The number of futuristic sci-fi movie in Taylor Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of intense detective thriller in Taylor Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 2 plus the number of intense detective thriller in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3 plus the number of futuristic sci-fi movie in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the number of upbeat metropolis comedy in Taylor Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 3. The number of intense detective thriller in Golden Banana Movie Festival equals 4.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define intense detective thriller in Golden Banana Movie Festival as B; so B = 4. Define solemn period drama in Golden Banana Movie Festival as H; Y = B = 4; so H = 2 + Y = 2 + 4 = 6. Define total number of movies in Golden Banana Movie Festival as D; so D = H + B = 6 + 4 = 10. Define futuristic sci-fi movie in Taylor Movie Festival as P; so P = D = 10. Define upbeat metropolis comedy in Taylor Movie Festival as g; G = P = 10; so g = 3 + G = 3 + 10 = 13. Define intense detective thriller in Taylor Movie Festival as o; so o = g = 13. Define upbeat metropolis comedy in Northwood Movie Festival as Z; so Z = o = 13. Define futuristic sci-fi movie in Northwood Movie Festival as l; so l = B = 4. Define intense detective thriller in Northwood Movie Festival as a; so a = 3. Define total number of movies in Northwood Movie Festival as N; i = l + a = 4 + 3 = 7; so N = i + Z = 7 + 13 = 20. Answer: 20.


The number of public highschool in Shoreline City equals 4. The number of culinarian school in Ruby Bay equals the number of public highschool in Clearwater Bay. The number of public highschool in Ruby Bay equals the sum of the number of public highschool in Clearwater Bay and the number of private middle school in Clearwater Bay. The number of private middle school in Ruby Bay equals 3 plus the difference between the total number of schools in Shoreline City and the number of public highschool in Ruby Bay. The number of private middle school in Clearwater Bay equals the number of public highschool in Shoreline City. The number of culinarian school in Clearwater Bay equals the sum of the number of public highschool in Ruby Bay and the number of private middle school in Clearwater Bay. The number of public highschool in Clearwater Bay equals 4. The number of culinarian school in Shoreline City equals the number of private middle school in Clearwater Bay.

Question: What is the total number of schools in Ruby Bay?

Solution: Define public highschool in Shoreline City as M; so M = 4. Define private middle school in Clearwater Bay as x; so x = M = 4. Define culinarian school in Shoreline City as V; so V = x = 4. Define public highschool in Clearwater Bay as L; so L = 4. Define public highschool in Ruby Bay as D; so D = L + x = 4 + 4 = 8. Define total number of schools in Shoreline City as o; so o = M + V = 4 + 4 = 8. Define private middle school in Ruby Bay as N; v = o - D = 8 - 8 = 0; so N = 3 + v = 3 + 0 = 3. Define culinarian school in Ruby Bay as d; so d = L = 4. Define total number of schools in Ruby Bay as I; w = D + d = 8 + 4 = 12; so I = w + N = 12 + 3 = 15. Answer: 15.


The number of adult wolf in South Zoo equals the sum of the total number of adult animals in Hamilton Farm, the number of adult racoon in Hamilton Farm, and the number of adult deer in Hamilton Farm. The number of adult racoon in Jefferson Circus equals 1 plus the number of adult deer in Hamilton Farm. The number of adult deer in Hamilton Farm equals 1. The number of adult racoon in Hamilton Farm equals 2. The number of adult deer in Bundle Ranch equals 3. The number of adult deer in Jefferson Circus equals the number of adult wolf in South Zoo. The number of adult racoon in Mayer Aquarium equals 1 plus the number of adult wolf in Bundle Ranch. The number of adult racoon in South Zoo equals 4 times the number of adult deer in Bundle Ranch. The number of adult deer in South Zoo equals the difference between the number of adult racoon in South Zoo and the number of adult deer in Bundle Ranch. The number of adult wolf in Bundle Ranch equals 1. The number of adult wolf in Jefferson Circus equals the sum of the number of adult wolf in South Zoo and the total number of adult animals in Hamilton Farm.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult deer in Hamilton Farm as W; so W = 1. Define adult racoon in Hamilton Farm as d; so d = 2. Define total number of adult animals in Hamilton Farm as a; so a = W + d = 1 + 2 = 3. Define adult wolf in South Zoo as Z; l = a + d = 3 + 2 = 5; so Z = l + W = 5 + 1 = 6. Define adult wolf in Jefferson Circus as f; so f = Z + a = 6 + 3 = 9. Define adult deer in Jefferson Circus as S; so S = Z = 6. Define adult racoon in Jefferson Circus as Q; w = W = 1; so Q = 1 + w = 1 + 1 = 2. Define total number of adult animals in Jefferson Circus as s; x = f + S = 9 + 6 = 15; so s = x + Q = 15 + 2 = 17. Answer: 17.


The number of regional medical school in Shoreline City equals 3 plus the sum of the number of private middle school in Clearwater Bay, the number of culinarian school in Oakbridge City, and the number of culinarian school in Shoreline City. The number of culinarian school in Riverton City equals 4. The number of public highschool in Oakbridge City equals 3. The number of private middle school in Oakbridge City equals 3. The number of culinarian school in Shoreline City equals 3. The number of private middle school in Clearwater Bay equals the number of public highschool in Riverton City. The number of culinarian school in Clearwater Bay equals 2. The number of public highschool in Riverton City equals 3 plus the number of regional medical school in Clearwater Bay. The number of regional medical school in Clearwater Bay equals 3. The number of regional medical school in Oakbridge City equals 4 times the number of culinarian school in Riverton City. The number of regional medical school in Riverton City equals 2. The number of public highschool in Shoreline City equals 3. The number of private middle school in Riverton City equals 2 plus the number of culinarian school in Shoreline City. The number of private middle school in Shoreline City equals 4. The number of culinarian school in Oakbridge City equals the sum of the total number of schools in Clearwater Bay, the number of culinarian school in Clearwater Bay, the number of regional medical school in Clearwater Bay, and the number of private middle school in Clearwater Bay. The number of public highschool in Clearwater Bay equals the difference between the number of public highschool in Riverton City and the number of regional medical school in Clearwater Bay.

Question: How many culinarian school does Oakbridge City have?

Solution: Define regional medical school in Clearwater Bay as W; so W = 3. Define public highschool in Riverton City as I; u = W = 3; so I = 3 + u = 3 + 3 = 6. Define public highschool in Clearwater Bay as e; so e = I - W = 6 - 3 = 3. Define culinarian school in Clearwater Bay as i; so i = 2. Define private middle school in Clearwater Bay as x; so x = I = 6. Define total number of schools in Clearwater Bay as M; K = e + x = 3 + 6 = 9; a = K + W = 9 + 3 = 12; so M = a + i = 12 + 2 = 14. Define culinarian school in Oakbridge City as k; t = M + i = 14 + 2 = 16; d = t + W = 16 + 3 = 19; so k = d + x = 19 + 6 = 25. Answer: 25.


The number of calm road movie in Cinéma de Montreval equals the sum of the number of solemn period drama in Festival de Saint-Rivage, the total number of movies in Festival de Saint-Rivage, and the number of calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage equals 4 times the number of solemn period drama in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 2. The number of solemn period drama in Festival de Saint-Rivage equals 3. The number of futuristic sci-fi movie in Cinéma de Montreval equals 1 plus the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Cinéma de Montreval equals the sum of the total number of movies in Festival de Saint-Rivage and the number of solemn period drama in Festival de Saint-Rivage. The number of calm road movie in Festival de Clairmont equals 3. The number of solemn period drama in Festival de Clairmont equals 3. The number of calm road movie in Festival Lumière de Valmont equals the number of calm road movie in Festival de Saint-Rivage.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define solemn period drama in Festival de Saint-Rivage as F; so F = 3. Define calm road movie in Festival de Saint-Rivage as v; s = F = 3; so v = 4 * s = 4 * 3 = 12. Define total number of movies in Festival de Saint-Rivage as C; so C = v + F = 12 + 3 = 15. Define intense detective thriller in Cinéma de Montreval as P; so P = C + F = 15 + 3 = 18. Define calm road movie in Cinéma de Montreval as M; R = F + C = 3 + 15 = 18; so M = R + v = 18 + 12 = 30. Define futuristic sci-fi movie in Cinéma de Montreval as N; o = P = 18; so N = 1 + o = 1 + 18 = 19. Define total number of movies in Cinéma de Montreval as Q; g = M + P = 30 + 18 = 48; so Q = g + N = 48 + 19 = 67. Answer: 67.


The number of adult crow in Oakridge Riverside equals the number of adult eagle in Oakridge Riverside. The number of adult crow in Cedar Valley equals 4 plus the difference between the total number of adult animals in Oakridge Riverside and the number of adult crow in Oakridge Riverside. The number of adult crow in Pine Ridge equals the total number of adult animals in Cedar Valley. The number of adult eagle in Cedar Valley equals 4. The number of adult eagle in Pine Ridge equals the sum of the total number of adult animals in Cedar Valley and the number of adult eagle in Cedar Valley. The number of adult eagle in Oakridge Riverside equals 4.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult eagle in Oakridge Riverside as s; so s = 4. Define adult crow in Oakridge Riverside as v; so v = s = 4. Define total number of adult animals in Oakridge Riverside as g; so g = s + v = 4 + 4 = 8. Define adult crow in Cedar Valley as I; B = g - v = 8 - 4 = 4; so I = 4 + B = 4 + 4 = 8. Define adult eagle in Cedar Valley as o; so o = 4. Define total number of adult animals in Cedar Valley as m; so m = o + I = 4 + 8 = 12. Define adult eagle in Pine Ridge as Z; so Z = m + o = 12 + 4 = 16. Define adult crow in Pine Ridge as h; so h = m = 12. Define total number of adult animals in Pine Ridge as F; so F = Z + h = 16 + 12 = 28. Answer: 28.


The number of solemn period drama in Festival de Clairmont equals 4. The number of intense detective thriller in Cinéma de Montreval equals the number of futuristic sci-fi movie in Festival de Clairmont. The number of intense detective thriller in Festival de Clairmont equals the number of intense detective thriller in Festival Lumière de Valmont. The number of calm road movie in Festival Lumière de Valmont equals 3. The number of futuristic sci-fi movie in Festival de Clairmont equals 1 plus the difference between the number of calm road movie in Festival de Clairmont and the number of futuristic sci-fi movie in Cinéma de Montreval. The number of calm road movie in Festival de Clairmont equals the total number of movies in Rêves de Belleville. The number of calm road movie in Rêves de Belleville equals 4 times the number of intense detective thriller in Festival de Clairmont. The number of futuristic sci-fi movie in Cinéma de Montreval equals the number of calm road movie in Festival Lumière de Valmont. The number of intense detective thriller in Festival Lumière de Valmont equals 1 plus the number of futuristic sci-fi movie in Cinéma de Montreval. The number of solemn period drama in Rêves de Belleville equals the number of intense detective thriller in Festival Lumière de Valmont.

Question: How many intense detective thriller does Cinéma de Montreval have?

Solution: Define calm road movie in Festival Lumière de Valmont as C; so C = 3. Define futuristic sci-fi movie in Cinéma de Montreval as H; so H = C = 3. Define intense detective thriller in Festival Lumière de Valmont as u; n = H = 3; so u = 1 + n = 1 + 3 = 4. Define intense detective thriller in Festival de Clairmont as R; so R = u = 4. Define solemn period drama in Rêves de Belleville as V; so V = u = 4. Define calm road movie in Rêves de Belleville as W; l = R = 4; so W = 4 * l = 4 * 4 = 16. Define total number of movies in Rêves de Belleville as t; so t = V + W = 4 + 16 = 20. Define calm road movie in Festival de Clairmont as v; so v = t = 20. Define futuristic sci-fi movie in Festival de Clairmont as U; s = v - H = 20 - 3 = 17; so U = 1 + s = 1 + 17 = 18. Define intense detective thriller in Cinéma de Montreval as E; so E = U = 18. Answer: 18.


The number of culinarian school in Brightford equals the number of regional medical school in Evervale City. The number of regional medical school in Evervale City equals 4 times the number of public highschool in Evervale City. The number of private middle school in Evervale City equals 4 times the total number of schools in Hawkesbury. The number of regional medical school in Hawkesbury equals 3. The number of culinarian school in Evervale City equals the number of regional medical school in Hawkesbury. The number of culinarian school in Glenfield City equals the total number of schools in Evervale City. The number of private middle school in Glenfield City equals 4. The number of private middle school in Brightford equals 4. The number of culinarian school in Hawkesbury equals the number of regional medical school in Hawkesbury. The number of public highschool in Glenfield City equals 2. The number of public highschool in Hawkesbury equals 2 plus the number of culinarian school in Evervale City. The number of regional medical school in Brightford equals 4. The number of public highschool in Evervale City equals 4 plus the number of private middle school in Evervale City. The number of regional medical school in Glenfield City equals 2 plus the sum of the number of regional medical school in Brightford and the number of public highschool in Glenfield City.

Question: How many culinarian school does Brightford have?

Solution: Define regional medical school in Hawkesbury as F; so F = 3. Define culinarian school in Evervale City as I; so I = F = 3. Define public highschool in Hawkesbury as X; a = I = 3; so X = 2 + a = 2 + 3 = 5. Define culinarian school in Hawkesbury as U; so U = F = 3. Define total number of schools in Hawkesbury as E; H = F + X = 3 + 5 = 8; so E = H + U = 8 + 3 = 11. Define private middle school in Evervale City as c; n = E = 11; so c = 4 * n = 4 * 11 = 44. Define public highschool in Evervale City as W; p = c = 44; so W = 4 + p = 4 + 44 = 48. Define regional medical school in Evervale City as j; Q = W = 48; so j = 4 * Q = 4 * 48 = 192. Define culinarian school in Brightford as s; so s = j = 192. Answer: 192.


The number of elementary school in Brightford equals 1 plus the total number of schools in Westhaven City. The number of elementary school in Hawkesbury equals 1. The number of culinarian school in Westhaven City equals the total number of schools in Hawkesbury. The number of culinarian school in Hawkesbury equals 2 plus the number of elementary school in Hawkesbury. The number of elementary school in Westhaven City equals 3. The number of culinarian school in Brightford equals 4 plus the number of elementary school in Hawkesbury.

Question: What is the total number of schools in Brightford?

Solution: Define elementary school in Hawkesbury as s; so s = 1. Define culinarian school in Hawkesbury as W; R = s = 1; so W = 2 + R = 2 + 1 = 3. Define total number of schools in Hawkesbury as Z; so Z = s + W = 1 + 3 = 4. Define culinarian school in Westhaven City as a; so a = Z = 4. Define elementary school in Westhaven City as O; so O = 3. Define total number of schools in Westhaven City as j; so j = O + a = 3 + 4 = 7. Define elementary school in Brightford as P; k = j = 7; so P = 1 + k = 1 + 7 = 8. Define culinarian school in Brightford as N; I = s = 1; so N = 4 + I = 4 + 1 = 5. Define total number of schools in Brightford as w; so w = P + N = 8 + 5 = 13. Answer: 13.


The number of intense detective thriller in Festival Lumière de Valmont equals the total number of movies in Festival de Clairmont. The number of intense detective thriller in Rêves de Belleville equals 2. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the sum of the total number of movies in Cinéma de Montreval and the number of intense detective thriller in Festival Lumière de Valmont. The number of intense detective thriller in Cinéma de Montreval equals 2 plus the number of upbeat metropolis comedy in Festival de Clairmont. The number of futuristic sci-fi movie in Rêves de Belleville equals 2. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 3. The number of upbeat metropolis comedy in Festival de Clairmont equals 1. The number of futuristic sci-fi movie in Festival de Clairmont equals 3 times the number of upbeat metropolis comedy in Festival de Clairmont.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define upbeat metropolis comedy in Festival de Clairmont as q; so q = 1. Define intense detective thriller in Cinéma de Montreval as U; H = q = 1; so U = 2 + H = 2 + 1 = 3. Define futuristic sci-fi movie in Festival de Clairmont as I; p = q = 1; so I = 3 * p = 3 * 1 = 3. Define total number of movies in Festival de Clairmont as B; so B = q + I = 1 + 3 = 4. Define intense detective thriller in Festival Lumière de Valmont as n; so n = B = 4. Define total number of movies in Cinéma de Montreval as T; so T = U = 3. Define futuristic sci-fi movie in Festival Lumière de Valmont as M; so M = T + n = 3 + 4 = 7. Define upbeat metropolis comedy in Festival Lumière de Valmont as m; so m = 3. Define total number of movies in Festival Lumière de Valmont as e; O = m + n = 3 + 4 = 7; so e = O + M = 7 + 7 = 14. Answer: 14.


The number of adult bear in Jefferson Circus equals 2. The number of adult bear in South Zoo equals 2 times the number of adult bear in Jefferson Circus. The number of adult racoon in Hamilton Farm equals the sum of the number of adult bear in South Zoo, the number of adult bear in Hamilton Farm, and the number of adult wolf in Hamilton Farm. The number of adult racoon in Jefferson Circus equals 4. The number of adult wolf in Jefferson Circus equals 2. The number of adult racoon in South Zoo equals the difference between the total number of adult animals in Jefferson Circus and the number of adult wolf in Hamilton Farm. The number of adult wolf in Hamilton Farm equals 4 times the difference between the number of adult bear in South Zoo and the number of adult bear in Jefferson Circus. The number of adult wolf in South Zoo equals 4 plus the number of adult racoon in Jefferson Circus. The number of adult bear in Hamilton Farm equals 1 plus the sum of the number of adult bear in South Zoo and the number of adult bear in Jefferson Circus.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult bear in Jefferson Circus as N; so N = 2. Define adult bear in South Zoo as q; T = N = 2; so q = 2 * T = 2 * 2 = 4. Define adult wolf in Hamilton Farm as O; r = q - N = 4 - 2 = 2; so O = 4 * r = 4 * 2 = 8. Define adult bear in Hamilton Farm as f; E = q + N = 4 + 2 = 6; so f = 1 + E = 1 + 6 = 7. Define adult racoon in Hamilton Farm as V; y = q + f = 4 + 7 = 11; so V = y + O = 11 + 8 = 19. Define total number of adult animals in Hamilton Farm as B; Z = O + f = 8 + 7 = 15; so B = Z + V = 15 + 19 = 34. Answer: 34.


The number of upbeat metropolis comedy in Cinéma de Montreval equals the number of calm road movie in Rêves de Belleville. The number of intense detective thriller in Festival Lumière de Valmont equals 3 plus the sum of the total number of movies in Festival Lumière de Valmont and the number of intense detective thriller in Rêves de Belleville. The number of solemn period drama in Festival de Saint-Rivage equals 3. The number of solemn period drama in Rêves de Belleville equals 2 times the total number of movies in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the number of solemn period drama in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2 plus the number of solemn period drama in Festival de Saint-Rivage. The number of calm road movie in Rêves de Belleville equals 1 plus the sum of the total number of movies in Festival de Saint-Rivage, the number of solemn period drama in Festival de Saint-Rivage, and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of intense detective thriller in Cinéma de Montreval equals 4. The number of intense detective thriller in Rêves de Belleville equals 4.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define solemn period drama in Festival de Saint-Rivage as n; so n = 3. Define upbeat metropolis comedy in Festival de Saint-Rivage as g; N = n = 3; so g = 2 + N = 2 + 3 = 5. Define total number of movies in Festival de Saint-Rivage as d; so d = n + g = 3 + 5 = 8. Define calm road movie in Rêves de Belleville as P; v = d + n = 8 + 3 = 11; Y = v + g = 11 + 5 = 16; so P = 1 + Y = 1 + 16 = 17. Define intense detective thriller in Rêves de Belleville as l; so l = 4. Define solemn period drama in Rêves de Belleville as D; m = d = 8; so D = 2 * m = 2 * 8 = 16. Define total number of movies in Rêves de Belleville as o; j = l + P = 4 + 17 = 21; so o = j + D = 21 + 16 = 37. Answer: 37.


The number of adult bear in Cedar Valley equals 4 plus the total number of adult animals in Maple Creek. The number of adult deer in Pine Ridge equals 2. The number of adult bear in Beverly Forest equals the sum of the total number of adult animals in Cedar Valley, the number of adult deer in Pine Ridge, the number of adult bear in Cedar Valley, and the number of adult wolf in Maple Creek. The number of adult racoon in Maple Creek equals 2. The number of adult wolf in Maple Creek equals the sum of the total number of adult animals in Pine Ridge and the number of adult deer in Pine Ridge.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult deer in Pine Ridge as P; so P = 2. Define total number of adult animals in Pine Ridge as H; so H = P = 2. Define adult wolf in Maple Creek as I; so I = H + P = 2 + 2 = 4. Define adult racoon in Maple Creek as b; so b = 2. Define total number of adult animals in Maple Creek as M; so M = b + I = 2 + 4 = 6. Define adult bear in Cedar Valley as s; K = M = 6; so s = 4 + K = 4 + 6 = 10. Define total number of adult animals in Cedar Valley as i; so i = s = 10. Define adult bear in Beverly Forest as G; r = i + P = 10 + 2 = 12; g = r + s = 12 + 10 = 22; so G = g + I = 22 + 4 = 26. Define total number of adult animals in Beverly Forest as O; so O = G = 26. Answer: 26.


The number of adult parrot in Cedar Valley equals 3 times the number of adult parrot in Maple Creek. The number of adult eagle in Pine Ridge equals 4 times the total number of adult animals in Cedar Valley. The number of adult parrot in Maple Creek equals 2. The number of adult owl in Cedar Valley equals the difference between the total number of adult animals in Maple Creek and the number of adult parrot in Maple Creek. The number of adult eagle in Maple Creek equals 4. The number of adult eagle in Cedar Valley equals 4.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult eagle in Maple Creek as o; so o = 4. Define adult parrot in Maple Creek as g; so g = 2. Define total number of adult animals in Maple Creek as i; so i = g + o = 2 + 4 = 6. Define adult owl in Cedar Valley as E; so E = i - g = 6 - 2 = 4. Define adult eagle in Cedar Valley as R; so R = 4. Define adult parrot in Cedar Valley as T; H = g = 2; so T = 3 * H = 3 * 2 = 6. Define total number of adult animals in Cedar Valley as J; f = T + E = 6 + 4 = 10; so J = f + R = 10 + 4 = 14. Define adult eagle in Pine Ridge as C; x = J = 14; so C = 4 * x = 4 * 14 = 56. Define total number of adult animals in Pine Ridge as q; so q = C = 56. Answer: 56.


The number of calm road movie in Verdi Movie Festival equals 1 plus the number of upbeat metropolis comedy in Northwood Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1 plus the number of solemn period drama in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 4. The number of solemn period drama in Northwood Movie Festival equals the difference between the number of calm road movie in Northwood Movie Festival and the number of upbeat metropolis comedy in Taylor Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 3. The number of solemn period drama in Verdi Movie Festival equals the sum of the number of upbeat metropolis comedy in Verdi Movie Festival, the number of intense detective thriller in Taylor Movie Festival, and the number of calm road movie in Taylor Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals the number of intense detective thriller in Northwood Movie Festival. The number of calm road movie in Taylor Movie Festival equals the number of upbeat metropolis comedy in Verdi Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the number of upbeat metropolis comedy in Verdi Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 3. The number of intense detective thriller in Northwood Movie Festival equals 4 times the number of upbeat metropolis comedy in Taylor Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 3. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of intense detective thriller in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals 4 times the number of intense detective thriller in Northwood Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the total number of movies in Northwood Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals the sum of the number of solemn period drama in Verdi Movie Festival, the number of intense detective thriller in Golden Banana Movie Festival, the number of intense detective thriller in Taylor Movie Festival, and the number of calm road movie in Taylor Movie Festival.

Question: How many calm road movie does Golden Banana Movie Festival have?

Solution: Define upbeat metropolis comedy in Taylor Movie Festival as C; so C = 4. Define intense detective thriller in Northwood Movie Festival as g; v = C = 4; so g = 4 * v = 4 * 4 = 16. Define solemn period drama in Golden Banana Movie Festival as x; so x = g = 16. Define calm road movie in Northwood Movie Festival as q; o = g = 16; so q = 4 * o = 4 * 16 = 64. Define upbeat metropolis comedy in Northwood Movie Festival as V; X = x = 16; so V = 1 + X = 1 + 16 = 17. Define solemn period drama in Northwood Movie Festival as H; so H = q - C = 64 - 4 = 60. Define total number of movies in Northwood Movie Festival as m; A = H + q = 60 + 64 = 124; Q = A + V = 124 + 17 = 141; so m = Q + g = 141 + 16 = 157. Define calm road movie in Golden Banana Movie Festival as L; so L = m = 157. Answer: 157.


The number of adult parrot in South Zoo equals 3. The number of adult blue jay in Hamilton Farm equals 2 times the difference between the total number of adult animals in Mayer Aquarium and the number of adult owl in South Zoo. The number of adult parrot in Hamilton Farm equals the number of adult crow in Bundle Ranch. The number of adult crow in Bundle Ranch equals 2 plus the number of adult owl in South Zoo. The number of adult parrot in Mayer Aquarium equals the sum of the number of adult parrot in Hamilton Farm, the number of adult owl in South Zoo, and the number of adult crow in Bundle Ranch. The number of adult owl in South Zoo equals 3 plus the number of adult parrot in South Zoo.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult parrot in South Zoo as X; so X = 3. Define adult owl in South Zoo as y; G = X = 3; so y = 3 + G = 3 + 3 = 6. Define adult crow in Bundle Ranch as E; F = y = 6; so E = 2 + F = 2 + 6 = 8. Define adult parrot in Hamilton Farm as o; so o = E = 8. Define adult parrot in Mayer Aquarium as t; O = o + y = 8 + 6 = 14; so t = O + E = 14 + 8 = 22. Define total number of adult animals in Mayer Aquarium as e; so e = t = 22. Define adult blue jay in Hamilton Farm as R; l = e - y = 22 - 6 = 16; so R = 2 * l = 2 * 16 = 32. Define total number of adult animals in Hamilton Farm as m; so m = o + R = 8 + 32 = 40. Answer: 40.


The number of calm road movie in Festival de Saint-Rivage equals 2 times the number of calm road movie in Festival Lumière de Valmont. The number of solemn period drama in Festival de Clairmont equals 1 plus the total number of movies in Festival de Saint-Rivage. The number of solemn period drama in Rêves de Belleville equals 2 plus the total number of movies in Festival de Clairmont. The number of calm road movie in Festival de Clairmont equals 2. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 3. The number of calm road movie in Festival Lumière de Valmont equals 4 times the sum of the number of futuristic sci-fi movie in Festival Lumière de Valmont and the number of calm road movie in Festival de Clairmont.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define calm road movie in Festival de Clairmont as d; so d = 2. Define futuristic sci-fi movie in Festival Lumière de Valmont as L; so L = 3. Define calm road movie in Festival Lumière de Valmont as T; k = L + d = 3 + 2 = 5; so T = 4 * k = 4 * 5 = 20. Define calm road movie in Festival de Saint-Rivage as j; g = T = 20; so j = 2 * g = 2 * 20 = 40. Define total number of movies in Festival de Saint-Rivage as P; so P = j = 40. Define solemn period drama in Festival de Clairmont as e; O = P = 40; so e = 1 + O = 1 + 40 = 41. Define total number of movies in Festival de Clairmont as m; so m = e + d = 41 + 2 = 43. Define solemn period drama in Rêves de Belleville as q; F = m = 43; so q = 2 + F = 2 + 43 = 45. Define total number of movies in Rêves de Belleville as w; so w = q = 45. Answer: 45.