The number of futuristic sci-fi movie in Cinéma de Montreval equals the sum of the number of solemn period drama in Cinéma de Montreval, the number of solemn period drama in Festival Lumière de Valmont, the number of futuristic sci-fi movie in Festival de Saint-Rivage, and the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Festival Lumière de Valmont equals the sum of the number of futuristic sci-fi movie in Festival de Saint-Rivage, the number of solemn period drama in Rêves de Belleville, and the number of upbeat metropolis comedy in Rêves de Belleville. The number of futuristic sci-fi movie in Rêves de Belleville equals 4 times the sum of the number of solemn period drama in Rêves de Belleville, the total number of movies in Festival de Saint-Rivage, and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of solemn period drama in Cinéma de Montreval equals 4 times the number of solemn period drama in Festival Lumière de Valmont. The number of solemn period drama in Rêves de Belleville equals 4. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 4. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 3 times the sum of the number of upbeat metropolis comedy in Rêves de Belleville and the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Festival de Saint-Rivage equals 2 plus the sum of the number of solemn period drama in Rêves de Belleville, the total number of movies in Festival de Saint-Rivage, and the number of upbeat metropolis comedy in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Rêves de Belleville equals 2 plus the number of solemn period drama in Rêves de Belleville.

Question: How many futuristic sci-fi movie does Cinéma de Montreval have?

Solution: Define solemn period drama in Rêves de Belleville as z; so z = 4. Define upbeat metropolis comedy in Rêves de Belleville as T; C = z = 4; so T = 2 + C = 2 + 4 = 6. Define futuristic sci-fi movie in Festival de Saint-Rivage as K; t = T + z = 6 + 4 = 10; so K = 3 * t = 3 * 10 = 30. Define solemn period drama in Festival Lumière de Valmont as J; Y = K + z = 30 + 4 = 34; so J = Y + T = 34 + 6 = 40. Define solemn period drama in Cinéma de Montreval as D; n = J = 40; so D = 4 * n = 4 * 40 = 160. Define futuristic sci-fi movie in Cinéma de Montreval as o; X = D + J = 160 + 40 = 200; i = X + K = 200 + 30 = 230; so o = i + z = 230 + 4 = 234. Answer: 234.


The number of solemn period drama in Rêves de Belleville equals 4. The number of intense detective thriller in Festival de Saint-Rivage equals the number of intense detective thriller in Festival de Clairmont. The number of futuristic sci-fi movie in Rêves de Belleville equals 3 plus the difference between the total number of movies in Festival de Clairmont and the number of intense detective thriller in Festival de Clairmont. The number of intense detective thriller in Festival de Clairmont equals 3 times the number of solemn period drama in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Clairmont equals the number of intense detective thriller in Festival de Clairmont. The number of intense detective thriller in Rêves de Belleville equals 1. The number of solemn period drama in Festival de Saint-Rivage equals 2 times the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of solemn period drama in Festival de Clairmont equals 4 times the number of intense detective thriller in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the number of intense detective thriller in Rêves de Belleville.

Question: How many futuristic sci-fi movie does Rêves de Belleville have?

Solution: Define intense detective thriller in Rêves de Belleville as w; so w = 1. Define futuristic sci-fi movie in Festival de Saint-Rivage as b; so b = w = 1. Define solemn period drama in Festival de Saint-Rivage as y; v = b = 1; so y = 2 * v = 2 * 1 = 2. Define intense detective thriller in Festival de Clairmont as m; t = y = 2; so m = 3 * t = 3 * 2 = 6. Define solemn period drama in Festival de Clairmont as Y; f = m = 6; so Y = 4 * f = 4 * 6 = 24. Define futuristic sci-fi movie in Festival de Clairmont as g; so g = m = 6. Define total number of movies in Festival de Clairmont as H; U = m + Y = 6 + 24 = 30; so H = U + g = 30 + 6 = 36. Define futuristic sci-fi movie in Rêves de Belleville as d; r = H - m = 36 - 6 = 30; so d = 3 + r = 3 + 30 = 33. Answer: 33.


The number of adult eagle in Bundle Ranch equals the number of adult eagle in Mayer Aquarium. The number of adult eagle in Mayer Aquarium equals 4. The number of adult eagle in Jefferson Circus equals 2 plus the number of adult owl in Jefferson Circus. The number of adult owl in Jefferson Circus equals the sum of the total number of adult animals in Mayer Aquarium and the number of adult eagle in Mayer Aquarium. The number of adult owl in Bundle Ranch equals the difference between the total number of adult animals in Jefferson Circus and the number of adult eagle in Mayer Aquarium. The number of adult owl in Mayer Aquarium equals 2.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult owl in Mayer Aquarium as M; so M = 2. Define adult eagle in Mayer Aquarium as R; so R = 4. Define total number of adult animals in Mayer Aquarium as Z; so Z = R + M = 4 + 2 = 6. Define adult owl in Jefferson Circus as s; so s = Z + R = 6 + 4 = 10. Define adult eagle in Jefferson Circus as f; P = s = 10; so f = 2 + P = 2 + 10 = 12. Define total number of adult animals in Jefferson Circus as i; so i = s + f = 10 + 12 = 22. Define adult owl in Bundle Ranch as L; so L = i - R = 22 - 4 = 18. Define adult eagle in Bundle Ranch as v; so v = R = 4. Define total number of adult animals in Bundle Ranch as X; so X = L + v = 18 + 4 = 22. Answer: 22.


The number of intense detective thriller in Festival de Clairmont equals 2 plus the number of solemn period drama in Festival de Clairmont. The number of solemn period drama in Festival de Clairmont equals 4. The number of intense detective thriller in Festival Lumière de Valmont equals 3 times the total number of movies in Cinéma de Montreval. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the difference between the total number of movies in Cinéma de Montreval and the number of intense detective thriller in Festival de Clairmont. The number of futuristic sci-fi movie in Cinéma de Montreval equals the total number of movies in Festival de Clairmont. The number of solemn period drama in Festival Lumière de Valmont equals 2.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define solemn period drama in Festival de Clairmont as N; so N = 4. Define intense detective thriller in Festival de Clairmont as Q; o = N = 4; so Q = 2 + o = 2 + 4 = 6. Define total number of movies in Festival de Clairmont as S; so S = N + Q = 4 + 6 = 10. Define futuristic sci-fi movie in Cinéma de Montreval as q; so q = S = 10. Define total number of movies in Cinéma de Montreval as U; so U = q = 10. Define solemn period drama in Festival Lumière de Valmont as P; so P = 2. Define intense detective thriller in Festival Lumière de Valmont as d; Z = U = 10; so d = 3 * Z = 3 * 10 = 30. Define futuristic sci-fi movie in Festival Lumière de Valmont as x; so x = U - Q = 10 - 6 = 4. Define total number of movies in Festival Lumière de Valmont as m; y = P + d = 2 + 30 = 32; so m = y + x = 32 + 4 = 36. Answer: 36.


The number of regional medical school in Evervale City equals 4. The number of regional medical school in Glenfield City equals 3 plus the total number of schools in Hawkesbury. The number of elementary school in Hawkesbury equals 3. The number of regional medical school in Hawkesbury equals 3 plus the sum of the number of private middle school in Hawkesbury and the number of elementary school in Hawkesbury. The number of private middle school in Evervale City equals the number of private middle school in Glenfield City. The number of private middle school in Hawkesbury equals 4. The number of elementary school in Glenfield City equals the number of elementary school in Hawkesbury. The number of private middle school in Glenfield City equals the total number of schools in Hawkesbury. The number of elementary school in Evervale City equals the number of regional medical school in Evervale City.

Question: What is the total number of schools in Glenfield City?

Solution: Define elementary school in Hawkesbury as w; so w = 3. Define private middle school in Hawkesbury as y; so y = 4. Define regional medical school in Hawkesbury as U; r = y + w = 4 + 3 = 7; so U = 3 + r = 3 + 7 = 10. Define total number of schools in Hawkesbury as D; K = w + U = 3 + 10 = 13; so D = K + y = 13 + 4 = 17. Define regional medical school in Glenfield City as R; q = D = 17; so R = 3 + q = 3 + 17 = 20. Define private middle school in Glenfield City as m; so m = D = 17. Define elementary school in Glenfield City as I; so I = w = 3. Define total number of schools in Glenfield City as N; i = I + R = 3 + 20 = 23; so N = i + m = 23 + 17 = 40. Answer: 40.


The number of adult parrot in Oakridge Riverside equals the number of adult owl in Beverly Forest. The number of adult crow in Cedar Valley equals the difference between the number of adult owl in Maple Creek and the total number of adult animals in Beverly Forest. The number of adult eagle in Oakridge Riverside equals 4 plus the number of adult parrot in Oakridge Riverside. The number of adult crow in Maple Creek equals the number of adult eagle in Pine Ridge. The number of adult owl in Beverly Forest equals 2. The number of adult parrot in Pine Ridge equals the total number of adult animals in Beverly Forest. The number of adult owl in Cedar Valley equals 3 times the sum of the number of adult blue jay in Beverly Forest, the number of adult eagle in Oakridge Riverside, and the number of adult parrot in Oakridge Riverside. The number of adult owl in Maple Creek equals 3 plus the number of adult owl in Cedar Valley. The number of adult parrot in Maple Creek equals 2. The number of adult eagle in Pine Ridge equals the number of adult parrot in Maple Creek. The number of adult blue jay in Maple Creek equals 2. The number of adult blue jay in Beverly Forest equals the sum of the total number of adult animals in Oakridge Riverside, the number of adult eagle in Oakridge Riverside, and the number of adult parrot in Oakridge Riverside.

Question: How many adult owl does Maple Creek have?

Solution: Define adult owl in Beverly Forest as A; so A = 2. Define adult parrot in Oakridge Riverside as B; so B = A = 2. Define adult eagle in Oakridge Riverside as N; U = B = 2; so N = 4 + U = 4 + 2 = 6. Define total number of adult animals in Oakridge Riverside as K; so K = B + N = 2 + 6 = 8. Define adult blue jay in Beverly Forest as m; f = K + N = 8 + 6 = 14; so m = f + B = 14 + 2 = 16. Define adult owl in Cedar Valley as V; w = m + N = 16 + 6 = 22; z = w + B = 22 + 2 = 24; so V = 3 * z = 3 * 24 = 72. Define adult owl in Maple Creek as n; a = V = 72; so n = 3 + a = 3 + 72 = 75. Answer: 75.


The number of adult wolf in Oakridge Riverside equals the number of adult deer in Beverly Forest. The number of adult deer in Beverly Forest equals 3 plus the number of adult wolf in Beverly Forest. The number of adult deer in Oakridge Riverside equals 2 times the total number of adult animals in Beverly Forest. The number of adult fox in Maple Creek equals the total number of adult animals in Oakridge Riverside. The number of adult wolf in Beverly Forest equals 4. The number of adult fox in Oakridge Riverside equals the sum of the number of adult deer in Oakridge Riverside and the total number of adult animals in Beverly Forest.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult wolf in Beverly Forest as d; so d = 4. Define adult deer in Beverly Forest as l; A = d = 4; so l = 3 + A = 3 + 4 = 7. Define total number of adult animals in Beverly Forest as P; so P = l + d = 7 + 4 = 11. Define adult deer in Oakridge Riverside as k; u = P = 11; so k = 2 * u = 2 * 11 = 22. Define adult fox in Oakridge Riverside as B; so B = k + P = 22 + 11 = 33. Define adult wolf in Oakridge Riverside as T; so T = l = 7. Define total number of adult animals in Oakridge Riverside as D; n = k + B = 22 + 33 = 55; so D = n + T = 55 + 7 = 62. Define adult fox in Maple Creek as I; so I = D = 62. Define total number of adult animals in Maple Creek as s; so s = I = 62. Answer: 62.


The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 3 times the number of calm road movie in Festival Lumière de Valmont. The number of intense detective thriller in Cinéma de Montreval equals 3. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the sum of the number of intense detective thriller in Festival de Saint-Rivage and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of calm road movie in Cinéma de Montreval equals 4 plus the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Festival de Saint-Rivage equals 4. The number of upbeat metropolis comedy in Cinéma de Montreval equals the difference between the number of intense detective thriller in Festival de Saint-Rivage and the number of calm road movie in Cinéma de Montreval. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 3 times the total number of movies in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the number of intense detective thriller in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Cinéma de Montreval equals the difference between the number of calm road movie in Cinéma de Montreval and the number of intense detective thriller in Cinéma de Montreval. The number of calm road movie in Festival Lumière de Valmont equals 1.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define intense detective thriller in Festival de Saint-Rivage as o; so o = 4. Define futuristic sci-fi movie in Festival de Saint-Rivage as C; so C = o = 4. Define upbeat metropolis comedy in Festival de Saint-Rivage as T; so T = o + C = 4 + 4 = 8. Define total number of movies in Festival de Saint-Rivage as h; E = T + o = 8 + 4 = 12; so h = E + C = 12 + 4 = 16. Define futuristic sci-fi movie in Festival Lumière de Valmont as q; d = h = 16; so q = 3 * d = 3 * 16 = 48. Define calm road movie in Festival Lumière de Valmont as V; so V = 1. Define upbeat metropolis comedy in Festival Lumière de Valmont as g; v = V = 1; so g = 3 * v = 3 * 1 = 3. Define total number of movies in Festival Lumière de Valmont as a; f = g + V = 3 + 1 = 4; so a = f + q = 4 + 48 = 52. Answer: 52.


The number of adult parrot in Cedar Valley equals 4 plus the difference between the total number of adult animals in Maple Creek and the number of adult owl in Maple Creek. The number of adult owl in Maple Creek equals 3. The number of adult owl in Pine Ridge equals 2. The number of adult eagle in Pine Ridge equals 1 plus the total number of adult animals in Cedar Valley. The number of adult parrot in Pine Ridge equals the number of adult owl in Maple Creek. The number of adult eagle in Maple Creek equals 3.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult owl in Maple Creek as O; so O = 3. Define adult eagle in Maple Creek as D; so D = 3. Define total number of adult animals in Maple Creek as L; so L = D + O = 3 + 3 = 6. Define adult parrot in Cedar Valley as G; l = L - O = 6 - 3 = 3; so G = 4 + l = 4 + 3 = 7. Define total number of adult animals in Cedar Valley as t; so t = G = 7. Define adult eagle in Pine Ridge as i; v = t = 7; so i = 1 + v = 1 + 7 = 8. Define adult parrot in Pine Ridge as m; so m = O = 3. Define adult owl in Pine Ridge as e; so e = 2. Define total number of adult animals in Pine Ridge as u; W = i + m = 8 + 3 = 11; so u = W + e = 11 + 2 = 13. Answer: 13.


The number of private middle school in Shoreline City equals 1 plus the difference between the total number of schools in Riverton City and the number of regional medical school in Riverton City. The number of regional medical school in Ruby Bay equals the number of culinarian school in Oakbridge City. The number of regional medical school in Oakbridge City equals the difference between the total number of schools in Oakbridge City and the number of culinarian school in Oakbridge City. The number of regional medical school in Shoreline City equals 2 times the difference between the number of public highschool in Ruby Bay and the number of public highschool in Oakbridge City. The number of regional medical school in Riverton City equals the number of public highschool in Shoreline City. The number of private middle school in Oakbridge City equals the number of regional medical school in Shoreline City. The number of public highschool in Riverton City equals the sum of the number of private middle school in Riverton City, the number of public highschool in Shoreline City, and the number of regional medical school in Riverton City. The number of private middle school in Riverton City equals 4 times the number of regional medical school in Riverton City. The number of public highschool in Ruby Bay equals 4 times the number of culinarian school in Shoreline City. The number of culinarian school in Riverton City equals the number of private middle school in Riverton City. The number of private middle school in Ruby Bay equals 4 plus the number of public highschool in Riverton City. The number of public highschool in Shoreline City equals 3. The number of culinarian school in Shoreline City equals 4. The number of public highschool in Oakbridge City equals 4. The number of culinarian school in Oakbridge City equals 3 times the difference between the number of regional medical school in Shoreline City and the number of public highschool in Ruby Bay.

Question: How many private middle school does Shoreline City have?

Solution: Define public highschool in Shoreline City as o; so o = 3. Define regional medical school in Riverton City as Y; so Y = o = 3. Define private middle school in Riverton City as r; m = Y = 3; so r = 4 * m = 4 * 3 = 12. Define public highschool in Riverton City as j; U = r + o = 12 + 3 = 15; so j = U + Y = 15 + 3 = 18. Define culinarian school in Riverton City as h; so h = r = 12. Define total number of schools in Riverton City as y; V = h + r = 12 + 12 = 24; b = V + j = 24 + 18 = 42; so y = b + Y = 42 + 3 = 45. Define private middle school in Shoreline City as t; A = y - Y = 45 - 3 = 42; so t = 1 + A = 1 + 42 = 43. Answer: 43.


The number of intense detective thriller in Cinéma de Montreval equals 1 plus the number of calm road movie in Festival Lumière de Valmont. The number of solemn period drama in Rêves de Belleville equals the sum of the number of calm road movie in Festival Lumière de Valmont, the total number of movies in Rêves de Belleville, the number of calm road movie in Cinéma de Montreval, and the number of upbeat metropolis comedy in Cinéma de Montreval. The number of intense detective thriller in Festival Lumière de Valmont equals the number of calm road movie in Cinéma de Montreval. The number of intense detective thriller in Rêves de Belleville equals the sum of the number of upbeat metropolis comedy in Cinéma de Montreval, the number of calm road movie in Cinéma de Montreval, and the number of solemn period drama in Cinéma de Montreval. The number of calm road movie in Rêves de Belleville equals 4. The number of intense detective thriller in Festival de Clairmont equals 4. The number of calm road movie in Festival Lumière de Valmont equals 3. The number of calm road movie in Festival de Clairmont equals 2. The number of upbeat metropolis comedy in Festival de Clairmont equals the number of intense detective thriller in Festival de Clairmont. The number of upbeat metropolis comedy in Cinéma de Montreval equals 1 plus the number of intense detective thriller in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the number of solemn period drama in Festival de Clairmont. The number of calm road movie in Cinéma de Montreval equals the sum of the number of calm road movie in Festival Lumière de Valmont, the number of intense detective thriller in Cinéma de Montreval, and the number of upbeat metropolis comedy in Cinéma de Montreval. The number of upbeat metropolis comedy in Rêves de Belleville equals 2. The number of solemn period drama in Festival de Clairmont equals 1 plus the number of intense detective thriller in Festival de Clairmont. The number of solemn period drama in Cinéma de Montreval equals 2 times the sum of the number of calm road movie in Cinéma de Montreval and the number of calm road movie in Festival Lumière de Valmont.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define calm road movie in Festival Lumière de Valmont as R; so R = 3. Define intense detective thriller in Cinéma de Montreval as M; J = R = 3; so M = 1 + J = 1 + 3 = 4. Define upbeat metropolis comedy in Cinéma de Montreval as N; b = M = 4; so N = 1 + b = 1 + 4 = 5. Define calm road movie in Cinéma de Montreval as Q; Z = R + M = 3 + 4 = 7; so Q = Z + N = 7 + 5 = 12. Define solemn period drama in Cinéma de Montreval as K; V = Q + R = 12 + 3 = 15; so K = 2 * V = 2 * 15 = 30. Define total number of movies in Cinéma de Montreval as j; E = K + N = 30 + 5 = 35; F = E + M = 35 + 4 = 39; so j = F + Q = 39 + 12 = 51. Answer: 51.


The number of public highschool in Brightford equals 3 times the number of culinarian school in Glenfield City. The number of private middle school in Hawkesbury equals the number of regional medical school in Westhaven City. The number of elementary school in Westhaven City equals 3. The number of regional medical school in Westhaven City equals 4 times the sum of the number of public highschool in Westhaven City and the number of elementary school in Westhaven City. The number of public highschool in Westhaven City equals 4. The number of elementary school in Glenfield City equals the sum of the number of culinarian school in Evervale City, the total number of schools in Westhaven City, and the number of elementary school in Westhaven City. The number of regional medical school in Brightford equals 1. The number of culinarian school in Glenfield City equals 4. The number of culinarian school in Evervale City equals the total number of schools in Hawkesbury. The number of elementary school in Hawkesbury equals 3 times the total number of schools in Westhaven City.

Question: What is the total number of schools in Evervale City?

Solution: Define elementary school in Westhaven City as b; so b = 3. Define public highschool in Westhaven City as K; so K = 4. Define regional medical school in Westhaven City as o; n = K + b = 4 + 3 = 7; so o = 4 * n = 4 * 7 = 28. Define total number of schools in Westhaven City as T; Q = K + o = 4 + 28 = 32; so T = Q + b = 32 + 3 = 35. Define elementary school in Hawkesbury as B; P = T = 35; so B = 3 * P = 3 * 35 = 105. Define private middle school in Hawkesbury as Y; so Y = o = 28. Define total number of schools in Hawkesbury as S; so S = Y + B = 28 + 105 = 133. Define culinarian school in Evervale City as H; so H = S = 133. Define total number of schools in Evervale City as u; so u = H = 133. Answer: 133.


The number of adult fox in Jefferson Circus equals the sum of the total number of adult animals in Hamilton Farm and the total number of adult animals in Mayer Aquarium. The number of adult deer in Hamilton Farm equals the total number of adult animals in Mayer Aquarium. The number of adult wolf in Mayer Aquarium equals 2. The number of adult racoon in South Zoo equals the total number of adult animals in Jefferson Circus. The number of adult bear in Jefferson Circus equals the total number of adult animals in Hamilton Farm. The number of adult wolf in Jefferson Circus equals the number of adult fox in Jefferson Circus. The number of adult racoon in Hamilton Farm equals the total number of adult animals in Mayer Aquarium.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult wolf in Mayer Aquarium as y; so y = 2. Define total number of adult animals in Mayer Aquarium as U; so U = y = 2. Define adult racoon in Hamilton Farm as D; so D = U = 2. Define adult deer in Hamilton Farm as V; so V = U = 2. Define total number of adult animals in Hamilton Farm as w; so w = V + D = 2 + 2 = 4. Define adult fox in Jefferson Circus as c; so c = w + U = 4 + 2 = 6. Define adult wolf in Jefferson Circus as X; so X = c = 6. Define adult bear in Jefferson Circus as I; so I = w = 4. Define total number of adult animals in Jefferson Circus as Q; n = X + I = 6 + 4 = 10; so Q = n + c = 10 + 6 = 16. Define adult racoon in South Zoo as Y; so Y = Q = 16. Define total number of adult animals in South Zoo as i; so i = Y = 16. Answer: 16.


The number of adult fox in South Zoo equals the sum of the number of adult deer in South Zoo and the number of adult bear in South Zoo. The number of adult bear in South Zoo equals 2. The number of adult wolf in Hamilton Farm equals the number of adult wolf in South Zoo. The number of adult wolf in South Zoo equals the number of adult deer in South Zoo. The number of adult deer in South Zoo equals 3. The number of adult deer in Hamilton Farm equals the total number of adult animals in South Zoo. The number of adult bear in Hamilton Farm equals the number of adult deer in South Zoo.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult deer in South Zoo as p; so p = 3. Define adult bear in South Zoo as E; so E = 2. Define adult wolf in South Zoo as Z; so Z = p = 3. Define adult fox in South Zoo as L; so L = p + E = 3 + 2 = 5. Define total number of adult animals in South Zoo as K; y = Z + L = 3 + 5 = 8; S = y + p = 8 + 3 = 11; so K = S + E = 11 + 2 = 13. Define adult deer in Hamilton Farm as t; so t = K = 13. Define adult bear in Hamilton Farm as n; so n = p = 3. Define adult wolf in Hamilton Farm as a; so a = Z = 3. Define total number of adult animals in Hamilton Farm as r; d = a + t = 3 + 13 = 16; so r = d + n = 16 + 3 = 19. Answer: 19.


The number of calm road movie in Festival de Saint-Rivage equals the sum of the number of solemn period drama in Festival de Clairmont and the total number of movies in Cinéma de Montreval. The number of upbeat metropolis comedy in Cinéma de Montreval equals the number of calm road movie in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the sum of the total number of movies in Cinéma de Montreval, the number of solemn period drama in Cinéma de Montreval, and the number of calm road movie in Cinéma de Montreval. The number of calm road movie in Festival de Clairmont equals the sum of the number of upbeat metropolis comedy in Festival de Saint-Rivage, the total number of movies in Festival de Saint-Rivage, and the number of solemn period drama in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival de Clairmont equals 3. The number of solemn period drama in Cinéma de Montreval equals 2 plus the sum of the number of calm road movie in Cinéma de Montreval and the number of upbeat metropolis comedy in Cinéma de Montreval. The number of solemn period drama in Festival de Saint-Rivage equals 4 plus the sum of the number of upbeat metropolis comedy in Festival de Saint-Rivage, the number of calm road movie in Cinéma de Montreval, and the total number of movies in Cinéma de Montreval. The number of solemn period drama in Festival de Clairmont equals the sum of the number of upbeat metropolis comedy in Cinéma de Montreval and the number of calm road movie in Cinéma de Montreval. The number of calm road movie in Cinéma de Montreval equals 3.

Question: How many solemn period drama does Festival de Saint-Rivage have?

Solution: Define calm road movie in Cinéma de Montreval as P; so P = 3. Define upbeat metropolis comedy in Cinéma de Montreval as I; so I = P = 3. Define solemn period drama in Cinéma de Montreval as g; Y = P + I = 3 + 3 = 6; so g = 2 + Y = 2 + 6 = 8. Define total number of movies in Cinéma de Montreval as h; a = P + I = 3 + 3 = 6; so h = a + g = 6 + 8 = 14. Define upbeat metropolis comedy in Festival de Saint-Rivage as l; n = h + g = 14 + 8 = 22; so l = n + P = 22 + 3 = 25. Define solemn period drama in Festival de Saint-Rivage as Q; y = l + P = 25 + 3 = 28; f = y + h = 28 + 14 = 42; so Q = 4 + f = 4 + 42 = 46. Answer: 46.


The number of regional medical school in Westhaven City equals 2 plus the number of private middle school in Brightford. The number of private middle school in Brightford equals 3 times the number of public highschool in Westhaven City. The number of regional medical school in Brightford equals 3 plus the number of regional medical school in Westhaven City. The number of public highschool in Westhaven City equals 4. The number of private middle school in Westhaven City equals 4 times the sum of the total number of schools in Brightford and the number of public highschool in Westhaven City. The number of public highschool in Brightford equals the sum of the number of regional medical school in Westhaven City and the number of public highschool in Westhaven City.

Question: How many private middle school does Westhaven City have?

Solution: Define public highschool in Westhaven City as g; so g = 4. Define private middle school in Brightford as I; q = g = 4; so I = 3 * q = 3 * 4 = 12. Define regional medical school in Westhaven City as h; Y = I = 12; so h = 2 + Y = 2 + 12 = 14. Define regional medical school in Brightford as z; A = h = 14; so z = 3 + A = 3 + 14 = 17. Define public highschool in Brightford as i; so i = h + g = 14 + 4 = 18. Define total number of schools in Brightford as T; E = i + z = 18 + 17 = 35; so T = E + I = 35 + 12 = 47. Define private middle school in Westhaven City as Z; D = T + g = 47 + 4 = 51; so Z = 4 * D = 4 * 51 = 204. Answer: 204.


The number of private middle school in Ruby Bay equals 2 plus the sum of the total number of schools in Shoreline City, the number of public highschool in Clearwater Bay, and the total number of schools in Clearwater Bay. The number of public highschool in Shoreline City equals the number of public highschool in Clearwater Bay. The number of culinarian school in Ruby Bay equals 2. The number of culinarian school in Shoreline City equals 1 plus the difference between the total number of schools in Clearwater Bay and the number of public highschool in Clearwater Bay. The number of public highschool in Clearwater Bay equals 1.

Question: What is the total number of schools in Ruby Bay?

Solution: Define public highschool in Clearwater Bay as e; so e = 1. Define total number of schools in Clearwater Bay as Z; so Z = e = 1. Define culinarian school in Shoreline City as Q; p = Z - e = 1 - 1 = 0; so Q = 1 + p = 1 + 0 = 1. Define public highschool in Shoreline City as N; so N = e = 1. Define total number of schools in Shoreline City as R; so R = N + Q = 1 + 1 = 2. Define private middle school in Ruby Bay as D; E = R + e = 2 + 1 = 3; y = E + Z = 3 + 1 = 4; so D = 2 + y = 2 + 4 = 6. Define culinarian school in Ruby Bay as x; so x = 2. Define total number of schools in Ruby Bay as J; so J = D + x = 6 + 2 = 8. Answer: 8.


The number of adult crow in Jefferson Circus equals 2. The number of adult owl in Hamilton Farm equals the sum of the total number of adult animals in Jefferson Circus and the number of adult owl in Jefferson Circus. The number of adult crow in Hamilton Farm equals 3 times the sum of the number of adult crow in Jefferson Circus and the number of adult owl in Jefferson Circus. The number of adult owl in Jefferson Circus equals the number of adult crow in Jefferson Circus. The number of adult crow in Mayer Aquarium equals 4 plus the difference between the total number of adult animals in Hamilton Farm and the number of adult owl in Hamilton Farm.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult crow in Jefferson Circus as b; so b = 2. Define adult owl in Jefferson Circus as C; so C = b = 2. Define total number of adult animals in Jefferson Circus as e; so e = C + b = 2 + 2 = 4. Define adult owl in Hamilton Farm as n; so n = e + C = 4 + 2 = 6. Define adult crow in Hamilton Farm as m; W = b + C = 2 + 2 = 4; so m = 3 * W = 3 * 4 = 12. Define total number of adult animals in Hamilton Farm as U; so U = n + m = 6 + 12 = 18. Define adult crow in Mayer Aquarium as d; X = U - n = 18 - 6 = 12; so d = 4 + X = 4 + 12 = 16. Define total number of adult animals in Mayer Aquarium as l; so l = d = 16. Answer: 16.