The number of regional medical school in Brightford equals 2. The number of elementary school in Westhaven City equals 2 times the sum of the total number of schools in Brightford and the number of regional medical school in Brightford. The number of regional medical school in Westhaven City equals 4 times the sum of the number of elementary school in Westhaven City and the number of regional medical school in Brightford.

Question: What is the total number of schools in Westhaven City?

Solution: Define regional medical school in Brightford as g; so g = 2. Define total number of schools in Brightford as J; so J = g = 2. Define elementary school in Westhaven City as R; j = J + g = 2 + 2 = 4; so R = 2 * j = 2 * 4 = 8. Define regional medical school in Westhaven City as N; b = R + g = 8 + 2 = 10; so N = 4 * b = 4 * 10 = 40. Define total number of schools in Westhaven City as B; so B = R + N = 8 + 40 = 48. Answer: 48.


The number of upbeat metropolis comedy in Northwood Movie Festival equals 4 plus the sum of the number of calm road movie in Northwood Movie Festival and the total number of movies in Golden Banana Movie Festival. The number of calm road movie in Northwood Movie Festival equals 4 plus the difference between the total number of movies in Golden Banana Movie Festival and the number of calm road movie in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 3.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define calm road movie in Golden Banana Movie Festival as C; so C = 3. Define total number of movies in Golden Banana Movie Festival as P; so P = C = 3. Define calm road movie in Northwood Movie Festival as x; U = P - C = 3 - 3 = 0; so x = 4 + U = 4 + 0 = 4. Define upbeat metropolis comedy in Northwood Movie Festival as o; V = x + P = 4 + 3 = 7; so o = 4 + V = 4 + 7 = 11. Define total number of movies in Northwood Movie Festival as r; so r = x + o = 4 + 11 = 15. Answer: 15.


The number of calm road movie in Taylor Movie Festival equals the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals the sum of the number of solemn period drama in Taylor Movie Festival and the number of calm road movie in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 3 times the total number of movies in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 4.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define solemn period drama in Taylor Movie Festival as i; so i = 4. Define calm road movie in Taylor Movie Festival as Z; so Z = i = 4. Define total number of movies in Taylor Movie Festival as T; so T = Z + i = 4 + 4 = 8. Define calm road movie in West Sahara Movie Festival as Y; m = T = 8; so Y = 3 * m = 3 * 8 = 24. Define solemn period drama in West Sahara Movie Festival as q; so q = i + Y = 4 + 24 = 28. Define total number of movies in West Sahara Movie Festival as U; so U = q + Y = 28 + 24 = 52. Answer: 52.


The number of regional medical school in Oakbridge City equals 2. The number of elementary school in Shoreline City equals 1 plus the sum of the total number of schools in Oakbridge City and the number of regional medical school in Oakbridge City. The number of regional medical school in Shoreline City equals the sum of the number of elementary school in Shoreline City, the total number of schools in Oakbridge City, and the number of regional medical school in Oakbridge City.

Question: What is the total number of schools in Shoreline City?

Solution: Define regional medical school in Oakbridge City as t; so t = 2. Define total number of schools in Oakbridge City as k; so k = t = 2. Define elementary school in Shoreline City as H; K = k + t = 2 + 2 = 4; so H = 1 + K = 1 + 4 = 5. Define regional medical school in Shoreline City as z; Z = H + k = 5 + 2 = 7; so z = Z + t = 7 + 2 = 9. Define total number of schools in Shoreline City as D; so D = H + z = 5 + 9 = 14. Answer: 14.


The number of adult eagle in Bundle Ranch equals 1 plus the sum of the total number of adult animals in Hamilton Farm and the number of adult blue jay in Bundle Ranch. The number of adult eagle in Hamilton Farm equals 2 plus the number of adult blue jay in Bundle Ranch. The number of adult blue jay in Hamilton Farm equals 3 plus the number of adult blue jay in Bundle Ranch. The number of adult blue jay in Bundle Ranch equals 2.

Question: How many adult eagle does Bundle Ranch have?

Solution: Define adult blue jay in Bundle Ranch as K; so K = 2. Define adult eagle in Hamilton Farm as B; c = K = 2; so B = 2 + c = 2 + 2 = 4. Define adult blue jay in Hamilton Farm as F; y = K = 2; so F = 3 + y = 3 + 2 = 5. Define total number of adult animals in Hamilton Farm as a; so a = B + F = 4 + 5 = 9. Define adult eagle in Bundle Ranch as L; j = a + K = 9 + 2 = 11; so L = 1 + j = 1 + 11 = 12. Answer: 12.


The number of culinarian school in Brightford equals 2. The number of regional medical school in Westhaven City equals the sum of the number of elementary school in Hawkesbury and the number of public highschool in Evervale City. The number of elementary school in Hawkesbury equals 4. The number of public highschool in Evervale City equals the sum of the total number of schools in Glenfield City, the number of elementary school in Hawkesbury, and the number of culinarian school in Glenfield City. The number of elementary school in Brightford equals 2. The number of private middle school in Brightford equals the number of elementary school in Brightford. The number of culinarian school in Glenfield City equals 3 times the sum of the total number of schools in Hawkesbury and the number of elementary school in Hawkesbury. The number of public highschool in Westhaven City equals 3.

Question: What is the total number of schools in Evervale City?

Solution: Define elementary school in Hawkesbury as D; so D = 4. Define total number of schools in Hawkesbury as c; so c = D = 4. Define culinarian school in Glenfield City as u; A = c + D = 4 + 4 = 8; so u = 3 * A = 3 * 8 = 24. Define total number of schools in Glenfield City as b; so b = u = 24. Define public highschool in Evervale City as T; r = b + D = 24 + 4 = 28; so T = r + u = 28 + 24 = 52. Define total number of schools in Evervale City as P; so P = T = 52. Answer: 52.


The number of culinarian school in Riverton City equals 2. The number of elementary school in Oakbridge City equals 4 plus the difference between the total number of schools in Riverton City and the number of culinarian school in Riverton City. The number of culinarian school in Oakbridge City equals the sum of the number of culinarian school in Riverton City, the total number of schools in Riverton City, and the number of elementary school in Oakbridge City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define culinarian school in Riverton City as r; so r = 2. Define total number of schools in Riverton City as L; so L = r = 2. Define elementary school in Oakbridge City as n; Z = L - r = 2 - 2 = 0; so n = 4 + Z = 4 + 0 = 4. Define culinarian school in Oakbridge City as B; W = r + L = 2 + 2 = 4; so B = W + n = 4 + 4 = 8. Define total number of schools in Oakbridge City as u; so u = n + B = 4 + 8 = 12. Answer: 12.


The number of adult racoon in Mayer Aquarium equals the difference between the total number of adult animals in Bundle Ranch and the number of adult bear in Hamilton Farm. The number of adult deer in South Zoo equals 3 plus the total number of adult animals in Hamilton Farm. The number of adult bear in Hamilton Farm equals 4. The number of adult wolf in Bundle Ranch equals the total number of adult animals in South Zoo.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult bear in Hamilton Farm as U; so U = 4. Define total number of adult animals in Hamilton Farm as M; so M = U = 4. Define adult deer in South Zoo as w; h = M = 4; so w = 3 + h = 3 + 4 = 7. Define total number of adult animals in South Zoo as P; so P = w = 7. Define adult wolf in Bundle Ranch as q; so q = P = 7. Define total number of adult animals in Bundle Ranch as K; so K = q = 7. Define adult racoon in Mayer Aquarium as Z; so Z = K - U = 7 - 4 = 3. Define total number of adult animals in Mayer Aquarium as V; so V = Z = 3. Answer: 3.


The number of adult blue jay in Pine Ridge equals 2. The number of adult crow in Pine Ridge equals 3 times the number of adult blue jay in Pine Ridge. The number of adult blue jay in Beverly Forest equals the number of adult blue jay in Pine Ridge. The number of adult crow in Beverly Forest equals 2 times the total number of adult animals in Pine Ridge.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult blue jay in Pine Ridge as F; so F = 2. Define adult crow in Pine Ridge as Q; C = F = 2; so Q = 3 * C = 3 * 2 = 6. Define total number of adult animals in Pine Ridge as m; so m = F + Q = 2 + 6 = 8. Define adult crow in Beverly Forest as R; n = m = 8; so R = 2 * n = 2 * 8 = 16. Define adult blue jay in Beverly Forest as L; so L = F = 2. Define total number of adult animals in Beverly Forest as w; so w = L + R = 2 + 16 = 18. Answer: 18.


The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4 plus the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 3. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2 times the total number of movies in Golden Banana Movie Festival.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define futuristic sci-fi movie in Golden Banana Movie Festival as J; so J = 3. Define upbeat metropolis comedy in Golden Banana Movie Festival as o; M = J = 3; so o = 4 + M = 4 + 3 = 7. Define total number of movies in Golden Banana Movie Festival as T; so T = J + o = 3 + 7 = 10. Define futuristic sci-fi movie in West Sahara Movie Festival as G; a = T = 10; so G = 2 * a = 2 * 10 = 20. Define upbeat metropolis comedy in West Sahara Movie Festival as d; so d = J = 3. Define total number of movies in West Sahara Movie Festival as p; so p = G + d = 20 + 3 = 23. Answer: 23.


The number of public highschool in Glenfield City equals 1 plus the difference between the total number of schools in Evervale City and the number of culinarian school in Evervale City. The number of culinarian school in Glenfield City equals 2 plus the difference between the number of culinarian school in Evervale City and the total number of schools in Evervale City. The number of culinarian school in Evervale City equals 4.

Question: What is the total number of schools in Glenfield City?

Solution: Define culinarian school in Evervale City as A; so A = 4. Define total number of schools in Evervale City as T; so T = A = 4. Define public highschool in Glenfield City as p; d = T - A = 4 - 4 = 0; so p = 1 + d = 1 + 0 = 1. Define culinarian school in Glenfield City as c; Z = A - T = 4 - 4 = 0; so c = 2 + Z = 2 + 0 = 2. Define total number of schools in Glenfield City as Y; so Y = c + p = 2 + 1 = 3. Answer: 3.


The number of culinarian school in Hawkesbury equals 4. The number of public highschool in Brightford equals the sum of the number of elementary school in Brightford, the number of culinarian school in Hawkesbury, and the total number of schools in Hawkesbury. The number of elementary school in Brightford equals 3 times the sum of the total number of schools in Hawkesbury and the number of culinarian school in Hawkesbury.

Question: What is the total number of schools in Brightford?

Solution: Define culinarian school in Hawkesbury as X; so X = 4. Define total number of schools in Hawkesbury as Y; so Y = X = 4. Define elementary school in Brightford as I; L = Y + X = 4 + 4 = 8; so I = 3 * L = 3 * 8 = 24. Define public highschool in Brightford as e; O = I + X = 24 + 4 = 28; so e = O + Y = 28 + 4 = 32. Define total number of schools in Brightford as G; so G = e + I = 32 + 24 = 56. Answer: 56.


The number of solemn period drama in Festival de Clairmont equals 4 plus the difference between the number of upbeat metropolis comedy in Festival de Saint-Rivage and the number of solemn period drama in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2. The number of solemn period drama in Festival de Saint-Rivage equals 2. The number of upbeat metropolis comedy in Festival de Clairmont equals the total number of movies in Festival de Saint-Rivage.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define solemn period drama in Festival de Saint-Rivage as c; so c = 2. Define upbeat metropolis comedy in Festival de Saint-Rivage as N; so N = 2. Define total number of movies in Festival de Saint-Rivage as p; so p = N + c = 2 + 2 = 4. Define upbeat metropolis comedy in Festival de Clairmont as r; so r = p = 4. Define solemn period drama in Festival de Clairmont as k; u = N - c = 2 - 2 = 0; so k = 4 + u = 4 + 0 = 4. Define total number of movies in Festival de Clairmont as V; so V = r + k = 4 + 4 = 8. Answer: 8.


The number of culinarian school in Brightford equals 3 plus the number of private middle school in Brightford. The number of culinarian school in Hawkesbury equals 4. The number of private middle school in Brightford equals 4 plus the total number of schools in Hawkesbury. The number of private middle school in Hawkesbury equals the number of culinarian school in Hawkesbury.

Question: What is the total number of schools in Brightford?

Solution: Define culinarian school in Hawkesbury as N; so N = 4. Define private middle school in Hawkesbury as j; so j = N = 4. Define total number of schools in Hawkesbury as V; so V = j + N = 4 + 4 = 8. Define private middle school in Brightford as Z; P = V = 8; so Z = 4 + P = 4 + 8 = 12. Define culinarian school in Brightford as s; T = Z = 12; so s = 3 + T = 3 + 12 = 15. Define total number of schools in Brightford as K; so K = Z + s = 12 + 15 = 27. Answer: 27.


The number of intense detective thriller in Taylor Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. The number of calm road movie in Verdi Movie Festival equals the sum of the total number of movies in Taylor Movie Festival, the number of calm road movie in Taylor Movie Festival, and the number of intense detective thriller in Taylor Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 1. The number of futuristic sci-fi movie in Taylor Movie Festival equals 1. The number of intense detective thriller in West Sahara Movie Festival equals 4. The number of intense detective thriller in Golden Banana Movie Festival equals the sum of the number of calm road movie in Verdi Movie Festival and the number of calm road movie in Taylor Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the sum of the number of calm road movie in Taylor Movie Festival, the number of intense detective thriller in Verdi Movie Festival, and the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 4 plus the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of calm road movie in Taylor Movie Festival equals 2 plus the number of futuristic sci-fi movie in Taylor Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2. The number of futuristic sci-fi movie in Verdi Movie Festival equals 2 plus the number of futuristic sci-fi movie in Taylor Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 3.

Question: How many calm road movie does Verdi Movie Festival have?

Solution: Define futuristic sci-fi movie in Taylor Movie Festival as H; so H = 1. Define calm road movie in Taylor Movie Festival as Z; j = H = 1; so Z = 2 + j = 2 + 1 = 3. Define intense detective thriller in Taylor Movie Festival as g; so g = H = 1. Define total number of movies in Taylor Movie Festival as i; p = g + H = 1 + 1 = 2; so i = p + Z = 2 + 3 = 5. Define calm road movie in Verdi Movie Festival as a; Q = i + Z = 5 + 3 = 8; so a = Q + g = 8 + 1 = 9. Answer: 9.


The number of adult fox in Hamilton Farm equals 4. The number of adult bear in South Zoo equals 3 plus the sum of the total number of adult animals in Hamilton Farm and the number of adult fox in Hamilton Farm. The number of adult fox in South Zoo equals 3 times the difference between the number of adult bear in South Zoo and the number of adult fox in Hamilton Farm.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult fox in Hamilton Farm as U; so U = 4. Define total number of adult animals in Hamilton Farm as M; so M = U = 4. Define adult bear in South Zoo as X; n = M + U = 4 + 4 = 8; so X = 3 + n = 3 + 8 = 11. Define adult fox in South Zoo as w; k = X - U = 11 - 4 = 7; so w = 3 * k = 3 * 7 = 21. Define total number of adult animals in South Zoo as A; so A = w + X = 21 + 11 = 32. Answer: 32.


The number of calm road movie in Festival de Saint-Rivage equals 4 times the number of intense detective thriller in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of calm road movie in Festival de Saint-Rivage. The number of intense detective thriller in Festival Lumière de Valmont equals 2. The number of intense detective thriller in Festival de Saint-Rivage equals 4. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 4. The number of intense detective thriller in Rêves de Belleville equals 3. The number of upbeat metropolis comedy in Rêves de Belleville equals 1 plus the total number of movies in Rêves de Belleville. The number of calm road movie in Rêves de Belleville equals 2 times the sum of the total number of movies in Festival de Saint-Rivage and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of calm road movie in Festival Lumière de Valmont equals 4.

Question: How many calm road movie does Rêves de Belleville have?

Solution: Define intense detective thriller in Festival de Saint-Rivage as i; so i = 4. Define calm road movie in Festival de Saint-Rivage as j; s = i = 4; so j = 4 * s = 4 * 4 = 16. Define upbeat metropolis comedy in Festival de Saint-Rivage as w; so w = j = 16. Define total number of movies in Festival de Saint-Rivage as Y; v = i + j = 4 + 16 = 20; so Y = v + w = 20 + 16 = 36. Define calm road movie in Rêves de Belleville as I; E = Y + w = 36 + 16 = 52; so I = 2 * E = 2 * 52 = 104. Answer: 104.