The number of adult fox in South Zoo equals 1 plus the difference between the total number of adult animals in Bundle Ranch and the number of adult bear in Bundle Ranch. The number of adult bear in Bundle Ranch equals 3. The number of adult fox in Bundle Ranch equals the number of adult bear in Bundle Ranch. The number of adult bear in South Zoo equals the number of adult fox in South Zoo.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult bear in Bundle Ranch as P; so P = 3. Define adult fox in Bundle Ranch as f; so f = P = 3. Define total number of adult animals in Bundle Ranch as X; so X = f + P = 3 + 3 = 6. Define adult fox in South Zoo as j; L = X - P = 6 - 3 = 3; so j = 1 + L = 1 + 3 = 4. Define adult bear in South Zoo as R; so R = j = 4. Define total number of adult animals in South Zoo as K; so K = j + R = 4 + 4 = 8. Answer: 8.


The number of upbeat metropolis comedy in Festival de Clairmont equals the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Rêves de Belleville equals 1 plus the number of calm road movie in Rêves de Belleville. The number of solemn period drama in Festival de Clairmont equals the difference between the total number of movies in Rêves de Belleville and the number of solemn period drama in Rêves de Belleville. The number of calm road movie in Rêves de Belleville equals 4. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2. The number of calm road movie in Festival de Saint-Rivage equals 3.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define calm road movie in Rêves de Belleville as b; so b = 4. Define solemn period drama in Rêves de Belleville as D; A = b = 4; so D = 1 + A = 1 + 4 = 5. Define total number of movies in Rêves de Belleville as O; so O = D + b = 5 + 4 = 9. Define solemn period drama in Festival de Clairmont as L; so L = O - D = 9 - 5 = 4. Define upbeat metropolis comedy in Festival de Clairmont as F; so F = D = 5. Define total number of movies in Festival de Clairmont as l; so l = L + F = 4 + 5 = 9. Answer: 9.


The number of adult racoon in South Zoo equals the number of adult fox in South Zoo. The number of adult bear in Hamilton Farm equals the number of adult racoon in South Zoo. The number of adult deer in Hamilton Farm equals 2 times the sum of the number of adult racoon in Hamilton Farm and the number of adult fox in South Zoo. The number of adult deer in South Zoo equals the difference between the number of adult deer in Mayer Aquarium and the number of adult bear in Hamilton Farm. The number of adult racoon in Hamilton Farm equals the number of adult fox in South Zoo. The number of adult deer in Bundle Ranch equals 3 plus the number of adult fox in Bundle Ranch. The number of adult fox in Mayer Aquarium equals 2. The number of adult fox in Bundle Ranch equals 4. The number of adult bear in South Zoo equals 1 plus the sum of the number of adult racoon in Mayer Aquarium and the number of adult deer in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 3. The number of adult fox in Hamilton Farm equals the number of adult bear in Mayer Aquarium. The number of adult bear in Mayer Aquarium equals 4. The number of adult racoon in Mayer Aquarium equals 3 times the difference between the number of adult bear in Bundle Ranch and the number of adult racoon in Bundle Ranch. The number of adult fox in South Zoo equals 3. The number of adult bear in Bundle Ranch equals the sum of the number of adult racoon in Bundle Ranch and the number of adult fox in Bundle Ranch. The number of adult racoon in Bundle Ranch equals 4.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult fox in Bundle Ranch as o; so o = 4. Define adult racoon in Bundle Ranch as I; so I = 4. Define adult bear in Bundle Ranch as q; so q = I + o = 4 + 4 = 8. Define adult deer in Bundle Ranch as w; h = o = 4; so w = 3 + h = 3 + 4 = 7. Define total number of adult animals in Bundle Ranch as B; L = q + o = 8 + 4 = 12; A = L + w = 12 + 7 = 19; so B = A + I = 19 + 4 = 23. Answer: 23.


The number of futuristic sci-fi movie in Cinéma de Montreval equals 2. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 3 plus the total number of movies in Cinéma de Montreval. The number of calm road movie in Festival de Saint-Rivage equals 2 plus the sum of the number of futuristic sci-fi movie in Festival de Saint-Rivage, the number of futuristic sci-fi movie in Cinéma de Montreval, and the total number of movies in Cinéma de Montreval.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define futuristic sci-fi movie in Cinéma de Montreval as u; so u = 2. Define total number of movies in Cinéma de Montreval as b; so b = u = 2. Define futuristic sci-fi movie in Festival de Saint-Rivage as O; w = b = 2; so O = 3 + w = 3 + 2 = 5. Define calm road movie in Festival de Saint-Rivage as m; W = O + u = 5 + 2 = 7; I = W + b = 7 + 2 = 9; so m = 2 + I = 2 + 9 = 11. Define total number of movies in Festival de Saint-Rivage as k; so k = O + m = 5 + 11 = 16. Answer: 16.


The number of adult deer in Oakridge Riverside equals the sum of the total number of adult animals in Cedar Valley and the number of adult deer in Cedar Valley. The number of adult racoon in Oakridge Riverside equals the total number of adult animals in Cedar Valley. The number of adult racoon in Cedar Valley equals 4. The number of adult deer in Cedar Valley equals 1 plus the number of adult racoon in Cedar Valley.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult racoon in Cedar Valley as w; so w = 4. Define adult deer in Cedar Valley as j; Q = w = 4; so j = 1 + Q = 1 + 4 = 5. Define total number of adult animals in Cedar Valley as G; so G = w + j = 4 + 5 = 9. Define adult deer in Oakridge Riverside as k; so k = G + j = 9 + 5 = 14. Define adult racoon in Oakridge Riverside as M; so M = G = 9. Define total number of adult animals in Oakridge Riverside as q; so q = M + k = 9 + 14 = 23. Answer: 23.


The number of adult deer in Beverly Forest equals the number of adult deer in Cedar Valley. The number of adult fox in Beverly Forest equals 4 times the sum of the total number of adult animals in Cedar Valley and the number of adult fox in Cedar Valley. The number of adult deer in Cedar Valley equals 3. The number of adult fox in Cedar Valley equals the number of adult deer in Cedar Valley.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult deer in Cedar Valley as x; so x = 3. Define adult fox in Cedar Valley as l; so l = x = 3. Define total number of adult animals in Cedar Valley as y; so y = x + l = 3 + 3 = 6. Define adult deer in Beverly Forest as h; so h = x = 3. Define adult fox in Beverly Forest as L; k = y + l = 6 + 3 = 9; so L = 4 * k = 4 * 9 = 36. Define total number of adult animals in Beverly Forest as Z; so Z = h + L = 3 + 36 = 39. Answer: 39.


The number of calm road movie in Rêves de Belleville equals the sum of the total number of movies in Festival de Saint-Rivage and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of solemn period drama in Festival de Saint-Rivage equals the sum of the total number of movies in Cinéma de Montreval and the number of calm road movie in Cinéma de Montreval. The number of calm road movie in Cinéma de Montreval equals 2. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the number of calm road movie in Cinéma de Montreval.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define calm road movie in Cinéma de Montreval as T; so T = 2. Define total number of movies in Cinéma de Montreval as P; so P = T = 2. Define futuristic sci-fi movie in Festival de Saint-Rivage as s; so s = T = 2. Define solemn period drama in Festival de Saint-Rivage as h; so h = P + T = 2 + 2 = 4. Define total number of movies in Festival de Saint-Rivage as q; so q = h + s = 4 + 2 = 6. Define calm road movie in Rêves de Belleville as V; so V = q + s = 6 + 2 = 8. Define total number of movies in Rêves de Belleville as p; so p = V = 8. Answer: 8.


The number of calm road movie in Northwood Movie Festival equals 2 plus the sum of the total number of movies in Taylor Movie Festival and the number of solemn period drama in Taylor Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals the number of calm road movie in Northwood Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 2. The number of calm road movie in Verdi Movie Festival equals the total number of movies in Northwood Movie Festival.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define solemn period drama in Taylor Movie Festival as L; so L = 2. Define total number of movies in Taylor Movie Festival as N; so N = L = 2. Define calm road movie in Northwood Movie Festival as O; i = N + L = 2 + 2 = 4; so O = 2 + i = 2 + 4 = 6. Define intense detective thriller in Northwood Movie Festival as U; so U = O = 6. Define total number of movies in Northwood Movie Festival as Z; so Z = U + O = 6 + 6 = 12. Define calm road movie in Verdi Movie Festival as y; so y = Z = 12. Define total number of movies in Verdi Movie Festival as e; so e = y = 12. Answer: 12.


The number of public highschool in Glenfield City equals the sum of the total number of schools in Brightford, the number of public highschool in Brightford, and the number of private middle school in Brightford. The number of public highschool in Brightford equals 1. The number of private middle school in Glenfield City equals the number of private middle school in Brightford. The number of private middle school in Brightford equals 2.

Question: What is the total number of schools in Glenfield City?

Solution: Define public highschool in Brightford as A; so A = 1. Define private middle school in Brightford as x; so x = 2. Define total number of schools in Brightford as e; so e = A + x = 1 + 2 = 3. Define public highschool in Glenfield City as b; q = e + A = 3 + 1 = 4; so b = q + x = 4 + 2 = 6. Define private middle school in Glenfield City as g; so g = x = 2. Define total number of schools in Glenfield City as v; so v = b + g = 6 + 2 = 8. Answer: 8.


The number of futuristic sci-fi movie in Cinéma de Montreval equals 3 times the total number of movies in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Rêves de Belleville equals the number of upbeat metropolis comedy in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals 4. The number of solemn period drama in Cinéma de Montreval equals the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of calm road movie in Rêves de Belleville equals 1. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 4 plus the difference between the number of futuristic sci-fi movie in Cinéma de Montreval and the total number of movies in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of calm road movie in Festival de Clairmont equals the number of upbeat metropolis comedy in Festival de Clairmont. The number of intense detective thriller in Festival Lumière de Valmont equals 1. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 4.

Question: How many solemn period drama does Cinéma de Montreval have?

Solution: Define upbeat metropolis comedy in Festival de Saint-Rivage as x; so x = 4. Define calm road movie in Festival de Saint-Rivage as D; so D = x = 4. Define total number of movies in Festival de Saint-Rivage as o; so o = D + x = 4 + 4 = 8. Define futuristic sci-fi movie in Cinéma de Montreval as p; H = o = 8; so p = 3 * H = 3 * 8 = 24. Define futuristic sci-fi movie in Festival Lumière de Valmont as b; J = p - o = 24 - 8 = 16; so b = 4 + J = 4 + 16 = 20. Define solemn period drama in Cinéma de Montreval as G; so G = b = 20. Answer: 20.


The number of solemn period drama in Taylor Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals the total number of movies in Taylor Movie Festival. The number of solemn period drama in Northwood Movie Festival equals the number of upbeat metropolis comedy in Northwood Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 3. The number of intense detective thriller in Northwood Movie Festival equals the number of solemn period drama in Taylor Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define solemn period drama in Taylor Movie Festival as r; so r = 3. Define intense detective thriller in Taylor Movie Festival as z; so z = 3. Define total number of movies in Taylor Movie Festival as a; so a = z + r = 3 + 3 = 6. Define upbeat metropolis comedy in Northwood Movie Festival as q; so q = a = 6. Define solemn period drama in Northwood Movie Festival as D; so D = q = 6. Define intense detective thriller in Northwood Movie Festival as R; so R = r = 3. Define total number of movies in Northwood Movie Festival as N; J = R + D = 3 + 6 = 9; so N = J + q = 9 + 6 = 15. Answer: 15.


The number of adult blue jay in Mayer Aquarium equals 4. The number of adult crow in Bundle Ranch equals 4 times the difference between the total number of adult animals in Hamilton Farm and the total number of adult animals in Mayer Aquarium. The number of adult owl in Hamilton Farm equals 3 plus the sum of the total number of adult animals in Mayer Aquarium and the number of adult blue jay in Mayer Aquarium.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult blue jay in Mayer Aquarium as s; so s = 4. Define total number of adult animals in Mayer Aquarium as E; so E = s = 4. Define adult owl in Hamilton Farm as Y; J = E + s = 4 + 4 = 8; so Y = 3 + J = 3 + 8 = 11. Define total number of adult animals in Hamilton Farm as l; so l = Y = 11. Define adult crow in Bundle Ranch as g; O = l - E = 11 - 4 = 7; so g = 4 * O = 4 * 7 = 28. Define total number of adult animals in Bundle Ranch as I; so I = g = 28. Answer: 28.


The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the sum of the number of futuristic sci-fi movie in Northwood Movie Festival, the number of calm road movie in Northwood Movie Festival, the total number of movies in Golden Banana Movie Festival, and the total number of movies in Northwood Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 1. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 2. The number of calm road movie in Northwood Movie Festival equals 3 times the number of solemn period drama in Northwood Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 1. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1 plus the number of calm road movie in Northwood Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 3. The number of solemn period drama in Northwood Movie Festival equals 4.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define solemn period drama in Northwood Movie Festival as I; so I = 4. Define futuristic sci-fi movie in Northwood Movie Festival as L; so L = 1. Define calm road movie in Northwood Movie Festival as x; a = I = 4; so x = 3 * a = 3 * 4 = 12. Define upbeat metropolis comedy in Northwood Movie Festival as R; p = x = 12; so R = 1 + p = 1 + 12 = 13. Define total number of movies in Northwood Movie Festival as m; D = x + I = 12 + 4 = 16; H = D + R = 16 + 13 = 29; so m = H + L = 29 + 1 = 30. Answer: 30.


The number of adult crow in Oakridge Riverside equals 1. The number of adult parrot in Oakridge Riverside equals the number of adult crow in Oakridge Riverside. The number of adult parrot in Pine Ridge equals the number of adult parrot in Oakridge Riverside. The number of adult crow in Pine Ridge equals the sum of the total number of adult animals in Oakridge Riverside, the number of adult parrot in Oakridge Riverside, and the number of adult crow in Oakridge Riverside.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult crow in Oakridge Riverside as b; so b = 1. Define adult parrot in Oakridge Riverside as L; so L = b = 1. Define total number of adult animals in Oakridge Riverside as i; so i = L + b = 1 + 1 = 2. Define adult crow in Pine Ridge as l; E = i + L = 2 + 1 = 3; so l = E + b = 3 + 1 = 4. Define adult parrot in Pine Ridge as Q; so Q = L = 1. Define total number of adult animals in Pine Ridge as O; so O = Q + l = 1 + 4 = 5. Answer: 5.


The number of adult eagle in Pine Ridge equals 4 times the sum of the number of adult owl in Oakridge Riverside and the total number of adult animals in Oakridge Riverside. The number of adult parrot in Pine Ridge equals 2 times the sum of the total number of adult animals in Oakridge Riverside and the number of adult owl in Oakridge Riverside. The number of adult owl in Oakridge Riverside equals 2. The number of adult owl in Beverly Forest equals 3 times the sum of the number of adult owl in Oakridge Riverside, the total number of adult animals in Pine Ridge, and the number of adult parrot in Pine Ridge. The number of adult blue jay in Beverly Forest equals the number of adult parrot in Pine Ridge.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult owl in Oakridge Riverside as l; so l = 2. Define total number of adult animals in Oakridge Riverside as G; so G = l = 2. Define adult parrot in Pine Ridge as H; u = G + l = 2 + 2 = 4; so H = 2 * u = 2 * 4 = 8. Define adult eagle in Pine Ridge as A; t = l + G = 2 + 2 = 4; so A = 4 * t = 4 * 4 = 16. Define total number of adult animals in Pine Ridge as m; so m = A + H = 16 + 8 = 24. Answer: 24.


The number of solemn period drama in West Sahara Movie Festival equals the total number of movies in Verdi Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 2 plus the number of solemn period drama in Verdi Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2 times the number of futuristic sci-fi movie in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 3.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define solemn period drama in Verdi Movie Festival as A; so A = 3. Define futuristic sci-fi movie in Verdi Movie Festival as j; v = A = 3; so j = 2 + v = 2 + 3 = 5. Define total number of movies in Verdi Movie Festival as Q; so Q = j + A = 5 + 3 = 8. Define solemn period drama in West Sahara Movie Festival as z; so z = Q = 8. Define futuristic sci-fi movie in West Sahara Movie Festival as i; t = j = 5; so i = 2 * t = 2 * 5 = 10. Define total number of movies in West Sahara Movie Festival as m; so m = z + i = 8 + 10 = 18. Answer: 18.


The number of solemn period drama in Festival de Clairmont equals 4. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 1. The number of intense detective thriller in Festival de Clairmont equals 3. The number of solemn period drama in Cinéma de Montreval equals 2 times the sum of the number of upbeat metropolis comedy in Festival de Saint-Rivage and the number of intense detective thriller in Festival de Clairmont. The number of intense detective thriller in Festival Lumière de Valmont equals 3. The number of intense detective thriller in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of solemn period drama in Festival Lumière de Valmont equals 2 times the number of intense detective thriller in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the total number of movies in Festival de Clairmont. The number of intense detective thriller in Cinéma de Montreval equals the number of solemn period drama in Cinéma de Montreval. The number of solemn period drama in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in Festival de Saint-Rivage.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define solemn period drama in Festival de Clairmont as z; so z = 4. Define intense detective thriller in Festival de Clairmont as k; so k = 3. Define total number of movies in Festival de Clairmont as v; so v = z + k = 4 + 3 = 7. Define upbeat metropolis comedy in Festival de Saint-Rivage as g; so g = v = 7. Define solemn period drama in Festival de Saint-Rivage as V; so V = g = 7. Define intense detective thriller in Festival de Saint-Rivage as J; so J = g = 7. Define total number of movies in Festival de Saint-Rivage as X; s = g + J = 7 + 7 = 14; so X = s + V = 14 + 7 = 21. Answer: 21.


The number of adult fox in Hamilton Farm equals the number of adult bear in South Zoo. The number of adult fox in South Zoo equals 2. The number of adult bear in South Zoo equals the number of adult fox in South Zoo. The number of adult bear in Hamilton Farm equals 4 times the difference between the total number of adult animals in South Zoo and the number of adult fox in South Zoo.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult fox in South Zoo as e; so e = 2. Define adult bear in South Zoo as I; so I = e = 2. Define total number of adult animals in South Zoo as Q; so Q = I + e = 2 + 2 = 4. Define adult bear in Hamilton Farm as Y; l = Q - e = 4 - 2 = 2; so Y = 4 * l = 4 * 2 = 8. Define adult fox in Hamilton Farm as o; so o = I = 2. Define total number of adult animals in Hamilton Farm as V; so V = Y + o = 8 + 2 = 10. Answer: 10.


The number of adult blue jay in Bundle Ranch equals 2. The number of adult blue jay in Mayer Aquarium equals 2. The number of adult crow in Mayer Aquarium equals 2 times the number of adult blue jay in Mayer Aquarium. The number of adult crow in Bundle Ranch equals 3 plus the total number of adult animals in Mayer Aquarium.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult blue jay in Mayer Aquarium as E; so E = 2. Define adult crow in Mayer Aquarium as a; N = E = 2; so a = 2 * N = 2 * 2 = 4. Define total number of adult animals in Mayer Aquarium as g; so g = a + E = 4 + 2 = 6. Define adult crow in Bundle Ranch as s; H = g = 6; so s = 3 + H = 3 + 6 = 9. Define adult blue jay in Bundle Ranch as d; so d = 2. Define total number of adult animals in Bundle Ranch as b; so b = s + d = 9 + 2 = 11. Answer: 11.


The number of culinarian school in Westhaven City equals the sum of the number of culinarian school in Glenfield City, the number of private middle school in Evervale City, the total number of schools in Evervale City, and the number of elementary school in Glenfield City. The number of private middle school in Evervale City equals the number of elementary school in Glenfield City. The number of elementary school in Glenfield City equals 4. The number of elementary school in Westhaven City equals 2. The number of culinarian school in Glenfield City equals the sum of the total number of schools in Evervale City, the number of private middle school in Evervale City, and the number of elementary school in Glenfield City.

Question: How many culinarian school does Westhaven City have?

Solution: Define elementary school in Glenfield City as c; so c = 4. Define private middle school in Evervale City as p; so p = c = 4. Define total number of schools in Evervale City as B; so B = p = 4. Define culinarian school in Glenfield City as u; j = B + p = 4 + 4 = 8; so u = j + c = 8 + 4 = 12. Define culinarian school in Westhaven City as T; D = u + p = 12 + 4 = 16; d = D + B = 16 + 4 = 20; so T = d + c = 20 + 4 = 24. Answer: 24.


The number of public highschool in Evervale City equals the number of culinarian school in Brightford. The number of culinarian school in Brightford equals 2. The number of culinarian school in Evervale City equals the sum of the total number of schools in Brightford, the number of culinarian school in Brightford, and the number of public highschool in Brightford. The number of public highschool in Brightford equals 3.

Question: What is the total number of schools in Evervale City?

Solution: Define culinarian school in Brightford as y; so y = 2. Define public highschool in Brightford as U; so U = 3. Define total number of schools in Brightford as r; so r = U + y = 3 + 2 = 5. Define culinarian school in Evervale City as d; o = r + y = 5 + 2 = 7; so d = o + U = 7 + 3 = 10. Define public highschool in Evervale City as H; so H = y = 2. Define total number of schools in Evervale City as X; so X = H + d = 2 + 10 = 12. Answer: 12.


The number of upbeat metropolis comedy in Taylor Movie Festival equals 4 times the number of solemn period drama in Taylor Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1 plus the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in Northwood Movie Festival equals the total number of movies in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 3.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define solemn period drama in Taylor Movie Festival as k; so k = 3. Define upbeat metropolis comedy in Taylor Movie Festival as h; f = k = 3; so h = 4 * f = 4 * 3 = 12. Define total number of movies in Taylor Movie Festival as l; so l = k + h = 3 + 12 = 15. Define upbeat metropolis comedy in Northwood Movie Festival as T; z = k = 3; so T = 1 + z = 1 + 3 = 4. Define solemn period drama in Northwood Movie Festival as B; so B = l = 15. Define total number of movies in Northwood Movie Festival as K; so K = B + T = 15 + 4 = 19. Answer: 19.


The number of adult racoon in Hamilton Farm equals 1 plus the difference between the number of adult wolf in Hamilton Farm and the total number of adult animals in South Zoo. The number of adult wolf in Hamilton Farm equals 4 plus the sum of the total number of adult animals in South Zoo and the number of adult wolf in South Zoo. The number of adult wolf in South Zoo equals 3.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult wolf in South Zoo as t; so t = 3. Define total number of adult animals in South Zoo as f; so f = t = 3. Define adult wolf in Hamilton Farm as o; m = f + t = 3 + 3 = 6; so o = 4 + m = 4 + 6 = 10. Define adult racoon in Hamilton Farm as u; y = o - f = 10 - 3 = 7; so u = 1 + y = 1 + 7 = 8. Define total number of adult animals in Hamilton Farm as g; so g = u + o = 8 + 10 = 18. Answer: 18.


The number of public highschool in Clearwater Bay equals 2. The number of public highschool in Riverton City equals the sum of the total number of schools in Clearwater Bay, the number of public highschool in Clearwater Bay, and the number of regional medical school in Clearwater Bay. The number of regional medical school in Riverton City equals the number of public highschool in Clearwater Bay. The number of regional medical school in Clearwater Bay equals 2.

Question: What is the total number of schools in Riverton City?

Solution: Define public highschool in Clearwater Bay as X; so X = 2. Define regional medical school in Clearwater Bay as z; so z = 2. Define total number of schools in Clearwater Bay as y; so y = z + X = 2 + 2 = 4. Define public highschool in Riverton City as t; F = y + X = 4 + 2 = 6; so t = F + z = 6 + 2 = 8. Define regional medical school in Riverton City as q; so q = X = 2. Define total number of schools in Riverton City as O; so O = q + t = 2 + 8 = 10. Answer: 10.


The number of elementary school in Clearwater Bay equals 2 plus the sum of the total number of schools in Ruby Bay, the number of public highschool in Ruby Bay, and the number of elementary school in Ruby Bay. The number of elementary school in Ruby Bay equals 2 times the number of public highschool in Ruby Bay. The number of public highschool in Ruby Bay equals 2.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define public highschool in Ruby Bay as K; so K = 2. Define elementary school in Ruby Bay as h; Q = K = 2; so h = 2 * Q = 2 * 2 = 4. Define total number of schools in Ruby Bay as n; so n = h + K = 4 + 2 = 6. Define elementary school in Clearwater Bay as Y; N = n + K = 6 + 2 = 8; U = N + h = 8 + 4 = 12; so Y = 2 + U = 2 + 12 = 14. Define total number of schools in Clearwater Bay as i; so i = Y = 14. Answer: 14.


The number of intense detective thriller in Rêves de Belleville equals the sum of the total number of movies in Cinéma de Montreval, the number of solemn period drama in Cinéma de Montreval, and the number of intense detective thriller in Cinéma de Montreval. The number of solemn period drama in Cinéma de Montreval equals the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Rêves de Belleville equals 3. The number of intense detective thriller in Cinéma de Montreval equals 2.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define solemn period drama in Rêves de Belleville as o; so o = 3. Define solemn period drama in Cinéma de Montreval as L; so L = o = 3. Define intense detective thriller in Cinéma de Montreval as T; so T = 2. Define total number of movies in Cinéma de Montreval as D; so D = T + L = 2 + 3 = 5. Define intense detective thriller in Rêves de Belleville as p; Y = D + L = 5 + 3 = 8; so p = Y + T = 8 + 2 = 10. Define total number of movies in Rêves de Belleville as J; so J = p + o = 10 + 3 = 13. Answer: 13.


The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the difference between the total number of movies in Rêves de Belleville and the number of upbeat metropolis comedy in Rêves de Belleville. The number of solemn period drama in Festival Lumière de Valmont equals 3. The number of solemn period drama in Rêves de Belleville equals 4. The number of upbeat metropolis comedy in Rêves de Belleville equals 2 times the number of solemn period drama in Rêves de Belleville.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define solemn period drama in Rêves de Belleville as j; so j = 4. Define upbeat metropolis comedy in Rêves de Belleville as w; d = j = 4; so w = 2 * d = 2 * 4 = 8. Define total number of movies in Rêves de Belleville as T; so T = w + j = 8 + 4 = 12. Define upbeat metropolis comedy in Festival Lumière de Valmont as s; so s = T - w = 12 - 8 = 4. Define solemn period drama in Festival Lumière de Valmont as U; so U = 3. Define total number of movies in Festival Lumière de Valmont as M; so M = s + U = 4 + 3 = 7. Answer: 7.


The number of adult eagle in Jefferson Circus equals 2 times the sum of the total number of adult animals in South Zoo, the number of adult eagle in South Zoo, and the number of adult crow in South Zoo. The number of adult crow in South Zoo equals 2 times the number of adult eagle in South Zoo. The number of adult eagle in South Zoo equals 3.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult eagle in South Zoo as z; so z = 3. Define adult crow in South Zoo as a; T = z = 3; so a = 2 * T = 2 * 3 = 6. Define total number of adult animals in South Zoo as P; so P = z + a = 3 + 6 = 9. Define adult eagle in Jefferson Circus as V; Z = P + z = 9 + 3 = 12; u = Z + a = 12 + 6 = 18; so V = 2 * u = 2 * 18 = 36. Define total number of adult animals in Jefferson Circus as B; so B = V = 36. Answer: 36.