The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 4. The number of intense detective thriller in Festival Lumière de Valmont equals 4 times the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of intense detective thriller in Festival de Saint-Rivage equals 2 plus the sum of the total number of movies in Festival Lumière de Valmont, the number of futuristic sci-fi movie in Festival Lumière de Valmont, and the number of intense detective thriller in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define futuristic sci-fi movie in Festival Lumière de Valmont as C; so C = 4. Define intense detective thriller in Festival Lumière de Valmont as f; w = C = 4; so f = 4 * w = 4 * 4 = 16. Define total number of movies in Festival Lumière de Valmont as K; so K = f + C = 16 + 4 = 20. Define intense detective thriller in Festival de Saint-Rivage as D; i = K + C = 20 + 4 = 24; R = i + f = 24 + 16 = 40; so D = 2 + R = 2 + 40 = 42. Define total number of movies in Festival de Saint-Rivage as G; so G = D = 42. Answer: 42.


The number of adult bear in Mayer Aquarium equals the difference between the number of adult wolf in Mayer Aquarium and the number of adult fox in Mayer Aquarium. The number of adult wolf in Mayer Aquarium equals the number of adult racoon in Mayer Aquarium. The number of adult fox in Mayer Aquarium equals the number of adult fox in Jefferson Circus. The number of adult wolf in South Zoo equals 4. The number of adult bear in Hamilton Farm equals 1 plus the sum of the number of adult bear in Mayer Aquarium, the number of adult fox in Jefferson Circus, and the total number of adult animals in Mayer Aquarium. The number of adult fox in Jefferson Circus equals 3. The number of adult wolf in Jefferson Circus equals the number of adult wolf in South Zoo. The number of adult fox in Hamilton Farm equals the difference between the number of adult racoon in Jefferson Circus and the total number of adult animals in Mayer Aquarium. The number of adult racoon in Jefferson Circus equals the number of adult fox in Jefferson Circus. The number of adult bear in South Zoo equals 4 plus the sum of the number of adult wolf in South Zoo and the number of adult wolf in Jefferson Circus. The number of adult fox in South Zoo equals 2. The number of adult racoon in Mayer Aquarium equals 4. The number of adult wolf in Hamilton Farm equals 2. The number of adult bear in Jefferson Circus equals 3.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult fox in Jefferson Circus as u; so u = 3. Define adult fox in Mayer Aquarium as P; so P = u = 3. Define adult racoon in Mayer Aquarium as s; so s = 4. Define adult wolf in Mayer Aquarium as o; so o = s = 4. Define adult bear in Mayer Aquarium as r; so r = o - P = 4 - 3 = 1. Define total number of adult animals in Mayer Aquarium as R; c = r + s = 1 + 4 = 5; g = c + P = 5 + 3 = 8; so R = g + o = 8 + 4 = 12. Answer: 12.


The number of upbeat metropolis comedy in Rêves de Belleville equals the total number of movies in Festival de Saint-Rivage. The number of solemn period drama in Festival de Clairmont equals 3. The number of calm road movie in Festival de Saint-Rivage equals the sum of the total number of movies in Festival de Clairmont, the number of solemn period drama in Festival de Clairmont, and the number of futuristic sci-fi movie in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Clairmont equals 3.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define solemn period drama in Festival de Clairmont as S; so S = 3. Define futuristic sci-fi movie in Festival de Clairmont as A; so A = 3. Define total number of movies in Festival de Clairmont as U; so U = S + A = 3 + 3 = 6. Define calm road movie in Festival de Saint-Rivage as q; H = U + S = 6 + 3 = 9; so q = H + A = 9 + 3 = 12. Define total number of movies in Festival de Saint-Rivage as W; so W = q = 12. Define upbeat metropolis comedy in Rêves de Belleville as X; so X = W = 12. Define total number of movies in Rêves de Belleville as z; so z = X = 12. Answer: 12.


The number of adult parrot in Mayer Aquarium equals 3. The number of adult eagle in Bundle Ranch equals 1 plus the sum of the total number of adult animals in Mayer Aquarium, the number of adult parrot in Mayer Aquarium, and the number of adult crow in Mayer Aquarium. The number of adult crow in Mayer Aquarium equals 2 plus the number of adult parrot in Mayer Aquarium.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult parrot in Mayer Aquarium as l; so l = 3. Define adult crow in Mayer Aquarium as Z; T = l = 3; so Z = 2 + T = 2 + 3 = 5. Define total number of adult animals in Mayer Aquarium as s; so s = l + Z = 3 + 5 = 8. Define adult eagle in Bundle Ranch as c; u = s + l = 8 + 3 = 11; a = u + Z = 11 + 5 = 16; so c = 1 + a = 1 + 16 = 17. Define total number of adult animals in Bundle Ranch as q; so q = c = 17. Answer: 17.


The number of regional medical school in Brightford equals the number of elementary school in Glenfield City. The number of elementary school in Glenfield City equals 1 plus the difference between the number of regional medical school in Glenfield City and the number of elementary school in Evervale City. The number of elementary school in Evervale City equals 4. The number of regional medical school in Glenfield City equals the number of elementary school in Evervale City. The number of regional medical school in Evervale City equals the total number of schools in Glenfield City.

Question: What is the total number of schools in Evervale City?

Solution: Define elementary school in Evervale City as V; so V = 4. Define regional medical school in Glenfield City as P; so P = V = 4. Define elementary school in Glenfield City as g; G = P - V = 4 - 4 = 0; so g = 1 + G = 1 + 0 = 1. Define total number of schools in Glenfield City as r; so r = g + P = 1 + 4 = 5. Define regional medical school in Evervale City as w; so w = r = 5. Define total number of schools in Evervale City as k; so k = V + w = 4 + 5 = 9. Answer: 9.


The number of solemn period drama in Verdi Movie Festival equals 3 times the sum of the total number of movies in Golden Banana Movie Festival, the number of solemn period drama in Golden Banana Movie Festival, and the number of intense detective thriller in Golden Banana Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 4 plus the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 4.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define solemn period drama in Golden Banana Movie Festival as u; so u = 4. Define intense detective thriller in Golden Banana Movie Festival as O; x = u = 4; so O = 4 + x = 4 + 4 = 8. Define total number of movies in Golden Banana Movie Festival as k; so k = u + O = 4 + 8 = 12. Define solemn period drama in Verdi Movie Festival as a; Q = k + u = 12 + 4 = 16; p = Q + O = 16 + 8 = 24; so a = 3 * p = 3 * 24 = 72. Define total number of movies in Verdi Movie Festival as z; so z = a = 72. Answer: 72.


The number of elementary school in Westhaven City equals 4 times the number of regional medical school in Westhaven City. The number of regional medical school in Westhaven City equals 2. The number of culinarian school in Glenfield City equals 2 plus the total number of schools in Westhaven City. The number of regional medical school in Hawkesbury equals the total number of schools in Glenfield City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define regional medical school in Westhaven City as f; so f = 2. Define elementary school in Westhaven City as k; F = f = 2; so k = 4 * F = 4 * 2 = 8. Define total number of schools in Westhaven City as D; so D = k + f = 8 + 2 = 10. Define culinarian school in Glenfield City as d; R = D = 10; so d = 2 + R = 2 + 10 = 12. Define total number of schools in Glenfield City as B; so B = d = 12. Define regional medical school in Hawkesbury as i; so i = B = 12. Define total number of schools in Hawkesbury as r; so r = i = 12. Answer: 12.


The number of regional medical school in Brightford equals 1 plus the total number of schools in Hawkesbury. The number of culinarian school in Westhaven City equals the sum of the total number of schools in Brightford, the total number of schools in Glenfield City, and the total number of schools in Hawkesbury. The number of regional medical school in Hawkesbury equals 3. The number of elementary school in Brightford equals 4 plus the total number of schools in Glenfield City. The number of public highschool in Westhaven City equals 4 plus the number of regional medical school in Hawkesbury. The number of elementary school in Glenfield City equals 4.

Question: What is the total number of schools in Brightford?

Solution: Define regional medical school in Hawkesbury as Y; so Y = 3. Define total number of schools in Hawkesbury as R; so R = Y = 3. Define regional medical school in Brightford as u; Z = R = 3; so u = 1 + Z = 1 + 3 = 4. Define elementary school in Glenfield City as V; so V = 4. Define total number of schools in Glenfield City as b; so b = V = 4. Define elementary school in Brightford as B; C = b = 4; so B = 4 + C = 4 + 4 = 8. Define total number of schools in Brightford as x; so x = u + B = 4 + 8 = 12. Answer: 12.


The number of culinarian school in Brightford equals 3 plus the difference between the number of regional medical school in Brightford and the number of elementary school in Glenfield City. The number of regional medical school in Brightford equals 2 times the sum of the total number of schools in Glenfield City and the number of elementary school in Glenfield City. The number of elementary school in Glenfield City equals 2.

Question: What is the total number of schools in Brightford?

Solution: Define elementary school in Glenfield City as g; so g = 2. Define total number of schools in Glenfield City as K; so K = g = 2. Define regional medical school in Brightford as r; h = K + g = 2 + 2 = 4; so r = 2 * h = 2 * 4 = 8. Define culinarian school in Brightford as O; P = r - g = 8 - 2 = 6; so O = 3 + P = 3 + 6 = 9. Define total number of schools in Brightford as y; so y = O + r = 9 + 8 = 17. Answer: 17.


The number of regional medical school in Westhaven City equals 3. The number of private middle school in Westhaven City equals the sum of the total number of schools in Hawkesbury, the number of private middle school in Hawkesbury, and the number of regional medical school in Hawkesbury. The number of private middle school in Hawkesbury equals 3. The number of regional medical school in Hawkesbury equals the number of private middle school in Hawkesbury.

Question: What is the total number of schools in Westhaven City?

Solution: Define private middle school in Hawkesbury as g; so g = 3. Define regional medical school in Hawkesbury as R; so R = g = 3. Define total number of schools in Hawkesbury as z; so z = g + R = 3 + 3 = 6. Define private middle school in Westhaven City as W; k = z + g = 6 + 3 = 9; so W = k + R = 9 + 3 = 12. Define regional medical school in Westhaven City as K; so K = 3. Define total number of schools in Westhaven City as f; so f = W + K = 12 + 3 = 15. Answer: 15.


The number of culinarian school in Westhaven City equals 1 plus the number of private middle school in Westhaven City. The number of culinarian school in Brightford equals 2 times the sum of the total number of schools in Westhaven City, the number of private middle school in Westhaven City, and the number of culinarian school in Westhaven City. The number of private middle school in Westhaven City equals 2.

Question: What is the total number of schools in Brightford?

Solution: Define private middle school in Westhaven City as c; so c = 2. Define culinarian school in Westhaven City as Y; A = c = 2; so Y = 1 + A = 1 + 2 = 3. Define total number of schools in Westhaven City as u; so u = c + Y = 2 + 3 = 5. Define culinarian school in Brightford as k; r = u + c = 5 + 2 = 7; Q = r + Y = 7 + 3 = 10; so k = 2 * Q = 2 * 10 = 20. Define total number of schools in Brightford as v; so v = k = 20. Answer: 20.


The number of adult fox in Beverly Forest equals 2. The number of adult bear in Oakridge Riverside equals the sum of the total number of adult animals in Maple Creek, the number of adult wolf in Maple Creek, and the total number of adult animals in Beverly Forest. The number of adult wolf in Maple Creek equals 2 times the sum of the total number of adult animals in Beverly Forest and the number of adult fox in Beverly Forest.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult fox in Beverly Forest as c; so c = 2. Define total number of adult animals in Beverly Forest as q; so q = c = 2. Define adult wolf in Maple Creek as r; S = q + c = 2 + 2 = 4; so r = 2 * S = 2 * 4 = 8. Define total number of adult animals in Maple Creek as L; so L = r = 8. Define adult bear in Oakridge Riverside as X; Y = L + r = 8 + 8 = 16; so X = Y + q = 16 + 2 = 18. Define total number of adult animals in Oakridge Riverside as W; so W = X = 18. Answer: 18.


The number of private middle school in Oakbridge City equals 1 plus the sum of the total number of schools in Shoreline City and the number of regional medical school in Shoreline City. The number of private middle school in Shoreline City equals the number of regional medical school in Shoreline City. The number of regional medical school in Oakbridge City equals 2. The number of regional medical school in Shoreline City equals 3.

Question: What is the total number of schools in Oakbridge City?

Solution: Define regional medical school in Shoreline City as s; so s = 3. Define private middle school in Shoreline City as m; so m = s = 3. Define total number of schools in Shoreline City as J; so J = s + m = 3 + 3 = 6. Define private middle school in Oakbridge City as T; e = J + s = 6 + 3 = 9; so T = 1 + e = 1 + 9 = 10. Define regional medical school in Oakbridge City as Q; so Q = 2. Define total number of schools in Oakbridge City as k; so k = Q + T = 2 + 10 = 12. Answer: 12.


The number of elementary school in Clearwater Bay equals 3 times the number of private middle school in Clearwater Bay. The number of private middle school in Ruby Bay equals 4 plus the number of private middle school in Clearwater Bay. The number of private middle school in Clearwater Bay equals 2. The number of elementary school in Ruby Bay equals the total number of schools in Clearwater Bay.

Question: What is the total number of schools in Ruby Bay?

Solution: Define private middle school in Clearwater Bay as q; so q = 2. Define elementary school in Clearwater Bay as y; H = q = 2; so y = 3 * H = 3 * 2 = 6. Define total number of schools in Clearwater Bay as a; so a = q + y = 2 + 6 = 8. Define elementary school in Ruby Bay as z; so z = a = 8. Define private middle school in Ruby Bay as I; A = q = 2; so I = 4 + A = 4 + 2 = 6. Define total number of schools in Ruby Bay as v; so v = I + z = 6 + 8 = 14. Answer: 14.


The number of private middle school in Glenfield City equals the number of private middle school in Brightford. The number of public highschool in Glenfield City equals 3 plus the sum of the total number of schools in Brightford and the number of private middle school in Brightford. The number of private middle school in Brightford equals 4. The number of public highschool in Brightford equals the number of private middle school in Brightford.

Question: What is the total number of schools in Glenfield City?

Solution: Define private middle school in Brightford as b; so b = 4. Define public highschool in Brightford as E; so E = b = 4. Define total number of schools in Brightford as c; so c = E + b = 4 + 4 = 8. Define public highschool in Glenfield City as p; O = c + b = 8 + 4 = 12; so p = 3 + O = 3 + 12 = 15. Define private middle school in Glenfield City as s; so s = b = 4. Define total number of schools in Glenfield City as P; so P = p + s = 15 + 4 = 19. Answer: 19.