so o = T + W = 3 + 6 = 9. Define adult bear in Hamilton Farm as P; so P = o - T = (9) - (3) = 6. Define adult bear in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult fox in Hamilton Farm as p; Y = x - T = (x) - (3) = x - 3; so p = 4 + Y = 4 + x - 3 = x + 1. Define total number of adult animals in Hamilton Farm as J; so J = p + P = x + 1 + 6 = x + 7. We know J = 10, so we have x + 7 = 10 and we solve it through the following steps: Simplifying the equation: x + 7 = 10. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of adult blue jay in Pine Ridge equals 3 plus the total number of adult animals in Cedar Valley. The number of adult crow in Oakridge Riverside equals 2. The number of adult blue jay in Cedar Valley equals the number of adult crow in Oakridge Riverside. The number of adult owl in Cedar Valley equals 3 times the total number of adult animals in Oakridge Riverside. The number of adult parrot in Pine Ridge equals the number of adult blue jay in Pine Ridge. The number of adult parrot in Beverly Forest equals 1 plus the total number of adult animals in Pine Ridge.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult crow in Oakridge Riverside as D; so D = 2. Define total number of adult animals in Oakridge Riverside as x; so x = D = 2. Define adult owl in Cedar Valley as s; Y = x = 2; so s = 3 * Y = 3 * 2 = 6. Define adult blue jay in Cedar Valley as Z; so Z = D = 2. Define total number of adult animals in Cedar Valley as H; so H = Z + s = 2 + 6 = 8. Define adult blue jay in Pine Ridge as b; m = H = 8; so b = 3 + m = 3 + 8 = 11. Define adult parrot in Pine Ridge as g; so g = b = 11. Define total number of adult animals in Pine Ridge as f; so f = b + g = 11 + 11 = 22. Define adult parrot in Beverly Forest as J; w = f = 22; so J = 1 + w = 1 + 22 = 23. Define total number of adult animals in Beverly Forest as S; so S = J = 23. Answer: 23.


The number of calm road movie in Cinéma de Montreval equals the sum of the total number of movies in Festival de Clairmont and the number of solemn period drama in Festival Lumière de Valmont. The number of solemn period drama in Festival Lumière de Valmont equals 1. The number of intense detective thriller in Festival Lumière de Valmont equals the number of calm road movie in Festival Lumière de Valmont. The number of intense detective thriller in Cinéma de Montreval equals 2 times the number of calm road movie in Cinéma de Montreval. The number of intense detective thriller in Festival de Clairmont equals 2 times the total number of movies in Festival Lumière de Valmont. The number of calm road movie in Festival Lumière de Valmont equals 3.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define solemn period drama in Festival Lumière de Valmont as h; so h = 1. Define calm road movie in Festival Lumière de Valmont as e; so e = 3. Define intense detective thriller in Festival Lumière de Valmont as Z; so Z = e = 3. Define total number of movies in Festival Lumière de Valmont as G; U = Z + h = 3 + 1 = 4; so G = U + e = 4 + 3 = 7. Define intense detective thriller in Festival de Clairmont as K; A = G = 7; so K = 2 * A = 2 * 7 = 14. Define total number of movies in Festival de Clairmont as D; so D = K = 14. Define calm road movie in Cinéma de Montreval as x; so x = D + h = 14 + 1 = 15. Define intense detective thriller in Cinéma de Montreval as J; j = x = 15; so J = 2 * j = 2 * 15 = 30. Define total number of movies in Cinéma de Montreval as u; so u = J + x = 30 + 15 = 45. Answer: 45.


The number of calm road movie in Cinéma de Montreval equals 3 plus the total number of movies in Rêves de Belleville. The number of futuristic sci-fi movie in Rêves de Belleville equals 3 times the number of intense detective thriller in Rêves de Belleville. The number of intense detective thriller in Rêves de Belleville equals 4. The number of solemn period drama in Festival Lumière de Valmont equals 3 times the total number of movies in Cinéma de Montreval. The number of calm road movie in Festival de Saint-Rivage equals the sum of the total number of movies in Festival Lumière de Valmont, the number of intense detective thriller in Rêves de Belleville, and the number of futuristic sci-fi movie in Rêves de Belleville.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define intense detective thriller in Rêves de Belleville as n; so n = 4. Define futuristic sci-fi movie in Rêves de Belleville as I; e = n = 4; so I = 3 * e = 3 * 4 = 12. Define total number of movies in Rêves de Belleville as T; so T = I + n = 12 + 4 = 16. Define calm road movie in Cinéma de Montreval as s; q = T = 16; so s = 3 + q = 3 + 16 = 19. Define total number of movies in Cinéma de Montreval as H; so H = s = 19. Define solemn period drama in Festival Lumière de Valmont as E; b = H = 19; so E = 3 * b = 3 * 19 = 57. Define total number of movies in Festival Lumière de Valmont as x; so x = E = 57. Define calm road movie in Festival de Saint-Rivage as Y; M = x + n = 57 + 4 = 61; so Y = M + I = 61 + 12 = 73. Define total number of movies in Festival de Saint-Rivage as h; so h = Y = 73. Answer: 73.


The number of private middle school in Westhaven City equals the total number of schools in Evervale City. The number of culinarian school in Glenfield City equals 4 times the number of regional medical school in Glenfield City. The number of regional medical school in Glenfield City equals 2. The number of public highschool in Brightford equals the sum of the total number of schools in Glenfield City and the number of culinarian school in Glenfield City. The number of private middle school in Evervale City equals 4 plus the total number of schools in Brightford. The number of public highschool in Glenfield City equals 3.

Question: What is the total number of schools in Westhaven City?

Solution: Define public highschool in Glenfield City as G; so G = 3. Define regional medical school in Glenfield City as B; so B = 2. Define culinarian school in Glenfield City as I; W = B = 2; so I = 4 * W = 4 * 2 = 8. Define total number of schools in Glenfield City as J; D = I + G = 8 + 3 = 11; so J = D + B = 11 + 2 = 13. Define public highschool in Brightford as k; so k = J + I = 13 + 8 = 21. Define total number of schools in Brightford as m; so m = k = 21. Define private middle school in Evervale City as w; d = m = 21; so w = 4 + d = 4 + 21 = 25. Define total number of schools in Evervale City as v; so v = w = 25. Define private middle school in Westhaven City as R; so R = v = 25. Define total number of schools in Westhaven City as Q; so Q = R = 25. Answer: 25.


The number of futuristic sci-fi movie in Rêves de Belleville equals 2. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2 times the difference between the total number of movies in Rêves de Belleville and the number of futuristic sci-fi movie in Rêves de Belleville. The number of upbeat metropolis comedy in Festival de Clairmont exists, and its number is greater than 0. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 4 times the sum of the total number of movies in Festival de Clairmont and the total number of movies in Rêves de Belleville. The total number of movies in Festival de Saint-Rivage equals 56. The number of upbeat metropolis comedy in Rêves de Belleville equals 3 times the number of futuristic sci-fi movie in Rêves de Belleville.

Question: How many upbeat metropolis comedy does Festival de Clairmont have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Rêves de Belleville as c; so c = 2. Define upbeat metropolis comedy in Rêves de Belleville as C; g = c = 2; so C = 3 * g = (3) * (2) = 6. Define total number of movies in Rêves de Belleville as H; so H = C + c = 6 + 2 = 8. Define upbeat metropolis comedy in Festival de Saint-Rivage as K; f = H - c = (8) - (2) = 6; so K = 2 * f = (2) * (6) = 12. Define upbeat metropolis comedy in Festival de Clairmont as x; we don't know its value yet but will find it out later. Define total number of movies in Festival de Clairmont as m; so m = x = x. Define futuristic sci-fi movie in Festival de Saint-Rivage as j; T = m + H = x + 8 = x + 8; so j = 4 * T = (4) * (x + 8) = 4*x + 32. Define total number of movies in Festival de Saint-Rivage as i; so i = K + j = 12 + 4*x + 32 = 4*x + 44. We know i = 56, so we have 4*x + 44 = 56 and we solve it through the following steps: Simplifying the equation: 4*x + 44 = 56. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.


The number of adult racoon in Maple Creek equals 3 plus the number of adult wolf in Pine Ridge. The number of adult racoon in Oakridge Riverside equals the sum of the number of adult deer in Cedar Valley, the number of adult deer in Beverly Forest, and the total number of adult animals in Pine Ridge. The number of adult bear in Beverly Forest equals 2 times the number of adult deer in Beverly Forest. The number of adult racoon in Beverly Forest equals 3. The number of adult wolf in Cedar Valley equals 4 times the number of adult deer in Beverly Forest. The number of adult deer in Beverly Forest equals 4. The number of adult wolf in Oakridge Riverside equals the total number of adult animals in Cedar Valley. The number of adult deer in Oakridge Riverside equals 3. The number of adult fox in Cedar Valley equals the difference between the total number of adult animals in Beverly Forest and the number of adult racoon in Beverly Forest. The number of adult deer in Cedar Valley equals the number of adult deer in Beverly Forest. The number of adult wolf in Maple Creek equals 1 plus the sum of the number of adult wolf in Pine Ridge, the number of adult racoon in Maple Creek, and the number of adult deer in Oakridge Riverside. The number of adult fox in Pine Ridge equals 4. The number of adult wolf in Pine Ridge equals 2.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult deer in Beverly Forest as z; so z = 4. Define adult deer in Cedar Valley as w; so w = z = 4. Define adult bear in Beverly Forest as R; r = z = 4; so R = 2 * r = 2 * 4 = 8. Define adult racoon in Beverly Forest as E; so E = 3. Define total number of adult animals in Beverly Forest as b; n = z + R = 4 + 8 = 12; so b = n + E = 12 + 3 = 15. Define adult fox in Cedar Valley as V; so V = b - E = 15 - 3 = 12. Define adult wolf in Cedar Valley as A; i = z = 4; so A = 4 * i = 4 * 4 = 16. Define total number of adult animals in Cedar Valley as x; s = w + A = 4 + 16 = 20; so x = s + V = 20 + 12 = 32. Answer: 32.


The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the total number of movies in Festival de Clairmont. The number of intense detective thriller in Festival de Clairmont equals 4. The number of futuristic sci-fi movie in Cinéma de Montreval equals 3 plus the difference between the total number of movies in Festival de Clairmont and the number of calm road movie in Festival de Clairmont. The number of calm road movie in Cinéma de Montreval exists, and its number is greater than 0. The number of calm road movie in Cinéma de Montreval exists, and its number is greater than 0. The number of upbeat metropolis comedy in Festival de Clairmont equals 2 plus the number of intense detective thriller in Festival de Clairmont. The number of calm road movie in Festival de Clairmont equals 3 times the sum of the number of upbeat metropolis comedy in Festival de Clairmont and the number of intense detective thriller in Festival de Clairmont. The number of intense detective thriller in Festival de Saint-Rivage equals 2. The total number of movies in Cinéma de Montreval equals 15.

Question: How many calm road movie does Cinéma de Montreval have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Festival de Clairmont as z; so z = 4. Define upbeat metropolis comedy in Festival de Clairmont as u; Y = z = 4; so u = 2 + Y = 2 + 4 = 6. Define calm road movie in Festival de Clairmont as Z; D = u + z = 6 + 4 = 10; so Z = 3 * D = (3) * (10) = 30. Define total number of movies in Festival de Clairmont as o; B = Z + u = 30 + 6 = 36; so o = B + z = 36 + 4 = 40. Define futuristic sci-fi movie in Cinéma de Montreval as i; M = o - Z = (40) - (30) = 10; so i = 3 + M = 3 + 10 = 13. Define calm road movie in Cinéma de Montreval as x; we don't know its value yet but will find it out later. Define total number of movies in Cinéma de Montreval as R; so R = x + i = x + 13 = x + 13. We know R = 15, so we have x + 13 = 15 and we solve it through the following steps: Simplifying the equation: x + 13 = 15. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of culinarian school in Riverton City equals 3. The number of culinarian school in Oakbridge City equals the number of elementary school in Riverton City. The number of regional medical school in Riverton City equals 3 times the number of culinarian school in Riverton City. The number of elementary school in Riverton City equals 1 plus the number of regional medical school in Riverton City. The number of elementary school in Oakbridge City equals 4. The number of regional medical school in Oakbridge City equals the difference between the total number of schools in Riverton City and the number of regional medical school in Riverton City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define culinarian school in Riverton City as K; so K = 3. Define regional medical school in Riverton City as z; u = K = 3; so z = 3 * u = 3 * 3 = 9. Define elementary school in Riverton City as r; g = z = 9; so r = 1 + g = 1 + 9 = 10. Define total number of schools in Riverton City as e; n = z + r = 9 + 10 = 19; so e = n + K = 19 + 3 = 22. Define regional medical school in Oakbridge City as C; so C = e - z = 22 - 9 = 13. Define elementary school in Oakbridge City as G; so G = 4. Define culinarian school in Oakbridge City as o; so o = r = 10. Define total number of schools in Oakbridge City as b; c = o + G = 10 + 4 = 14; so b = c + C = 14 + 13 = 27. Answer: 27.


The number of regional medical school in Ruby Bay equals 4. The number of regional medical school in Shoreline City equals 3. The number of elementary school in Clearwater Bay equals 4. The number of private middle school in Shoreline City equals 3 plus the number of public highschool in Riverton City. The number of regional medical school in Clearwater Bay equals the number of private middle school in Shoreline City. The number of elementary school in Ruby Bay equals the sum of the total number of schools in Clearwater Bay, the number of private middle school in Shoreline City, and the number of public highschool in Riverton City. The number of public highschool in Riverton City equals 3. The number of public highschool in Ruby Bay equals 3. The number of regional medical school in Riverton City equals 2.

Question: What is the total number of schools in Ruby Bay?

Solution: Define public highschool in Riverton City as E; so E = 3. Define private middle school in Shoreline City as N; j = E = 3; so N = 3 + j = 3 + 3 = 6. Define elementary school in Clearwater Bay as r; so r = 4. Define regional medical school in Clearwater Bay as O; so O = N = 6. Define total number of schools in Clearwater Bay as l; so l = O + r = 6 + 4 = 10. Define elementary school in Ruby Bay as z; v = l + N = 10 + 6 = 16; so z = v + E = 16 + 3 = 19. Define public highschool in Ruby Bay as H; so H = 3. Define regional medical school in Ruby Bay as c; so c = 4. Define total number of schools in Ruby Bay as f; b = H + c = 3 + 4 = 7; so f = b + z = 7 + 19 = 26. Answer: 26.


The number of adult eagle in Mayer Aquarium equals 2. The number of adult crow in Mayer Aquarium equals 2. The number of adult owl in Mayer Aquarium equals 1 plus the sum of the number of adult crow in Mayer Aquarium and the number of adult eagle in Mayer Aquarium. The number of adult crow in Hamilton Farm equals the sum of the total number of adult animals in Mayer Aquarium, the number of adult owl in Mayer Aquarium, and the number of adult eagle in Mayer Aquarium. The number of adult eagle in Bundle Ranch equals 4 plus the total number of adult animals in Hamilton Farm.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult crow in Mayer Aquarium as J; so J = 2. Define adult eagle in Mayer Aquarium as P; so P = 2. Define adult owl in Mayer Aquarium as p; W = J + P = 2 + 2 = 4; so p = 1 + W = 1 + 4 = 5. Define total number of adult animals in Mayer Aquarium as H; s = J + P = 2 + 2 = 4; so H = s + p = 4 + 5 = 9. Define adult crow in Hamilton Farm as X; g = H + p = 9 + 5 = 14; so X = g + P = 14 + 2 = 16. Define total number of adult animals in Hamilton Farm as N; so N = X = 16. Define adult eagle in Bundle Ranch as A; z = N = 16; so A = 4 + z = 4 + 16 = 20. Define total number of adult animals in Bundle Ranch as Z; so Z = A = 20. Answer: 20.


The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals the sum of the total number of movies in Golden Banana Movie Festival and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 3. The number of solemn period drama in Golden Banana Movie Festival equals 3 times the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of calm road movie in Verdi Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 4 times the number of upbeat metropolis comedy in Verdi Movie Festival.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define intense detective thriller in Golden Banana Movie Festival as s; so s = 3. Define upbeat metropolis comedy in Golden Banana Movie Festival as K; so K = s = 3. Define solemn period drama in Golden Banana Movie Festival as E; m = K = 3; so E = 3 * m = 3 * 3 = 9. Define total number of movies in Golden Banana Movie Festival as f; u = E + K = 9 + 3 = 12; so f = u + s = 12 + 3 = 15. Define upbeat metropolis comedy in Verdi Movie Festival as r; so r = f + K = 15 + 3 = 18. Define calm road movie in Verdi Movie Festival as R; so R = K = 3. Define intense detective thriller in Verdi Movie Festival as z; N = r = 18; so z = 4 * N = 4 * 18 = 72. Define total number of movies in Verdi Movie Festival as I; W = R + r = 3 + 18 = 21; so I = W + z = 21 + 72 = 93. Answer: 93.


The number of adult deer in South Zoo equals the number of adult fox in Hamilton Farm. The number of adult fox in Hamilton Farm equals 4. The number of adult fox in South Zoo equals 4 times the total number of adult animals in Hamilton Farm. The number of adult bear in South Zoo exists, and its number is greater than 0. The number of adult fox in Mayer Aquarium equals the sum of the number of adult fox in Jefferson Circus, the total number of adult animals in Hamilton Farm, the number of adult fox in Hamilton Farm, and the number of adult bear in Mayer Aquarium. The number of adult bear in Hamilton Farm equals 1. The number of adult fox in Jefferson Circus equals 4. The number of adult deer in Jefferson Circus equals 2 plus the sum of the number of adult deer in Hamilton Farm and the total number of adult animals in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals the sum of the number of adult bear in Hamilton Farm and the number of adult bear in South Zoo. The number of adult racoon in South Zoo equals the number of adult bear in Hamilton Farm. The number of adult deer in Hamilton Farm equals 3. The total number of adult animals in South Zoo equals 40. The number of adult bear in Mayer Aquarium equals 3 times the sum of the number of adult bear in Hamilton Farm and the total number of adult animals in Hamilton Farm.

Question: How many adult bear does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Hamilton Farm as D; so D = 1. Define adult deer in Hamilton Farm as E; so E = 3. Define adult fox in Hamilton Farm as K; so K = 4. Define total number of adult animals in Hamilton Farm as f; y = K + D = 4 + 1 = 5; so f = y + E = 5 + 3 = 8. Define adult fox in South Zoo as F; Z = f = 8; so F = 4 * Z = (4) * (8) = 32. Define adult deer in South Zoo as t; so t = K = 4. Define adult racoon in South Zoo as c; so c = D = 1. Define adult bear in South Zoo as x; we don't know its value yet but will find it out later. Define total number of adult animals in South Zoo as q; k = F + c = 32 + 1 = 33; G = k + x = 33 + x = x + 33; so q = G + t = x + 33 + 4 = x + 37. We know q = 40, so we have x + 37 = 40 and we solve it through the following steps: Simplifying the equation: x + 37 = 40. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of adult owl in Pine Ridge equals 2 times the number of adult eagle in Oakridge Riverside. The number of adult blue jay in Cedar Valley equals 3. The number of adult eagle in Oakridge Riverside equals 3. The number of adult blue jay in Oakridge Riverside equals 2. The number of adult blue jay in Pine Ridge equals the number of adult owl in Pine Ridge. The total number of adult animals in Pine Ridge equals 39. The number of adult eagle in Cedar Valley equals 2. The number of adult owl in Cedar Valley equals 3. The number of adult owl in Oakridge Riverside exists, and its number is greater than 0. The number of adult eagle in Pine Ridge equals 3 times the sum of the total number of adult animals in Oakridge Riverside and the number of adult blue jay in Oakridge Riverside.

Question: How many adult owl does Oakridge Riverside have?

Solution: The question is difficult, so we use equations to solve it. Define adult eagle in Oakridge Riverside as N; so N = 3. Define adult blue jay in Oakridge Riverside as M; so M = 2. Define adult owl in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define total number of adult animals in Oakridge Riverside as z; i = N + x = 3 + x = x + 3; so z = i + M = x + 3 + 2 = x + 5. Define adult eagle in Pine Ridge as F; Z = z + M = x + 5 + 2 = x + 7; so F = 3 * Z = (3) * (x + 7) = 3*x + 21. Define adult owl in Pine Ridge as K; r = N = 3; so K = 2 * r = (2) * (3) = 6. Define adult blue jay in Pine Ridge as E; so E = K = 6. Define total number of adult animals in Pine Ridge as e; v = F + K = 3*x + 21 + 6 = 3*x + 27; so e = v + E = 3*x + 27 + 6 = 3*x + 33. We know e = 39, so we have 3*x + 33 = 39 and we solve it through the following steps: Simplifying the equation: 3*x + 33 = 39. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.


The number of public highschool in Brightford equals the sum of the number of public highschool in Westhaven City and the total number of schools in Hawkesbury. The number of regional medical school in Glenfield City equals 4. The number of public highschool in Westhaven City equals 3 plus the number of public highschool in Glenfield City. The number of private middle school in Brightford equals 4 times the difference between the number of public highschool in Westhaven City and the number of public highschool in Glenfield City. The number of public highschool in Glenfield City exists, and its number is greater than 0. The total number of schools in Hawkesbury equals 63. The number of public highschool in Glenfield City exists, and its number is greater than 0. The number of elementary school in Glenfield City equals 4 times the sum of the number of private middle school in Brightford, the number of public highschool in Westhaven City, and the total number of schools in Hawkesbury. The number of public highschool in Glenfield City exists, and its number is greater than 0.

Question: How many public highschool does Glenfield City have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Glenfield City as x; we don't know its value yet but will find it out later. Define public highschool in Westhaven City as d; j = x = x; so d = 3 + j = 3 + x = x + 3. Define private middle school in Brightford as K; z = d - x = (x + 3) - (x) = 3; so K = 4 * z = (4) * (3) = 12. Define elementary school in Evervale City as t; n = K + x = 12 + x = x + 12; c = n + d = x + 12 + x + 3 = 2*x + 15; so t = 2 * c = (2) * (2*x + 15) = 4*x + 30. Define culinarian school in Hawkesbury as D; G = t + K = 4*x + 30 + 12 = 4*x + 42; m = G + x = 4*x + 42 + x = 5*x + 42; so D = m + d = 5*x + 42 + x + 3 = 6*x + 45. Define total number of schools in Hawkesbury as M; so M = D = 6*x + 45. We know M = 63, so we have 6*x + 45 = 63 and we solve it through the following steps: Simplifying the equation: 6*x + 45 = 63. Move all terms to one side: 6*x - 18 = 0. Isolate the term with x: 6*x = 18. Divide both sides by 6: x = 18 / 6. Solution: x = 3. Answer: 3.


The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 4. The number of calm road movie in Rêves de Belleville equals 2 plus the total number of movies in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Rêves de Belleville equals 2 times the number of calm road movie in Rêves de Belleville. The number of calm road movie in Festival Lumière de Valmont equals the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Rêves de Belleville equals 2 times the number of calm road movie in Rêves de Belleville. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 3.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define upbeat metropolis comedy in Festival Lumière de Valmont as n; so n = 4. Define futuristic sci-fi movie in Festival Lumière de Valmont as p; so p = 3. Define calm road movie in Festival Lumière de Valmont as q; so q = p = 3. Define total number of movies in Festival Lumière de Valmont as Z; a = p + n = 3 + 4 = 7; so Z = a + q = 7 + 3 = 10. Define calm road movie in Rêves de Belleville as k; e = Z = 10; so k = 2 + e = 2 + 10 = 12. Define futuristic sci-fi movie in Rêves de Belleville as m; s = k = 12; so m = 2 * s = 2 * 12 = 24. Define upbeat metropolis comedy in Rêves de Belleville as G; c = k = 12; so G = 2 * c = 2 * 12 = 24. Define total number of movies in Rêves de Belleville as A; b = m + k = 24 + 12 = 36; so A = b + G = 36 + 24 = 60. Answer: 60.


The number of calm road movie in Golden Banana Movie Festival equals 3 times the number of calm road movie in West Sahara Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 2. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 3 times the difference between the number of upbeat metropolis comedy in Taylor Movie Festival and the number of solemn period drama in Northwood Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 2. The total number of movies in Taylor Movie Festival equals 46. The number of calm road movie in Northwood Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 plus the difference between the number of intense detective thriller in Golden Banana Movie Festival and the number of intense detective thriller in Northwood Movie Festival. The number of solemn period drama in Taylor Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Golden Banana Movie Festival equals 4 times the number of intense detective thriller in Northwood Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 3 times the sum of the number of upbeat metropolis comedy in Golden Banana Movie Festival, the total number of movies in Taylor Movie Festival, and the number of solemn period drama in Northwood Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the sum of the number of calm road movie in Northwood Movie Festival and the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in Northwood Movie Festival equals the total number of movies in Taylor Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 4 times the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 3 plus the difference between the number of calm road movie in West Sahara Movie Festival and the number of calm road movie in Golden Banana Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 2.

Question: How many solemn period drama does Taylor Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Northwood Movie Festival as f; so f = 2. Define intense detective thriller in Golden Banana Movie Festival as j; w = f = 2; so j = 4 * w = (4) * (2) = 8. Define upbeat metropolis comedy in Golden Banana Movie Festival as d; E = j - f = (8) - (2) = 6; so d = 2 + E = 2 + 6 = 8. Define solemn period drama in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define calm road movie in Northwood Movie Festival as D; so D = d = 8. Define upbeat metropolis comedy in Taylor Movie Festival as y; l = d = 8; so y = 4 * l = (4) * (8) = 32. Define intense detective thriller in Taylor Movie Festival as a; so a = D + x = 8 + x = x + 8. Define total number of movies in Taylor Movie Festival as s; P = y + x = 32 + x = x + 32; so s = P + a = x + 32 + x + 8 = 2*x + 40. We know s = 46, so we have 2*x + 40 = 46 and we solve it through the following steps: Simplifying the equation: 2*x + 40 = 46. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of public highschool in Hawkesbury exists, and its number is greater than 0. The number of private middle school in Hawkesbury equals 3 times the number of public highschool in Hawkesbury. The number of elementary school in Brightford equals 3 times the difference between the number of private middle school in Hawkesbury and the number of public highschool in Hawkesbury. The number of private middle school in Brightford equals the difference between the number of elementary school in Brightford and the number of private middle school in Hawkesbury. The number of regional medical school in Westhaven City equals the sum of the total number of schools in Brightford, the number of public highschool in Hawkesbury, the number of private middle school in Brightford, and the number of elementary school in Brightford. The total number of schools in Westhaven City equals 38.

Question: How many public highschool does Hawkesbury have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Hawkesbury as x; we don't know its value yet but will find it out later. Define private middle school in Hawkesbury as l; q = x = x; so l = 3 * q = (3) * (x) = 3*x. Define elementary school in Brightford as A; E = l - x = (3*x) - (x) = 2*x; so A = 3 * E = (3) * (2*x) = 6*x. Define private middle school in Brightford as o; so o = A - l = (6*x) - (3*x) = 3*x. Define total number of schools in Brightford as S; so S = o + A = 3*x + 6*x = 9*x. Define regional medical school in Westhaven City as d; f = S + x = 9*x + x = 10*x; Y = f + o = 10*x + 3*x = 13*x; so d = Y + A = 13*x + 6*x = 19*x. Define total number of schools in Westhaven City as u; so u = d = 19*x. We know u = 38, so we have 19*x = 38 and we solve it through the following steps: Simplifying the equation: 19*x = 38. Move all terms to one side: 19*x - 38 = 0. Isolate the term with x: 19*x = 38. Divide both sides by 19: x = 38 / 19. Solution: x = 2. Answer: 2.


The number of adult wolf in Hamilton Farm equals the number of adult wolf in South Zoo. The number of adult racoon in Hamilton Farm equals 3 plus the sum of the number of adult racoon in South Zoo, the number of adult fox in Mayer Aquarium, and the total number of adult animals in Jefferson Circus. The number of adult fox in Jefferson Circus equals 4 times the number of adult wolf in Jefferson Circus. The number of adult racoon in Jefferson Circus equals the number of adult fox in Jefferson Circus. The number of adult wolf in Mayer Aquarium equals 3 plus the total number of adult animals in Jefferson Circus. The number of adult wolf in Jefferson Circus equals 1. The number of adult wolf in South Zoo equals 2. The number of adult racoon in Mayer Aquarium equals 3 times the number of adult fox in Jefferson Circus. The number of adult fox in Hamilton Farm equals the difference between the number of adult fox in Jefferson Circus and the number of adult wolf in Mayer Aquarium. The number of adult fox in South Zoo equals the number of adult racoon in Mayer Aquarium. The number of adult fox in Mayer Aquarium equals the total number of adult animals in Jefferson Circus. The number of adult racoon in South Zoo equals 4.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult wolf in Jefferson Circus as l; so l = 1. Define adult fox in Jefferson Circus as A; W = l = 1; so A = 4 * W = 4 * 1 = 4. Define adult racoon in Jefferson Circus as K; so K = A = 4. Define total number of adult animals in Jefferson Circus as R; s = A + l = 4 + 1 = 5; so R = s + K = 5 + 4 = 9. Define adult racoon in Mayer Aquarium as c; g = A = 4; so c = 3 * g = 3 * 4 = 12. Define adult wolf in Mayer Aquarium as a; X = R = 9; so a = 3 + X = 3 + 9 = 12. Define adult fox in Mayer Aquarium as Q; so Q = R = 9. Define total number of adult animals in Mayer Aquarium as t; y = Q + a = 9 + 12 = 21; so t = y + c = 21 + 12 = 33. Answer: 33.


The number of private middle school in Westhaven City equals 3. The number of culinarian school in Westhaven City equals 3. The number of public highschool in Evervale City equals 2 times the total number of schools in Westhaven City. The number of public highschool in Brightford equals the sum of the total number of schools in Glenfield City and the total number of schools in Evervale City. The number of regional medical school in Glenfield City equals 2 plus the sum of the total number of schools in Evervale City, the number of public highschool in Evervale City, and the number of culinarian school in Westhaven City.

Question: What is the total number of schools in Brightford?

Solution: Define private middle school in Westhaven City as N; so N = 3. Define culinarian school in Westhaven City as r; so r = 3. Define total number of schools in Westhaven City as C; so C = N + r = 3 + 3 = 6. Define public highschool in Evervale City as f; M = C = 6; so f = 2 * M = 2 * 6 = 12. Define total number of schools in Evervale City as h; so h = f = 12. Define regional medical school in Glenfield City as F; G = h + f = 12 + 12 = 24; v = G + r = 24 + 3 = 27; so F = 2 + v = 2 + 27 = 29. Define total number of schools in Glenfield City as E; so E = F = 29. Define public highschool in Brightford as X; so X = E + h = 29 + 12 = 41. Define total number of schools in Brightford as i; so i = X = 41. Answer: 41.


The number of public highschool in Hawkesbury equals the sum of the total number of schools in Evervale City, the number of culinarian school in Glenfield City, and the number of public highschool in Westhaven City. The number of private middle school in Westhaven City equals 2 times the number of culinarian school in Westhaven City. The number of culinarian school in Evervale City equals 4 plus the number of public highschool in Westhaven City. The number of culinarian school in Glenfield City equals 2 times the difference between the number of private middle school in Westhaven City and the number of culinarian school in Westhaven City. The number of culinarian school in Westhaven City equals 3. The number of public highschool in Westhaven City equals the sum of the number of culinarian school in Glenfield City and the number of private middle school in Westhaven City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define culinarian school in Westhaven City as R; so R = 3. Define private middle school in Westhaven City as G; x = R = 3; so G = 2 * x = 2 * 3 = 6. Define culinarian school in Glenfield City as K; r = G - R = 6 - 3 = 3; so K = 2 * r = 2 * 3 = 6. Define public highschool in Westhaven City as E; so E = K + G = 6 + 6 = 12. Define culinarian school in Evervale City as X; J = E = 12; so X = 4 + J = 4 + 12 = 16. Define total number of schools in Evervale City as e; so e = X = 16. Define public highschool in Hawkesbury as d; q = e + K = 16 + 6 = 22; so d = q + E = 22 + 12 = 34. Define total number of schools in Hawkesbury as P; so P = d = 34. Answer: 34.


The number of adult bear in Bundle Ranch equals 2 times the number of adult racoon in Bundle Ranch. The number of adult racoon in Bundle Ranch equals 1. The number of adult racoon in Hamilton Farm equals the number of adult wolf in Mayer Aquarium. The number of adult wolf in Mayer Aquarium equals 3 times the number of adult bear in Mayer Aquarium. The number of adult bear in Jefferson Circus equals 4 times the total number of adult animals in Mayer Aquarium. The number of adult racoon in Mayer Aquarium equals the number of adult wolf in Mayer Aquarium. The number of adult bear in Mayer Aquarium exists, and its number is greater than 0. The number of adult wolf in Hamilton Farm equals 3 times the number of adult racoon in Bundle Ranch. The total number of adult animals in Jefferson Circus equals 180. The number of adult wolf in Jefferson Circus equals 2 times the sum of the number of adult racoon in Hamilton Farm and the number of adult bear in Jefferson Circus.

Question: How many adult bear does Mayer Aquarium have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult wolf in Mayer Aquarium as Q; D = x = x; so Q = 3 * D = (3) * (x) = 3*x. Define adult racoon in Mayer Aquarium as z; so z = Q = 3*x. Define total number of adult animals in Mayer Aquarium as J; H = Q + x = 3*x + x = 4*x; so J = H + z = 4*x + 3*x = 7*x. Define adult bear in Jefferson Circus as q; n = J = 7*x; so q = 4 * n = (4) * (7*x) = 28*x. Define adult racoon in Hamilton Farm as w; so w = Q = 3*x. Define adult wolf in Jefferson Circus as l; O = w + q = 3*x + 28*x = 31*x; so l = 2 * O = (2) * (31*x) = 62*x. Define total number of adult animals in Jefferson Circus as e; so e = l + q = 62*x + 28*x = 90*x. We know e = 180, so we have 90*x = 180 and we solve it through the following steps: Simplifying the equation: 90*x = 180. Move all terms to one side: 90*x - 180 = 0. Isolate the term with x: 90*x = 180. Divide both sides by 90: x = 180 / 90. Solution: x = 2. Answer: 2.


The number of public highschool in Shoreline City equals 3 plus the number of private middle school in Shoreline City. The number of private middle school in Shoreline City exists, and its number is greater than 0. The total number of schools in Ruby Bay equals 145. The number of elementary school in Ruby Bay equals the sum of the number of private middle school in Ruby Bay and the number of private middle school in Shoreline City. The number of public highschool in Ruby Bay equals 4 times the number of private middle school in Ruby Bay. The number of elementary school in Shoreline City equals 4 times the sum of the number of public highschool in Shoreline City and the number of private middle school in Shoreline City. The number of private middle school in Ruby Bay equals 4 plus the number of elementary school in Shoreline City.

Question: How many private middle school does Shoreline City have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Shoreline City as x; we don't know its value yet but will find it out later. Define public highschool in Shoreline City as w; v = x = x; so w = 3 + v = 3 + x = x + 3. Define elementary school in Shoreline City as I; k = w + x = x + 3 + x = 2*x + 3; so I = 4 * k = (4) * (2*x + 3) = 8*x + 12. Define private middle school in Ruby Bay as f; n = I = 8*x + 12; so f = 4 + n = 4 + 8*x + 12 = 8*x + 16. Define public highschool in Ruby Bay as u; B = f = 8*x + 16; so u = 4 * B = (4) * (8*x + 16) = 32*x + 64. Define elementary school in Ruby Bay as e; so e = f + x = 8*x + 16 + x = 9*x + 16. Define total number of schools in Ruby Bay as a; L = e + f = 9*x + 16 + 8*x + 16 = 17*x + 32; so a = L + u = 17*x + 32 + 32*x + 64 = 49*x + 96. We know a = 145, so we have 49*x + 96 = 145 and we solve it through the following steps: Simplifying the equation: 49*x + 96 = 145. Move all terms to one side: 49*x - 49 = 0. Isolate the term with x: 49*x = 49. Divide both sides by 49: x = 49 / 49. Solution: x = 1. Answer: 1.


The number of private middle school in Brightford equals the total number of schools in Glenfield City. The number of regional medical school in Hawkesbury equals 3. The number of public highschool in Glenfield City equals the sum of the total number of schools in Evervale City and the total number of schools in Hawkesbury. The number of elementary school in Evervale City equals 1 plus the sum of the total number of schools in Hawkesbury and the number of regional medical school in Hawkesbury. The number of culinarian school in Glenfield City equals the number of elementary school in Evervale City. The number of elementary school in Glenfield City equals 2.

Question: What is the total number of schools in Brightford?

Solution: Define regional medical school in Hawkesbury as q; so q = 3. Define total number of schools in Hawkesbury as C; so C = q = 3. Define elementary school in Evervale City as r; h = C + q = 3 + 3 = 6; so r = 1 + h = 1 + 6 = 7. Define total number of schools in Evervale City as S; so S = r = 7. Define public highschool in Glenfield City as f; so f = S + C = 7 + 3 = 10. Define culinarian school in Glenfield City as X; so X = r = 7. Define elementary school in Glenfield City as v; so v = 2. Define total number of schools in Glenfield City as Y; D = v + f = 2 + 10 = 12; so Y = D + X = 12 + 7 = 19. Define private middle school in Brightford as Z; so Z = Y = 19. Define total number of schools in Brightford as O; so O = Z = 19. Answer: 19.


The number of adult wolf in Mayer Aquarium equals 3 plus the total number of adult animals in Hamilton Farm. The number of adult deer in South Zoo equals 3 plus the total number of adult animals in Mayer Aquarium. The number of adult bear in Bundle Ranch equals 3. The number of adult bear in Jefferson Circus equals 2 plus the sum of the total number of adult animals in Bundle Ranch and the number of adult bear in Bundle Ranch. The number of adult deer in Hamilton Farm equals 2 times the total number of adult animals in Jefferson Circus.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult bear in Bundle Ranch as D; so D = 3. Define total number of adult animals in Bundle Ranch as K; so K = D = 3. Define adult bear in Jefferson Circus as W; V = K + D = 3 + 3 = 6; so W = 2 + V = 2 + 6 = 8. Define total number of adult animals in Jefferson Circus as l; so l = W = 8. Define adult deer in Hamilton Farm as J; N = l = 8; so J = 2 * N = 2 * 8 = 16. Define total number of adult animals in Hamilton Farm as i; so i = J = 16. Define adult wolf in Mayer Aquarium as R; k = i = 16; so R = 3 + k = 3 + 16 = 19. Define total number of adult animals in Mayer Aquarium as c; so c = R = 19. Define adult deer in South Zoo as j; v = c = 19; so j = 3 + v = 3 + 19 = 22. Define total number of adult animals in South Zoo as U; so U = j = 22. Answer: 22.


The number of adult crow in Cedar Valley exists, and its number is greater than 0. The number of adult blue jay in Beverly Forest equals 2 plus the sum of the number of adult parrot in Beverly Forest and the total number of adult animals in Cedar Valley. The number of adult crow in Beverly Forest equals 4 times the number of adult blue jay in Beverly Forest. The total number of adult animals in Oakridge Riverside equals 416. The number of adult blue jay in Oakridge Riverside equals 4 times the number of adult crow in Beverly Forest. The number of adult parrot in Beverly Forest equals 2 times the total number of adult animals in Cedar Valley. The number of adult parrot in Cedar Valley equals 2 plus the number of adult crow in Cedar Valley.

Question: How many adult crow does Cedar Valley have?

Solution: The question is difficult, so we use equations to solve it. Define adult crow in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult parrot in Cedar Valley as S; W = x = x; so S = 2 + W = 2 + x = x + 2. Define total number of adult animals in Cedar Valley as C; so C = S + x = x + 2 + x = 2*x + 2. Define adult parrot in Beverly Forest as T; Q = C = 2*x + 2; so T = 2 * Q = (2) * (2*x + 2) = 4*x + 4. Define adult blue jay in Beverly Forest as r; E = T + C = 4*x + 4 + 2*x + 2 = 6*x + 6; so r = 2 + E = 2 + 6*x + 6 = 6*x + 8. Define adult crow in Beverly Forest as j; A = r = 6*x + 8; so j = 4 * A = (4) * (6*x + 8) = 24*x + 32. Define adult blue jay in Oakridge Riverside as y; H = j = 24*x + 32; so y = 4 * H = (4) * (24*x + 32) = 96*x + 128. Define total number of adult animals in Oakridge Riverside as q; so q = y = 96*x + 128. We know q = 416, so we have 96*x + 128 = 416 and we solve it through the following steps: Simplifying the equation: 96*x + 128 = 416. Move all terms to one side: 96*x - 288 = 0. Isolate the term with x: 96*x = 288. Divide both sides by 96: x = 288 / 96. Solution: x = 3. Answer: 3.


The number of upbeat metropolis comedy in Festival de Clairmont equals 1. The number of futuristic sci-fi movie in Rêves de Belleville equals the difference between the total number of movies in Festival de Saint-Rivage and the number of intense detective thriller in Festival de Clairmont. The number of intense detective thriller in Festival de Clairmont equals 1. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2 times the sum of the total number of movies in Festival de Clairmont, the number of intense detective thriller in Festival de Clairmont, and the number of upbeat metropolis comedy in Festival de Clairmont. The number of intense detective thriller in Rêves de Belleville equals 3 times the number of futuristic sci-fi movie in Rêves de Belleville.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define intense detective thriller in Festival de Clairmont as V; so V = 1. Define upbeat metropolis comedy in Festival de Clairmont as Y; so Y = 1. Define total number of movies in Festival de Clairmont as S; so S = Y + V = 1 + 1 = 2. Define upbeat metropolis comedy in Festival de Saint-Rivage as g; B = S + V = 2 + 1 = 3; C = B + Y = 3 + 1 = 4; so g = 2 * C = 2 * 4 = 8. Define total number of movies in Festival de Saint-Rivage as U; so U = g = 8. Define futuristic sci-fi movie in Rêves de Belleville as A; so A = U - V = 8 - 1 = 7. Define intense detective thriller in Rêves de Belleville as H; z = A = 7; so H = 3 * z = 3 * 7 = 21. Define total number of movies in Rêves de Belleville as Q; so Q = A + H = 7 + 21 = 28. Answer: 28.


The number of public highschool in Evervale City equals 3 plus the number of private middle school in Evervale City. The number of private middle school in Brightford equals 3 times the total number of schools in Glenfield City. The number of elementary school in Evervale City equals the number of public highschool in Glenfield City. The number of private middle school in Evervale City equals 4. The number of public highschool in Glenfield City equals 4. The number of elementary school in Brightford equals 4 plus the total number of schools in Evervale City.

Question: What is the total number of schools in Brightford?

Solution: Define public highschool in Glenfield City as K; so K = 4. Define elementary school in Evervale City as A; so A = K = 4. Define private middle school in Evervale City as q; so q = 4. Define public highschool in Evervale City as o; h = q = 4; so o = 3 + h = 3 + 4 = 7. Define total number of schools in Glenfield City as N; so N = K = 4. Define total number of schools in Evervale City as m; M = q + o = 4 + 7 = 11; so m = M + A = 11 + 4 = 15. Define private middle school in Brightford as H; Z = N = 4; so H = 3 * Z = 3 * 4 = 12. Define elementary school in Brightford as p; S = m = 15; so p = 4 + S = 4 + 15 = 19. Define total number of schools in Brightford as R; so R = H + p = 12 + 19 = 31. Answer: 31.


The total number of movies in West Sahara Movie Festival equals 63. The number of solemn period drama in Verdi Movie Festival equals 1. The number of upbeat metropolis comedy in Verdi Movie Festival equals 4 times the difference between the number of intense detective thriller in Golden Banana Movie Festival and the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in Northwood Movie Festival equals the number of upbeat metropolis comedy in Taylor Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2. The number of intense detective thriller in Golden Banana Movie Festival equals 3 times the number of solemn period drama in West Sahara Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4 times the sum of the number of upbeat metropolis comedy in Taylor Movie Festival and the number of intense detective thriller in Verdi Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 1 plus the number of solemn period drama in Taylor Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 3 times the number of upbeat metropolis comedy in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the difference between the number of upbeat metropolis comedy in Taylor Movie Festival and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the sum of the number of upbeat metropolis comedy in Verdi Movie Festival, the number of solemn period drama in West Sahara Movie Festival, and the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival exists, and its number is greater than 0.

Question: How many solemn period drama does Taylor Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define solemn period drama in West Sahara Movie Festival as D; g = x = x; so D = 1 + g = 1 + x = x + 1. Define intense detective thriller in Golden Banana Movie Festival as S; o = D = x + 1; so S = 3 * o = (3) * (x + 1) = 3*x + 3. Define upbeat metropolis comedy in Verdi Movie Festival as Z; c = S - x = (3*x + 3) - (x) = 2*x + 3; so Z = 4 * c = (4) * (2*x + 3) = 8*x + 12. Define upbeat metropolis comedy in West Sahara Movie Festival as d; F = Z + D = 8*x + 12 + x + 1 = 9*x + 13; so d = F + x = 9*x + 13 + x = 10*x + 13. Define intense detective thriller in West Sahara Movie Festival as Y; so Y = D = x + 1. Define total number of movies in West Sahara Movie Festival as a; v = d + Y = 10*x + 13 + x + 1 = 11*x + 14; so a = v + D = 11*x + 14 + x + 1 = 12*x + 15. We know a = 63, so we have 12*x + 15 = 63 and we solve it through the following steps: Simplifying the equation: 12*x + 15 = 63. Move all terms to one side: 12*x - 48 = 0. Isolate the term with x: 12*x = 48. Divide both sides by 12: x = 48 / 12. Solution: x = 4. Answer: 4.


The number of adult racoon in Bundle Ranch equals 4. The number of adult bear in South Zoo equals the sum of the number of adult wolf in South Zoo, the number of adult racoon in Jefferson Circus, and the number of adult bear in Jefferson Circus. The number of adult bear in Bundle Ranch equals 2. The number of adult bear in Jefferson Circus exists, and its number is greater than 0. The number of adult wolf in South Zoo equals 2 times the number of adult racoon in Jefferson Circus. The number of adult deer in South Zoo equals the number of adult racoon in South Zoo. The total number of adult animals in South Zoo equals 40. The number of adult deer in Jefferson Circus equals 3 times the difference between the number of adult wolf in Bundle Ranch and the number of adult racoon in Bundle Ranch. The number of adult racoon in South Zoo equals the difference between the number of adult racoon in Jefferson Circus and the number of adult bear in Jefferson Circus. The number of adult wolf in Jefferson Circus equals 4. The number of adult wolf in Bundle Ranch equals 2. The number of adult racoon in Jefferson Circus equals 3 times the number of adult bear in Jefferson Circus. The number of adult deer in Bundle Ranch equals the number of adult racoon in Bundle Ranch.

Question: How many adult bear does Jefferson Circus have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult racoon in Jefferson Circus as q; p = x = x; so q = 3 * p = (3) * (x) = 3*x. Define adult racoon in South Zoo as Z; so Z = q - x = (3*x) - (x) = 2*x. Define adult wolf in South Zoo as G; H = q = 3*x; so G = 2 * H = (2) * (3*x) = 6*x. Define adult deer in South Zoo as P; so P = Z = 2*x. Define adult bear in South Zoo as R; Y = G + q = 6*x + 3*x = 9*x; so R = Y + x = 9*x + x = 10*x. Define total number of adult animals in South Zoo as k; h = Z + P = 2*x + 2*x = 4*x; m = h + R = 4*x + 10*x = 14*x; so k = m + G = 14*x + 6*x = 20*x. We know k = 40, so we have 20*x = 40 and we solve it through the following steps: Simplifying the equation: 20*x = 40. Move all terms to one side: 20*x - 40 = 0. Isolate the term with x: 20*x = 40. Divide both sides by 20: x = 40 / 20. Solution: x = 2. Answer: 2.


The total number of schools in Shoreline City equals 16. The number of private middle school in Clearwater Bay equals the total number of schools in Ruby Bay. The number of regional medical school in Ruby Bay equals 1. The number of public highschool in Shoreline City equals the sum of the total number of schools in Clearwater Bay, the number of private middle school in Clearwater Bay, and the number of regional medical school in Ruby Bay. The number of private middle school in Ruby Bay equals 1 plus the number of regional medical school in Ruby Bay. The number of public highschool in Ruby Bay exists, and its number is greater than 0. The number of private middle school in Shoreline City equals the total number of schools in Ruby Bay.

Question: How many public highschool does Ruby Bay have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Ruby Bay as j; so j = 1. Define public highschool in Ruby Bay as x; we don't know its value yet but will find it out later. Define private middle school in Ruby Bay as E; D = j = 1; so E = 1 + D = 1 + 1 = 2. Define total number of schools in Ruby Bay as k; y = E + j = 2 + 1 = 3; so k = y + x = 3 + x = x + 3. Define private middle school in Clearwater Bay as O; so O = k = x + 3. Define total number of schools in Clearwater Bay as L; so L = O = x + 3. Define public highschool in Shoreline City as J; M = L + O = x + 3 + x + 3 = 2*x + 6; so J = M + j = 2*x + 6 + 1 = 2*x + 7. Define private middle school in Shoreline City as C; so C = k = x + 3. Define total number of schools in Shoreline City as z; so z = C + J = x + 3 + 2*x + 7 = 3*x + 10. We know z = 16, so we have 3*x + 10 = 16 and we solve it through the following steps: Simplifying the equation: 3*x + 10 = 16. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.


The number of upbeat metropolis comedy in Verdi Movie Festival equals 2 times the number of calm road movie in Verdi Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 2 times the total number of movies in Golden Banana Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the total number of movies in Golden Banana Movie Festival. The total number of movies in West Sahara Movie Festival equals 135. The number of calm road movie in Golden Banana Movie Festival equals 3 times the total number of movies in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Verdi Movie Festival equals the number of upbeat metropolis comedy in Verdi Movie Festival.

Question: How many calm road movie does Verdi Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define calm road movie in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Verdi Movie Festival as a; U = x = x; so a = 2 * U = (2) * (x) = 2*x. Define intense detective thriller in Verdi Movie Festival as o; so o = a = 2*x. Define total number of movies in Verdi Movie Festival as s; e = x + o = x + 2*x = 3*x; so s = e + a = 3*x + 2*x = 5*x. Define calm road movie in Golden Banana Movie Festival as I; Z = s = 5*x; so I = 3 * Z = (3) * (5*x) = 15*x. Define total number of movies in Golden Banana Movie Festival as J; so J = I = 15*x. Define intense detective thriller in West Sahara Movie Festival as H; G = J = 15*x; so H = 2 * G = (2) * (15*x) = 30*x. Define upbeat metropolis comedy in West Sahara Movie Festival as w; so w = J = 15*x. Define total number of movies in West Sahara Movie Festival as R; so R = H + w = 30*x + 15*x = 45*x. We know R = 135, so we have 45*x = 135 and we solve it through the following steps: Simplifying the equation: 45*x = 135. Move all terms to one side: 45*x - 135 = 0. Isolate the term with x: 45*x = 135. Divide both sides by 45: x = 135 / 45. Solution: x = 3. Answer: 3.


The number of upbeat metropolis comedy in West Sahara Movie Festival equals 2 times the number of futuristic sci-fi movie in Taylor Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals the total number of movies in Verdi Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals the total number of movies in Taylor Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 2 times the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals 4 times the total number of movies in Verdi Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 3.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define futuristic sci-fi movie in Verdi Movie Festival as t; so t = 3. Define upbeat metropolis comedy in Verdi Movie Festival as b; G = t = 3; so b = 2 * G = 2 * 3 = 6. Define total number of movies in Verdi Movie Festival as T; so T = b + t = 6 + 3 = 9. Define futuristic sci-fi movie in Taylor Movie Festival as q; D = T = 9; so q = 4 * D = 4 * 9 = 36. Define total number of movies in Taylor Movie Festival as I; so I = q = 36. Define solemn period drama in West Sahara Movie Festival as s; so s = I = 36. Define upbeat metropolis comedy in West Sahara Movie Festival as e; g = q = 36; so e = 2 * g = 2 * 36 = 72. Define futuristic sci-fi movie in West Sahara Movie Festival as U; so U = T = 9. Define total number of movies in West Sahara Movie Festival as m; p = e + U = 72 + 9 = 81; so m = p + s = 81 + 36 = 117. Answer: 117.


The number of private middle school in Riverton City equals the sum of the number of public highschool in Riverton City and the total number of schools in Shoreline City. The number of culinarian school in Riverton City equals 2 times the number of public highschool in Riverton City. The number of public highschool in Shoreline City equals 4 times the number of private middle school in Shoreline City. The number of public highschool in Riverton City equals the total number of schools in Shoreline City. The number of private middle school in Shoreline City equals 4. The number of culinarian school in Shoreline City equals the number of private middle school in Shoreline City.

Question: What is the total number of schools in Riverton City?

Solution: Define private middle school in Shoreline City as I; so I = 4. Define public highschool in Shoreline City as j; D = I = 4; so j = 4 * D = 4 * 4 = 16. Define culinarian school in Shoreline City as Z; so Z = I = 4. Define total number of schools in Shoreline City as G; H = Z + I = 4 + 4 = 8; so G = H + j = 8 + 16 = 24. Define public highschool in Riverton City as g; so g = G = 24. Define culinarian school in Riverton City as b; u = g = 24; so b = 2 * u = 2 * 24 = 48. Define private middle school in Riverton City as M; so M = g + G = 24 + 24 = 48. Define total number of schools in Riverton City as o; K = b + M = 48 + 48 = 96; so o = K + g = 96 + 24 = 120. Answer: 120.


The total number of schools in Glenfield City equals 212. The number of culinarian school in Evervale City equals 3 plus the number of culinarian school in Westhaven City. The number of culinarian school in Westhaven City equals 4 times the number of public highschool in Westhaven City. The number of public highschool in Westhaven City equals 2 plus the number of regional medical school in Westhaven City. The number of public highschool in Glenfield City equals the sum of the number of public highschool in Evervale City, the number of culinarian school in Westhaven City, and the number of regional medical school in Westhaven City. The number of regional medical school in Glenfield City equals the number of regional medical school in Westhaven City. The number of regional medical school in Evervale City equals the sum of the number of culinarian school in Glenfield City and the number of public highschool in Glenfield City. The number of regional medical school in Westhaven City exists, and its number is greater than 0. The number of public highschool in Evervale City equals the number of culinarian school in Westhaven City. The number of culinarian school in Glenfield City equals 3 times the number of public highschool in Glenfield City.

Question: How many regional medical school does Westhaven City have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Westhaven City as x; we don't know its value yet but will find it out later. Define public highschool in Westhaven City as F; T = x = x; so F = 2 + T = 2 + x = x + 2. Define culinarian school in Westhaven City as A; s = F = x + 2; so A = 4 * s = (4) * (x + 2) = 4*x + 8. Define public highschool in Evervale City as i; so i = A = 4*x + 8. Define public highschool in Glenfield City as J; w = i + A = 4*x + 8 + 4*x + 8 = 8*x + 16; so J = w + x = 8*x + 16 + x = 9*x + 16. Define culinarian school in Glenfield City as E; h = J = 9*x + 16; so E = 3 * h = (3) * (9*x + 16) = 27*x + 48. Define regional medical school in Glenfield City as z; so z = x = x. Define total number of schools in Glenfield City as Q; k = z + J = x + 9*x + 16 = 10*x + 16; so Q = k + E = 10*x + 16 + 27*x + 48 = 37*x + 64. We know Q = 212, so we have 37*x + 64 = 212 and we solve it through the following steps: Simplifying the equation: 37*x + 64 = 212. Move all terms to one side: 37*x - 148 = 0. Isolate the term with x: 37*x = 148. Divide both sides by 37: x = 148 / 37. Solution: x = 4. Answer: 4.


The number of adult blue jay in South Zoo equals 4. The total number of adult animals in Bundle Ranch equals 41. The number of adult crow in South Zoo equals 2. The number of adult eagle in Bundle Ranch equals 3 times the number of adult eagle in Hamilton Farm. The number of adult parrot in Bundle Ranch equals 2 times the sum of the number of adult eagle in Hamilton Farm and the number of adult blue jay in Mayer Aquarium. The number of adult eagle in Hamilton Farm equals 3 plus the number of adult blue jay in Mayer Aquarium. The number of adult crow in Bundle Ranch exists, and its number is greater than 0. The number of adult eagle in South Zoo equals the difference between the total number of adult animals in South Zoo and the total number of adult animals in Mayer Aquarium. The number of adult blue jay in Bundle Ranch equals 4 plus the number of adult crow in Bundle Ranch. The number of adult parrot in South Zoo equals 1. The number of adult blue jay in Mayer Aquarium equals 2. The number of adult parrot in Hamilton Farm equals 4. The number of adult eagle in Mayer Aquarium equals 3. The number of adult crow in Mayer Aquarium equals 2 times the number of adult parrot in South Zoo. The number of adult blue jay in Hamilton Farm equals 3. The number of adult parrot in Mayer Aquarium equals 1. The number of adult crow in Hamilton Farm equals 2.

Question: How many adult crow does Bundle Ranch have?

Solution: The question is difficult, so we use equations to solve it. Define adult blue jay in Mayer Aquarium as i; so i = 2. Define adult eagle in Hamilton Farm as s; H = i = 2; so s = 3 + H = 3 + 2 = 5. Define adult parrot in Bundle Ranch as R; o = s + i = 5 + 2 = 7; so R = 2 * o = (2) * (7) = 14. Define adult crow in Bundle Ranch as x; we don't know its value yet but will find it out later. Define adult blue jay in Bundle Ranch as I; u = x = x; so I = 4 + u = 4 + x = x + 4. Define adult eagle in Bundle Ranch as Q; K = s = 5; so Q = 3 * K = (3) * (5) = 15. Define total number of adult animals in Bundle Ranch as v; O = x + R = x + 14 = x + 14; f = O + I = x + 14 + x + 4 = 2*x + 18; so v = f + Q = 2*x + 18 + 15 = 2*x + 33. We know v = 41, so we have 2*x + 33 = 41 and we solve it through the following steps: Simplifying the equation: 2*x + 33 = 41. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.


The total number of movies in Festival de Clairmont equals 66. The number of intense detective thriller in Festival de Clairmont equals 3 times the sum of the number of calm road movie in Festival de Clairmont and the number of solemn period drama in Festival Lumière de Valmont. The number of solemn period drama in Festival de Clairmont equals 4 plus the total number of movies in Rêves de Belleville. The number of solemn period drama in Festival Lumière de Valmont equals 2 plus the number of intense detective thriller in Rêves de Belleville. The number of calm road movie in Festival de Clairmont equals 3 times the total number of movies in Festival Lumière de Valmont. The number of intense detective thriller in Rêves de Belleville exists, and its number is greater than 0.

Question: How many intense detective thriller does Rêves de Belleville have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Rêves de Belleville as x; we don't know its value yet but will find it out later. Define solemn period drama in Festival Lumière de Valmont as s; N = x = x; so s = 2 + N = 2 + x = x + 2. Define total number of movies in Rêves de Belleville as I; so I = x = x. Define total number of movies in Festival Lumière de Valmont as D; so D = s = x + 2. Define calm road movie in Festival de Clairmont as G; d = D = x + 2; so G = 3 * d = (3) * (x + 2) = 3*x + 6. Define solemn period drama in Festival de Clairmont as t; U = I = x; so t = 4 + U = 4 + x = x + 4. Define intense detective thriller in Festival de Clairmont as S; C = G + s = 3*x + 6 + x + 2 = 4*x + 8; so S = 3 * C = (3) * (4*x + 8) = 12*x + 24. Define total number of movies in Festival de Clairmont as o; y = S + G = 12*x + 24 + 3*x + 6 = 15*x + 30; so o = y + t = 15*x + 30 + x + 4 = 16*x + 34. We know o = 66, so we have 16*x + 34 = 66 and we solve it through the following steps: Simplifying the equation: 16*x + 34 = 66. Move all terms to one side: 16*x - 32 = 0. Isolate the term with x: 16*x = 32. Divide both sides by 16: x = 32 / 16. Solution: x = 2. Answer: 2.


The number of culinarian school in Clearwater Bay equals 3 times the sum of the number of private middle school in Riverton City, the number of culinarian school in Shoreline City, and the number of private middle school in Clearwater Bay. The number of private middle school in Clearwater Bay equals 4. The number of private middle school in Shoreline City equals 2 times the number of regional medical school in Riverton City. The number of regional medical school in Riverton City equals 2. The number of culinarian school in Shoreline City equals the number of private middle school in Shoreline City. The number of regional medical school in Shoreline City equals 4. The number of regional medical school in Clearwater Bay equals 4 plus the sum of the total number of schools in Shoreline City and the number of culinarian school in Shoreline City. The number of private middle school in Riverton City equals 3 times the sum of the number of regional medical school in Clearwater Bay, the number of regional medical school in Riverton City, and the number of regional medical school in Shoreline City.

Question: How many private middle school does Riverton City have?

Solution: Define regional medical school in Riverton City as G; so G = 2. Define private middle school in Shoreline City as C; x = G = 2; so C = 2 * x = 2 * 2 = 4. Define culinarian school in Shoreline City as d; so d = C = 4. Define regional medical school in Shoreline City as h; so h = 4. Define total number of schools in Shoreline City as k; l = d + h = 4 + 4 = 8; so k = l + C = 8 + 4 = 12. Define regional medical school in Clearwater Bay as B; s = k + d = 12 + 4 = 16; so B = 4 + s = 4 + 16 = 20. Define private middle school in Riverton City as r; S = B + G = 20 + 2 = 22; n = S + h = 22 + 4 = 26; so r = 3 * n = 3 * 26 = 78. Answer: 78.


The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 4 times the number of calm road movie in Verdi Movie Festival. The number of calm road movie in Northwood Movie Festival equals 3 times the number of upbeat metropolis comedy in Northwood Movie Festival. The number of calm road movie in Verdi Movie Festival equals 4. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 times the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the number of calm road movie in Verdi Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define calm road movie in Verdi Movie Festival as v; so v = 4. Define futuristic sci-fi movie in Golden Banana Movie Festival as B; o = v = 4; so B = 4 * o = 4 * 4 = 16. Define calm road movie in Golden Banana Movie Festival as N; so N = v = 4. Define upbeat metropolis comedy in Golden Banana Movie Festival as H; s = B = 16; so H = 2 * s = 2 * 16 = 32. Define total number of movies in Golden Banana Movie Festival as U; S = B + N = 16 + 4 = 20; so U = S + H = 20 + 32 = 52. Define futuristic sci-fi movie in Verdi Movie Festival as V; so V = U = 52. Define upbeat metropolis comedy in Northwood Movie Festival as r; so r = V = 52. Define calm road movie in Northwood Movie Festival as z; b = r = 52; so z = 3 * b = 3 * 52 = 156. Define total number of movies in Northwood Movie Festival as m; so m = r + z = 52 + 156 = 208. Answer: 208.


The number of calm road movie in Festival de Clairmont equals the total number of movies in Rêves de Belleville. The number of calm road movie in Festival Lumière de Valmont equals 2 plus the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 1. The number of upbeat metropolis comedy in Rêves de Belleville equals 4 plus the difference between the total number of movies in Festival Lumière de Valmont and the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of calm road movie in Rêves de Belleville equals 1. The number of futuristic sci-fi movie in Rêves de Belleville equals the number of calm road movie in Rêves de Belleville.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define futuristic sci-fi movie in Festival Lumière de Valmont as G; so G = 1. Define calm road movie in Festival Lumière de Valmont as j; w = G = 1; so j = 2 + w = 2 + 1 = 3. Define total number of movies in Festival Lumière de Valmont as r; so r = j + G = 3 + 1 = 4. Define upbeat metropolis comedy in Rêves de Belleville as Z; P = r - G = 4 - 1 = 3; so Z = 4 + P = 4 + 3 = 7. Define calm road movie in Rêves de Belleville as t; so t = 1. Define futuristic sci-fi movie in Rêves de Belleville as J; so J = t = 1. Define total number of movies in Rêves de Belleville as y; A = t + J = 1 + 1 = 2; so y = A + Z = 2 + 7 = 9. Define calm road movie in Festival de Clairmont as C; so C = y = 9. Define total number of movies in Festival de Clairmont as v; so v = C = 9. Answer: 9.


The number of regional medical school in Hawkesbury equals the number of public highschool in Brightford. The number of private middle school in Hawkesbury equals the number of public highschool in Glenfield City. The number of private middle school in Evervale City equals the number of regional medical school in Evervale City. The total number of schools in Brightford equals 47. The number of public highschool in Glenfield City equals 3 plus the difference between the number of culinarian school in Evervale City and the number of culinarian school in Glenfield City. The number of culinarian school in Brightford equals 3 times the sum of the number of public highschool in Brightford and the number of culinarian school in Glenfield City. The number of regional medical school in Evervale City equals the number of regional medical school in Glenfield City. The number of regional medical school in Brightford exists, and its number is greater than 0. The number of culinarian school in Evervale City equals 2 plus the number of culinarian school in Glenfield City. The number of public highschool in Evervale City equals 2 plus the sum of the total number of schools in Hawkesbury, the number of private middle school in Evervale City, and the number of private middle school in Hawkesbury. The number of culinarian school in Glenfield City equals 1. The number of public highschool in Brightford equals 2 times the number of public highschool in Glenfield City. The number of regional medical school in Glenfield City equals 4.

Question: How many regional medical school does Brightford have?

Solution: The question is difficult, so we use equations to solve it. Define culinarian school in Glenfield City as g; so g = 1. Define culinarian school in Evervale City as Z; d = g = 1; so Z = 2 + d = 2 + 1 = 3. Define public highschool in Glenfield City as p; l = Z - g = (3) - (1) = 2; so p = 3 + l = 3 + 2 = 5. Define public highschool in Brightford as E; O = p = 5; so E = 2 * O = (2) * (5) = 10. Define culinarian school in Brightford as f; v = E + g = 10 + 1 = 11; so f = 3 * v = (3) * (11) = 33. Define regional medical school in Brightford as x; we don't know its value yet but will find it out later. Define total number of schools in Brightford as j; Y = x + E = x + 10 = x + 10; so j = Y + f = x + 10 + 33 = x + 43. We know j = 47, so we have x + 43 = 47 and we solve it through the following steps: Simplifying the equation: x + 43 = 47. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.


The total number of movies in West Sahara Movie Festival equals 6. The number of futuristic sci-fi movie in Northwood Movie Festival equals 1 plus the total number of movies in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Taylor Movie Festival equals 2 plus the total number of movies in Northwood Movie Festival. The number of calm road movie in West Sahara Movie Festival equals the difference between the total number of movies in Taylor Movie Festival and the number of calm road movie in Taylor Movie Festival. The number of solemn period drama in Verdi Movie Festival exists, and its number is greater than 0.

Question: How many solemn period drama does Verdi Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define solemn period drama in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Verdi Movie Festival as q; so q = x = x. Define futuristic sci-fi movie in Northwood Movie Festival as w; t = q = x; so w = 1 + t = 1 + x = x + 1. Define calm road movie in Taylor Movie Festival as k; y = w + x = x + 1 + x = 2*x + 1; so k = y + q = 2*x + 1 + x = 3*x + 1. Define total number of movies in Northwood Movie Festival as O; so O = w = x + 1. Define intense detective thriller in Taylor Movie Festival as c; T = O = x + 1; so c = 2 + T = 2 + x + 1 = x + 3. Define total number of movies in Taylor Movie Festival as D; so D = k + c = 3*x + 1 + x + 3 = 4*x + 4. Define calm road movie in West Sahara Movie Festival as Y; so Y = D - k = (4*x + 4) - (3*x + 1) = x + 3. Define total number of movies in West Sahara Movie Festival as Z; so Z = Y = x + 3. We know Z = 6, so we have x + 3 = 6 and we solve it through the following steps: Simplifying the equation: x + 3 = 6. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of intense detective thriller in Taylor Movie Festival equals the total number of movies in West Sahara Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 3 plus the total number of movies in Golden Banana Movie Festival. The total number of movies in Taylor Movie Festival equals 42. The number of solemn period drama in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival and the total number of movies in Golden Banana Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival exists, and its number is greater than 0. The number of solemn period drama in West Sahara Movie Festival equals 3 times the number of futuristic sci-fi movie in West Sahara Movie Festival.

Question: How many intense detective thriller does Golden Banana Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define solemn period drama in Golden Banana Movie Festival as h; so h = x = x. Define total number of movies in Golden Banana Movie Festival as o; so o = h + x = x + x = 2*x. Define futuristic sci-fi movie in West Sahara Movie Festival as W; r = o = 2*x; so W = 3 + r = 3 + 2*x = 2*x + 3. Define solemn period drama in West Sahara Movie Festival as T; U = W = 2*x + 3; so T = 3 * U = (3) * (2*x + 3) = 6*x + 9. Define total number of movies in West Sahara Movie Festival as Z; so Z = T + W = 6*x + 9 + 2*x + 3 = 8*x + 12. Define intense detective thriller in Taylor Movie Festival as e; so e = Z = 8*x + 12. Define futuristic sci-fi movie in Taylor Movie Festival as V; so V = Z + o = 8*x + 12 + 2*x = 10*x + 12. Define total number of movies in Taylor Movie Festival as H; so H = V + e = 10*x + 12 + 8*x + 12 = 18*x + 24. We know H = 42, so we have 18*x + 24 = 42 and we solve it through the following steps: Simplifying the equation: 18*x + 24 = 42. Move all terms to one side: 18*x - 18 = 0. Isolate the term with x: 18*x = 18. Divide both sides by 18: x = 18 / 18. Solution: x = 1. Answer: 1.