The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the total number of movies in Cinéma de Montreval. The number of solemn period drama in Festival de Clairmont equals 3 times the total number of movies in Cinéma de Montreval. The number of futuristic sci-fi movie in Cinéma de Montreval equals 3. The number of futuristic sci-fi movie in Festival de Clairmont equals 4 times the number of futuristic sci-fi movie in Cinéma de Montreval. The number of calm road movie in Cinéma de Montreval equals the number of futuristic sci-fi movie in Cinéma de Montreval. The number of solemn period drama in Festival de Saint-Rivage equals 4 plus the total number of movies in Festival de Clairmont.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define futuristic sci-fi movie in Cinéma de Montreval as q; so q = 3. Define calm road movie in Cinéma de Montreval as W; so W = q = 3. Define futuristic sci-fi movie in Festival de Clairmont as e; b = q = 3; so e = 4 * b = 4 * 3 = 12. Define total number of movies in Cinéma de Montreval as r; so r = W + q = 3 + 3 = 6. Define solemn period drama in Festival de Clairmont as B; p = r = 6; so B = 3 * p = 3 * 6 = 18. Define total number of movies in Festival de Clairmont as v; so v = e + B = 12 + 18 = 30. Define solemn period drama in Festival de Saint-Rivage as O; k = v = 30; so O = 4 + k = 4 + 30 = 34. Define futuristic sci-fi movie in Festival de Saint-Rivage as d; so d = r = 6. Define total number of movies in Festival de Saint-Rivage as T; so T = d + O = 6 + 34 = 40. Answer: 40.


The number of adult parrot in Pine Ridge equals 4. The number of adult parrot in Beverly Forest equals 4 times the sum of the number of adult blue jay in Pine Ridge, the number of adult parrot in Pine Ridge, and the number of adult blue jay in Beverly Forest. The number of adult blue jay in Pine Ridge equals the sum of the number of adult crow in Oakridge Riverside, the number of adult parrot in Oakridge Riverside, and the number of adult parrot in Pine Ridge. The number of adult crow in Pine Ridge equals 3. The number of adult blue jay in Beverly Forest equals 1 plus the sum of the number of adult parrot in Oakridge Riverside and the number of adult parrot in Pine Ridge. The number of adult crow in Oakridge Riverside equals 1 plus the number of adult blue jay in Beverly Forest. The number of adult parrot in Oakridge Riverside equals 1 plus the number of adult parrot in Pine Ridge.

Question: How many adult parrot does Beverly Forest have?

Solution: Define adult parrot in Pine Ridge as n; so n = 4. Define adult parrot in Oakridge Riverside as I; J = n = 4; so I = 1 + J = 1 + 4 = 5. Define adult blue jay in Beverly Forest as b; k = I + n = 5 + 4 = 9; so b = 1 + k = 1 + 9 = 10. Define adult crow in Oakridge Riverside as T; l = b = 10; so T = 1 + l = 1 + 10 = 11. Define adult blue jay in Pine Ridge as X; s = T + I = 11 + 5 = 16; so X = s + n = 16 + 4 = 20. Define adult parrot in Beverly Forest as a; r = X + n = 20 + 4 = 24; L = r + b = 24 + 10 = 34; so a = 4 * L = 4 * 34 = 136. Answer: 136.


The number of adult blue jay in Beverly Forest equals 2 times the number of adult eagle in Cedar Valley. The number of adult eagle in Cedar Valley equals 2 times the total number of adult animals in Maple Creek. The number of adult eagle in Beverly Forest equals 2 plus the number of adult eagle in Cedar Valley. The number of adult blue jay in Maple Creek equals 1. The number of adult owl in Cedar Valley equals 4. The number of adult owl in Beverly Forest equals the total number of adult animals in Cedar Valley.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult blue jay in Maple Creek as G; so G = 1. Define total number of adult animals in Maple Creek as R; so R = G = 1. Define adult eagle in Cedar Valley as a; c = R = 1; so a = 2 * c = 2 * 1 = 2. Define adult owl in Cedar Valley as h; so h = 4. Define total number of adult animals in Cedar Valley as v; so v = a + h = 2 + 4 = 6. Define adult owl in Beverly Forest as r; so r = v = 6. Define adult eagle in Beverly Forest as I; e = a = 2; so I = 2 + e = 2 + 2 = 4. Define adult blue jay in Beverly Forest as z; l = a = 2; so z = 2 * l = 2 * 2 = 4. Define total number of adult animals in Beverly Forest as x; B = I + r = 4 + 6 = 10; so x = B + z = 10 + 4 = 14. Answer: 14.


The number of elementary school in Glenfield City equals 3 plus the number of elementary school in Hawkesbury. The number of culinarian school in Westhaven City equals 3 times the number of private middle school in Hawkesbury. The number of culinarian school in Hawkesbury equals the number of private middle school in Hawkesbury. The number of private middle school in Glenfield City equals the number of private middle school in Hawkesbury. The number of elementary school in Hawkesbury equals 3. The number of private middle school in Brightford equals 3 plus the number of elementary school in Westhaven City. The number of elementary school in Westhaven City equals the difference between the number of elementary school in Glenfield City and the number of elementary school in Hawkesbury. The number of elementary school in Brightford equals 2. The number of culinarian school in Brightford equals the sum of the number of elementary school in Brightford, the number of elementary school in Hawkesbury, the number of elementary school in Glenfield City, and the number of private middle school in Brightford. The number of culinarian school in Glenfield City equals 3. The number of private middle school in Westhaven City equals 2. The number of private middle school in Hawkesbury equals 2.

Question: What is the total number of schools in Brightford?

Solution: Define elementary school in Hawkesbury as P; so P = 3. Define elementary school in Glenfield City as V; d = P = 3; so V = 3 + d = 3 + 3 = 6. Define elementary school in Westhaven City as r; so r = V - P = 6 - 3 = 3. Define private middle school in Brightford as m; k = r = 3; so m = 3 + k = 3 + 3 = 6. Define elementary school in Brightford as N; so N = 2. Define culinarian school in Brightford as h; B = N + P = 2 + 3 = 5; C = B + V = 5 + 6 = 11; so h = C + m = 11 + 6 = 17. Define total number of schools in Brightford as v; R = N + h = 2 + 17 = 19; so v = R + m = 19 + 6 = 25. Answer: 25.


The number of regional medical school in Glenfield City equals the number of private middle school in Evervale City. The number of regional medical school in Brightford equals 3. The number of private middle school in Evervale City equals 2 times the sum of the total number of schools in Brightford and the number of regional medical school in Brightford. The number of regional medical school in Evervale City equals 2 plus the number of private middle school in Evervale City. The number of public highschool in Glenfield City equals 1 plus the sum of the total number of schools in Evervale City and the number of regional medical school in Brightford.

Question: What is the total number of schools in Glenfield City?

Solution: Define regional medical school in Brightford as g; so g = 3. Define total number of schools in Brightford as M; so M = g = 3. Define private middle school in Evervale City as A; C = M + g = 3 + 3 = 6; so A = 2 * C = 2 * 6 = 12. Define regional medical school in Evervale City as N; H = A = 12; so N = 2 + H = 2 + 12 = 14. Define total number of schools in Evervale City as l; so l = A + N = 12 + 14 = 26. Define public highschool in Glenfield City as w; p = l + g = 26 + 3 = 29; so w = 1 + p = 1 + 29 = 30. Define regional medical school in Glenfield City as F; so F = A = 12. Define total number of schools in Glenfield City as P; so P = w + F = 30 + 12 = 42. Answer: 42.


The number of calm road movie in Festival de Clairmont equals the number of solemn period drama in Festival de Saint-Rivage. The number of solemn period drama in Festival de Saint-Rivage equals 1. The number of calm road movie in Rêves de Belleville equals 4 times the difference between the total number of movies in Festival de Saint-Rivage and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of solemn period drama in Festival de Clairmont equals 3 times the total number of movies in Rêves de Belleville. The number of intense detective thriller in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the number of solemn period drama in Festival de Saint-Rivage.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define solemn period drama in Festival de Saint-Rivage as P; so P = 1. Define futuristic sci-fi movie in Festival de Saint-Rivage as A; so A = P = 1. Define intense detective thriller in Festival de Saint-Rivage as n; so n = A = 1. Define total number of movies in Festival de Saint-Rivage as O; r = P + n = 1 + 1 = 2; so O = r + A = 2 + 1 = 3. Define calm road movie in Rêves de Belleville as C; c = O - A = 3 - 1 = 2; so C = 4 * c = 4 * 2 = 8. Define total number of movies in Rêves de Belleville as K; so K = C = 8. Define calm road movie in Festival de Clairmont as f; so f = P = 1. Define solemn period drama in Festival de Clairmont as U; X = K = 8; so U = 3 * X = 3 * 8 = 24. Define total number of movies in Festival de Clairmont as p; so p = U + f = 24 + 1 = 25. Answer: 25.