import os import pickle import torch import numpy as np import ast from flask import Flask, request, jsonify from transformers import AutoTokenizer, AutoModel # --- IMPORT ETHAN'S HYBRID ENGINE (Checker 1 & 2) --- from codesense.analyzer import analyze_code app = Flask(__name__) # --- CONFIG --- MODEL_FILE = 'NEW_BRAIN_MLP.pk2' base_dir = os.path.dirname(os.path.abspath(__file__)) model_path = os.path.join(base_dir, MODEL_FILE) print("âŗ Booting up CodeSense Triple-Checker System...") print("âŗ Loading Checker 1 & 2: AST Rule-Engine + CodeT5...") # --- LOAD YOUR SAFETY NET (Checker 3: CodeBERT + pk2) --- try: print(f"📂 Loading Checker 3: CodeBERT Safety Net ({MODEL_FILE})...") tokenizer = AutoTokenizer.from_pretrained("microsoft/codebert-base") codebert = AutoModel.from_pretrained("microsoft/codebert-base") with open(model_path, 'rb') as f: classifier = pickle.load(f) print("✅ All 3 AI Brains Loaded! Server Ready on Port 5000.") except Exception as e: print(f"❌ WARNING: Could not load Safety Net. {e}") classifier = None def get_vector(code): inputs = tokenizer(code, return_tensors="pt", truncation=True, max_length=512, padding=True) with torch.no_grad(): outputs = codebert(**inputs) return outputs.last_hidden_state[:, 0, :].numpy().flatten() # --- YOUR MAGIC VARIABLE EXTRACTOR & AST LOOP COUNTER --- class CodeAnalyzer(ast.NodeVisitor): def __init__(self): self.max_loop_depth = 0 self.current_loop_depth = 0 self.func_name = "optimized_function" self.args_string = "data" self.first_arg = "data" def visit_FunctionDef(self, node): self.func_name = node.name arg_names = [arg.arg for arg in node.args.args] if arg_names: self.args_string = ", ".join(arg_names) self.first_arg = arg_names[0] self.generic_visit(node) def visit_For(self, node): self.current_loop_depth += 1 if self.current_loop_depth > self.max_loop_depth: self.max_loop_depth = self.current_loop_depth self.generic_visit(node) self.current_loop_depth -= 1 def visit_While(self, node): self.current_loop_depth += 1 if self.current_loop_depth > self.max_loop_depth: self.max_loop_depth = self.current_loop_depth self.generic_visit(node) self.current_loop_depth -= 1 # --- API ROUTE --- @app.route('/predict', methods=['POST']) def predict(): data = request.json code = data.get('code', '') if not code: return jsonify({"error": "No code provided"}), 400 try: # 1. Extract your variables & Count Loops analyzer = CodeAnalyzer() try: tree = ast.parse(code) analyzer.visit(tree) # --- CALCULATE TIME COMPLEXITY USING AST --- loop_depth = analyzer.max_loop_depth if loop_depth == 0: dynamic_comp = "O(1) (No loops)" elif loop_depth == 1: dynamic_comp = "O(n) (Linear)" elif loop_depth == 2: dynamic_comp = "O(n^2) (Nested loops)" else: dynamic_comp = f"O(n^{loop_depth}) (Deeply nested)" except Exception: dynamic_comp = "Error parsing code structure" # ========================================== # đŸ›Ąī¸ THE TRIPLE-CHECKER LOGIC # ========================================== # Run Ethan's Engine analysis_result = analyze_code(code) algo = analysis_result.get("pattern", "Unknown") ethan_summary = analysis_result.get("summary", "") t5_raw_conf = analysis_result.get("ml_insights", {}).get("confidence", 0.0) final_conf = t5_raw_conf safety_net_triggered = False # Patterns that mean the first engine is slightly confused GENERIC_PATTERNS = ["Unknown", "Nested Iterative", "Linear Iterative", "Recursive (Linear)", "Recursive (Exponential)"] # If AST/CodeT5 is confused, trigger YOUR CodeBERT model! if (algo in GENERIC_PATTERNS or t5_raw_conf < 0.90) and classifier is not None: print(f"âš ī¸ Primary engine unsure (Confidence: {t5_raw_conf:.2f}). Triggering CodeBERT Safety Net...") try: vector = get_vector(code) bert_pred = classifier.predict([vector])[0] try: bert_probs = classifier.predict_proba([vector])[0] bert_conf = float(max(bert_probs)) except: bert_conf = 0.85 if bert_conf >= 0.80: algo = bert_pred final_conf = bert_conf safety_net_triggered = True print(f"đŸ›Ąī¸ Safety Net Override Successful: {algo} ({bert_conf*100:.1f}%)") except Exception as e: print(f"Safety Net Error: {e}") conf_percentage = (final_conf * 100) if final_conf else 100.0 # ========================================== # 📚 YOUR FULL UI DICTIONARY # ========================================== complexity_map = { # --- SORTING --- "Bubble Sort": { "space": "O(1)", "explanation": "âš ī¸ CRITICAL: Bubble Sort is inefficient (O(n^2)) for large datasets. Refactor to Quick Sort or Merge Sort (O(n log n)).", "improvements": ["Added a 'swapped' flag to exit early if sorted.", "Shrink inner loop by 'i' each pass."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n n = len([FIRST_ARG])\n for i in range(n):\n swapped = False\n for j in range(0, n - i - 1):\n if [FIRST_ARG][j] > [FIRST_ARG][j + 1]:\n [FIRST_ARG][j], [FIRST_ARG][j + 1] = [FIRST_ARG][j + 1], [FIRST_ARG][j]\n swapped = True\n if not swapped: break\n return [FIRST_ARG]", "recommended_name": "Quick Sort OR Merge Sort (O(n log n))", "recommended_code": "# --- OPTION 1: QUICK SORT ---\nimport random\ndef [FUNC_NAME]_quicksort([ARGS]):\n if len([FIRST_ARG]) <= 1: return [FIRST_ARG]\n pivot = random.choice([FIRST_ARG])\n L = [x for x in [FIRST_ARG] if x < pivot]\n M = [x for x in [FIRST_ARG] if x == pivot]\n R = [x for x in [FIRST_ARG] if x > pivot]\n return [FUNC_NAME]_quicksort(L) + M + [FUNC_NAME]_quicksort(R)\n\n# --- OPTION 2: BUILT-IN SORT ---\ndef [FUNC_NAME]_timsort([ARGS]):\n return sorted([FIRST_ARG])" }, "Insertion Sort": { "space": "O(1)", "explanation": "âš ī¸ WARNING: Insertion Sort is slow (O(n^2)) for large lists. It is okay for small inputs (<50 items), but consider Quick Sort for scalability.", "improvements": ["Your logic is correct for small datasets, but fails to scale.", "For >50 items, pivot to a divide-and-conquer approach."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n for i in range(1, len([FIRST_ARG])):\n key = [FIRST_ARG][i]\n j = i - 1\n while j >= 0 and key < [FIRST_ARG][j]:\n [FIRST_ARG][j + 1] = [FIRST_ARG][j]\n j -= 1\n [FIRST_ARG][j + 1] = key\n return [FIRST_ARG]", "recommended_name": "Quick Sort OR Merge Sort (O(n log n))", "recommended_code": "# --- OPTION 1: QUICK SORT ---\ndef [FUNC_NAME]_quicksort([ARGS]):\n if len([FIRST_ARG]) <= 1: return [FIRST_ARG]\n pivot = [FIRST_ARG][len([FIRST_ARG]) // 2]\n return [FUNC_NAME]_quicksort([x for x in [FIRST_ARG] if x < pivot]) + \\\n [x for x in [FIRST_ARG] if x == pivot] + \\\n [FUNC_NAME]_quicksort([x for x in [FIRST_ARG] if x > pivot])" }, "Hash Map Lookup": { "space": "O(n)", "explanation": "✅ GOOD: Uses a dictionary (Hash Map) for instant O(1) lookups instead of repeatedly searching through a list. This drops the time complexity from O(n^2) down to a highly efficient O(n).", "improvements": ["You are correctly using a dictionary to map elements.", "This trades a small amount of memory O(n) for a massive speedup O(1) per lookup."], "optimized_code": "def [FUNC_NAME]([ARGS], target):\n seen = {}\n for i, val in enumerate([FIRST_ARG]):\n needed = target - val\n if needed in seen:\n return [seen[needed], i]\n seen[val] = i\n return []" }, "Selection Sort": { "space": "O(1)", "explanation": "âš ī¸ WARNING: Selection Sort is always O(n^2), even if the list is sorted. Switch to Insertion Sort (for small lists) or Merge Sort.", "improvements": ["Avoid this algorithm entirely for production code.", "Replace with an algorithm that adapts to already-sorted data."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n for i in range(len([FIRST_ARG])):\n min_idx = i\n for j in range(i+1, len([FIRST_ARG])):\n if [FIRST_ARG][j] < [FIRST_ARG][min_idx]:\n min_idx = j\n [FIRST_ARG][i], [FIRST_ARG][min_idx] = [FIRST_ARG][min_idx], [FIRST_ARG][i]\n return [FIRST_ARG]", "recommended_name": "Insertion Sort OR Merge Sort", "recommended_code": "# --- OPTION 1: INSERTION SORT ---\ndef [FUNC_NAME]_insertion([ARGS]):\n for i in range(1, len([FIRST_ARG])):\n key = [FIRST_ARG][i]\n j = i - 1\n while j >= 0 and key < [FIRST_ARG][j]:\n [FIRST_ARG][j + 1] = [FIRST_ARG][j]\n j -= 1\n [FIRST_ARG][j + 1] = key\n return [FIRST_ARG]" }, "Quick Sort": { "space": "O(log n)", "explanation": "✅ EXCELLENT: Quick Sort is a standard, efficient O(n log n) algorithm. Ensure you handle the worst-case pivot selection.", "improvements": ["Ensure your pivot is chosen randomly instead of always picking the first or last element."], "optimized_code": "import random\ndef [FUNC_NAME]([ARGS]):\n if len([FIRST_ARG]) <= 1: return [FIRST_ARG]\n pivot = random.choice([FIRST_ARG])\n left = [x for x in [FIRST_ARG] if x < pivot]\n middle = [x for x in [FIRST_ARG] if x == pivot]\n right = [x for x in [FIRST_ARG] if x > pivot]\n return [FUNC_NAME](left) + middle + [FUNC_NAME](right)" }, "Merge Sort": { "space": "O(n)", "explanation": "✅ EXCELLENT: Merge Sort is stable and consistent O(n log n). Great for large datasets.", "improvements": ["Your algorithm is optimal for time complexity.", "Be aware that Merge Sort uses O(n) extra memory."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n if len([FIRST_ARG]) > 1:\n mid = len([FIRST_ARG]) // 2\n L, R = [FIRST_ARG][:mid], [FIRST_ARG][mid:]\n [FUNC_NAME](L)\n [FUNC_NAME](R)\n i = j = k = 0\n while i < len(L) and j < len(R):\n if L[i] < R[j]:\n [FIRST_ARG][k] = L[i]\n i += 1\n else:\n [FIRST_ARG][k] = R[j]\n j += 1\n k += 1\n while i < len(L):\n [FIRST_ARG][k] = L[i]\n i, k = i + 1, k + 1\n while j < len(R):\n [FIRST_ARG][k] = R[j]\n j, k = j + 1, k + 1\n return [FIRST_ARG]" }, "Heap Sort": { "space": "O(1)", "explanation": "✅ GOOD: Heap Sort is memory efficient (O(1) extra space) and fast (O(n log n)).", "improvements": ["Use Python's built-in `heapq` library for C-level optimization."], "optimized_code": "import heapq\ndef [FUNC_NAME]([ARGS]):\n heapq.heapify([FIRST_ARG])\n return [heapq.heappop([FIRST_ARG]) for _ in range(len([FIRST_ARG]))]" }, "Counting Sort": { "space": "O(n + k)", "explanation": "✅ EFFICIENT: Very fast (O(n+k)) for integers with a small range. Not suitable for strings or large ranges.", "improvements": ["Ensure your data strictly contains integers with a known maximum value."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n if not [FIRST_ARG]: return [FIRST_ARG]\n max_val = max([FIRST_ARG])\n count = [0] * (max_val + 1)\n for num in [FIRST_ARG]: count[num] += 1\n idx = 0\n for i in range(len(count)):\n while count[i] > 0:\n [FIRST_ARG][idx] = i\n idx += 1\n count[i] -= 1\n return [FIRST_ARG]" }, # --- SEARCHING --- "Linear Search": { "space": "O(1)", "explanation": "âš ī¸ INEFFICIENT: iterating through every item is O(n). If your data is sorted, switch to Binary Search (O(log n)) for a massive speedup.", "improvements": ["Only checking items one by one requires O(n) time.", "If your data is sorted, use Binary Search."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n for i in range(len([FIRST_ARG])):\n if [FIRST_ARG][i] == target: return i # Target must be passed\n return -1", "recommended_name": "Binary Search (O(log n))", "recommended_code": "import bisect\ndef [FUNC_NAME]_binary([ARGS]):\n # Assuming [FIRST_ARG] is sorted\n idx = bisect.bisect_left([FIRST_ARG], target)\n if idx < len([FIRST_ARG]) and [FIRST_ARG][idx] == target:\n return idx\n return -1" }, "Binary Search": { "space": "O(1)", "explanation": "✅ PERFECT: Binary Search is the gold standard (O(log n)) for sorted arrays.", "improvements": ["Ensure your array is sorted first.", "You can manually write it with a while loop, or use Python's built in `bisect` library."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n # Manual implementation\n left, right = 0, len([FIRST_ARG]) - 1\n while left <= right:\n mid = (left + right) // 2\n if [FIRST_ARG][mid] == target: return mid\n elif [FIRST_ARG][mid] < target: left = mid + 1\n else: right = mid - 1\n return -1" }, "Jump Search": { "space": "O(1)", "explanation": "✅ GOOD: Jump Search (O(√n)) is better than Linear Search, but Binary Search is still faster if random access is allowed.", "improvements": ["If you are using standard lists, switch to Binary Search (O(log n))."], "optimized_code": "import math\ndef [FUNC_NAME]([ARGS]):\n n = len([FIRST_ARG])\n step = int(math.sqrt(n))\n prev = 0\n while [FIRST_ARG][min(step, n)-1] < target:\n prev = step\n step += int(math.sqrt(n))\n if prev >= n: return -1\n while [FIRST_ARG][prev] < target:\n prev += 1\n if prev == min(step, n): return -1\n if [FIRST_ARG][prev] == target: return prev\n return -1", "recommended_name": "Binary Search (O(log n))", "recommended_code": "import bisect\ndef [FUNC_NAME]_binary([ARGS]):\n idx = bisect.bisect_left([FIRST_ARG], target)\n if idx < len([FIRST_ARG]) and [FIRST_ARG][idx] == target:\n return idx\n return -1" }, "Nested Iterative": { "space": "O(1)", "explanation": "âš ī¸ WARNING: Nested loops usually indicate a 'brute force' O(n^2) time complexity. This scales poorly for large datasets and can often be optimized.", "improvements": ["Check if the inner loop can be replaced with a Hash Map (dictionary) for O(1) lookups.", "If analyzing contiguous subarrays, switch to the Sliding Window technique (O(n))."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n n = len([FIRST_ARG])\n # If you MUST use nested loops, ensure the inner loop shrinks each pass (j = i + 1)\n for i in range(n):\n for j in range(i + 1, n):\n pass # Your logic here\n return [FIRST_ARG]", "recommended_name": "Hash Map Lookup OR Sliding Window (O(n))", "recommended_code": "# --- OPTION 1: HASH MAP (For finding pairs/duplicates) ---\ndef [FUNC_NAME]_hashmap([ARGS]):\n seen = set()\n for item in [FIRST_ARG]:\n if item in seen: return item\n seen.add(item)\n return [FIRST_ARG]\n\n# --- OPTION 2: SLIDING WINDOW (For subarrays) ---\ndef [FUNC_NAME]_window([ARGS], k=2):\n # Assumes [FIRST_ARG] is a list of numbers\n window_sum = sum([FIRST_ARG][:k])\n for i in range(len([FIRST_ARG]) - k):\n window_sum = window_sum - [FIRST_ARG][i] + [FIRST_ARG][i+k]\n return window_sum" }, # --- RECURSION, DP, & MATH --- "Fibonacci Sequence": { "space": "O(n)", "explanation": "âš ī¸ RECURSION ALERT: Simple recursive Fibonacci is O(2^n) (Exponential). Refactor to use Dynamic Programming (Memoization) or an Iterative Loop to make it O(n).", "improvements": ["Recursion causes stack overflow risks."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n if [FIRST_ARG] <= 0: return 0\n if [FIRST_ARG] == 1: return 1\n return [FUNC_NAME]([FIRST_ARG]-1) + [FUNC_NAME]([FIRST_ARG]-2)", "recommended_name": "Iterative OR Memoized Fibonacci (O(n))", "recommended_code": "# --- OPTION 1: ITERATIVE (O(1) Space) ---\ndef [FUNC_NAME]_iterative([ARGS]):\n if [FIRST_ARG] <= 0: return 0\n if [FIRST_ARG] == 1: return 1\n a, b = 0, 1\n for _ in range(2, [FIRST_ARG] + 1):\n a, b = b, a + b\n return b\n\n# --- OPTION 2: MEMOIZATION (Caching) ---\nfrom functools import lru_cache\n@lru_cache(maxsize=None)\ndef [FUNC_NAME]_memoized([ARGS]):\n if [FIRST_ARG] <= 1: return [FIRST_ARG]\n return [FUNC_NAME]_memoized([FIRST_ARG]-1) + [FUNC_NAME]_memoized([FIRST_ARG]-2)" }, "Memoization": { "space": "O(n)", "explanation": "✅ EFFICIENT: You successfully applied Memoization (Top-Down DP) to prevent redundant calculations.", "improvements": ["Caching results prevents the O(2^n) exponential blow-up of standard recursion."], "optimized_code": "memo = {}\ndef [FUNC_NAME]([ARGS]):\n if [FIRST_ARG] in memo: return memo[[FIRST_ARG]]\n if [FIRST_ARG] <= 1: return [FIRST_ARG]\n memo[[FIRST_ARG]] = [FUNC_NAME]([FIRST_ARG]-1) + [FUNC_NAME]([FIRST_ARG]-2)\n return memo[[FIRST_ARG]]" }, "Tabulation": { "space": "O(n)", "explanation": "✅ EFFICIENT: You successfully applied Tabulation (Bottom-Up DP) to prevent recursion stack overflow limits.", "improvements": ["Iteratively building the table is memory safe and prevents RecursionError."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n if [FIRST_ARG] <= 0: return 0\n dp = [0] * ([FIRST_ARG] + 1)\n dp[1] = 1\n for i in range(2, [FIRST_ARG] + 1):\n dp[i] = dp[i-1] + dp[i-2]\n return dp[[FIRST_ARG]]" }, "Factorial (Recursive)": { "space": "O(n)", "explanation": "âš ī¸ STACK RISK: Recursive Factorial works, but large inputs will cause a `RecursionError`. Use an Iterative Loop for safety.", "improvements": ["Use a `for` loop to accumulate the result instead of recursion.", "Better yet, use Python's built in `math.factorial()`."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n if [FIRST_ARG] == 1 or [FIRST_ARG] == 0: return 1\n return [FIRST_ARG] * [FUNC_NAME]([FIRST_ARG] - 1)", "recommended_name": "Iterative Factorial (O(n))", "recommended_code": "import math\ndef [FUNC_NAME]_safe([ARGS]):\n # Built-in math functions run in C and avoid RecursionErrors\n return math.factorial([FIRST_ARG])" }, "Factorial (Iterative)": { "space": "O(1)", "explanation": "✅ GOOD: Iterative Factorial is safe and efficient (O(n)).", "improvements": ["Your logic is solid, but you can achieve even faster execution using the built-in math module."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n result = 1\n for i in range(2, [FIRST_ARG] + 1):\n result *= i\n return result" }, "Prime Check": { "space": "O(1)", "explanation": "✅ EFFICIENT: This O(√n) approach is much faster than checking all numbers up to N.", "improvements": ["Ensure your loop stops at the square root of n.", "Handle edge cases for 1, 2, and 3 explicitly."], "optimized_code": "import math\ndef [FUNC_NAME]([ARGS]):\n if [FIRST_ARG] <= 1: return False\n if [FIRST_ARG] in (2, 3): return True\n if [FIRST_ARG] % 2 == 0 or [FIRST_ARG] % 3 == 0: return False\n for i in range(5, int(math.sqrt([FIRST_ARG])) + 1, 6):\n if [FIRST_ARG] % i == 0 or [FIRST_ARG] % (i + 2) == 0: return False\n return True" }, "GCD (Euclidean)": { "space": "O(1)", "explanation": "✅ PERFECT: Euclidean algorithm is the most efficient way to find GCD.", "improvements": ["Use Python's built-in `math.gcd` for cleaner and slightly faster code."], "optimized_code": "def [FUNC_NAME](a, b):\n while b:\n a, b = b, a % b\n return abs(a)" }, "Palindrome Check": { "space": "O(1)", "explanation": "✅ GOOD: O(n) is the optimal complexity for checking palindromes.", "improvements": ["In Python, slicing is often faster than setting up a while loop with two pointers."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n return str([FIRST_ARG]) == str([FIRST_ARG])[::-1]" }, "Armstrong Number": { "space": "O(log n)", "explanation": "✅ GOOD: Analyzing digits is O(log n), which is optimal.", "improvements": ["Convert the number to a string to easily iterate over the digits."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n digits = str([FIRST_ARG])\n power = len(digits)\n return [FIRST_ARG] == sum(int(d)**power for d in digits)" }, # --- GRAPHS, POINTERS, & DATA STRUCTURES --- "Dijkstra's Algorithm": { "space": "O(V)", "explanation": "✅ INDUSTRY STANDARD: Best for finding shortest paths in weighted graphs.", "improvements": ["Ensure you are using a Priority Queue (`heapq`) to achieve O(E log V) time complexity."], "optimized_code": "import heapq\ndef [FUNC_NAME](graph, start):\n distances = {node: float('inf') for node in graph}\n distances[start] = 0\n pq = [(0, start)]\n while pq:\n curr_dist, curr_node = heapq.heappop(pq)\n if curr_dist > distances[curr_node]: continue\n for neighbor, weight in graph[curr_node].items():\n dist = curr_dist + weight\n if dist < distances[neighbor]:\n distances[neighbor] = dist\n heapq.heappush(pq, (dist, neighbor))\n return distances" }, "Heap-Based Algorithm": { "space": "O(N)", "explanation": "✅ GOOD: Ideal for dynamically finding the top K elements (smallest/largest), scheduling tasks, or building priority queues without sorting the whole list.", "improvements": ["Always use Python's built-in `heapq` module instead of manually sorting arrays with `.sort()`.", "Use `heapq.heapify()` to build your initial heap in O(N) time instead of pushing items one-by-one."], "optimized_code": "import heapq\n\ndef [FUNC_NAME](data, k):\n # O(N) time to build the heap in-place\n heapq.heapify(data)\n # Extract the k smallest elements efficiently\n result = [heapq.heappop(data) for _ in range(k)]\n return result" }, "Breadth-First Search": { "space": "O(V)", "explanation": "✅ GOOD: Perfect for shortest paths in unweighted graphs or level-order traversal.", "improvements": ["Always use `collections.deque` for the queue instead of a standard list."], "optimized_code": "from collections import deque\ndef [FUNC_NAME](graph, start):\n visited = set([start])\n queue = deque([start])\n result = []\n while queue:\n node = queue.popleft()\n result.append(node)\n for neighbor in graph[node]:\n if neighbor not in visited:\n visited.add(neighbor)\n queue.append(neighbor)\n return result" }, "BFS (Graph)": { "space": "O(V)", "explanation": "✅ GOOD: Perfect for shortest paths in unweighted graphs or level-order traversal.", "improvements": ["Always use `collections.deque` for the queue instead of a standard list."], "optimized_code": "from collections import deque\ndef [FUNC_NAME](graph, start):\n visited = set([start])\n queue = deque([start])\n result = []\n while queue:\n node = queue.popleft()\n result.append(node)\n for neighbor in graph[node]:\n if neighbor not in visited:\n visited.add(neighbor)\n queue.append(neighbor)\n return result" }, "Depth-First Search": { "space": "O(V)", "explanation": "✅ GOOD: Standard for pathfinding puzzles, topological sorting, and cycle detection.", "improvements": ["If recursion depth is a concern, switch to an iterative DFS using a stack."], "optimized_code": "def [FUNC_NAME](graph, start, visited=None):\n if visited is None: visited = set()\n visited.add(start)\n # Process node here\n for neighbor in graph[start]:\n if neighbor not in visited:\n [FUNC_NAME](graph, neighbor, visited)\n return visited" }, "DFS (Graph)": { "space": "O(V)", "explanation": "✅ GOOD: Standard for pathfinding puzzles, topological sorting, and cycle detection.", "improvements": ["If recursion depth is a concern, switch to an iterative DFS using a stack."], "optimized_code": "def [FUNC_NAME](graph, start, visited=None):\n if visited is None: visited = set()\n visited.add(start)\n # Process node here\n for neighbor in graph[start]:\n if neighbor not in visited:\n [FUNC_NAME](graph, neighbor, visited)\n return visited" }, "Sliding Window": { "space": "O(1)", "explanation": "✅ EFFICIENT: Sliding window prevents duplicate work when analyzing subarrays.", "improvements": ["Maintains a running sum/condition without needing nested O(n^2) loops."], "optimized_code": "def [FUNC_NAME](arr, k):\n current_sum = 0\n left = 0\n for right in range(len(arr)):\n current_sum += arr[right]\n if right - left + 1 > k:\n current_sum -= arr[left]\n left += 1\n return current_sum" }, "Two-Pointer Technique": { "space": "O(1)", "explanation": "✅ EFFICIENT: Two pointers walking towards each other saves incredible amounts of memory.", "improvements": ["Much faster than nested O(n^2) loops when dealing with sorted arrays."], "optimized_code": "def [FUNC_NAME](arr, target):\n left, right = 0, len(arr) - 1\n while left < right:\n s = arr[left] + arr[right]\n if s == target: return True\n elif s < target: left += 1\n else: right -= 1\n return False" }, "Binary Search Tree": { "space": "O(n)", "explanation": "â„šī¸ INFO: Operations are O(log n) on average, but can degrade to O(n) if the tree is unbalanced. Consider an AVL Tree or Red-Black Tree for guaranteed performance.", "improvements": ["Consider just using the built-in `dict` or `set` which are highly optimized Hash Tables in Python."], "optimized_code": "class Node:\n def __init__(self, key):\n self.left, self.right, self.val = None, None, key\n\ndef [FUNC_NAME](root, key):\n if root is None or root.val == key: return root\n if root.val < key: return [FUNC_NAME](root.right, key)\n return [FUNC_NAME](root.left, key)" }, "Stack Operations": { "space": "O(n)", "explanation": "✅ OPTIMAL: Push/Pop operations are O(1).", "improvements": ["Standard Python lists are perfect for stacks. Just ensure you only use `.append()` and `.pop()`."], "optimized_code": "def [FUNC_NAME]():\n stack = []\n stack.append('item') # Push O(1)\n item = stack.pop() # Pop O(1)\n return item" }, "Queue (List)": { "space": "O(n)", "explanation": "âš ī¸ WARNING: Using `list.pop(0)` in Python is O(n). Use `collections.deque` for true O(1) queue operations.", "improvements": ["Import 'deque' from the collections module.", "Use 'popleft()' instead of 'pop(0)' to achieve O(1) constant time."], "optimized_code": "def [FUNC_NAME]([ARGS]):\n # Using list.pop(0) causes O(n) memory shifts\n queue = list([FIRST_ARG])\n queue.append('new_item')\n item = queue.pop(0) \n return item", "recommended_name": "Collections.deque (True O(1) Queue)", "recommended_code": "from collections import deque\ndef [FUNC_NAME]_optimized([ARGS]):\n queue = deque([FIRST_ARG])\n queue.append('new_item')\n # queue.popleft() is now O(1) instead of O(n)\n item = queue.popleft()\n return queue" }, "Linked List (Singly)": { "space": "O(n)", "explanation": "â„šī¸ INFO: Insertions are O(1) if you have the pointer, but searching is O(n).", "improvements": ["Linked lists are rarely used in standard Python because standard lists are dynamic arrays."], "optimized_code": "class Node:\n def __init__(self, data):\n self.data = data\n self.next = None\n\nclass LinkedList:\n def __init__(self):\n self.head = None\n def print_list(self):\n temp = self.head\n while temp:\n print(temp.data)\n temp = temp.next" }, "Linked List (Doubly)": { "space": "O(n)", "explanation": "✅ FLEXIBLE: Doubly Linked Lists allow bidirectional traversal, at the cost of slightly more memory.", "improvements": ["Python's built-in `collections.deque` is actually a Doubly Linked List under the hood! Use it for max performance."], "optimized_code": "from collections import deque\n# deque is an optimized doubly linked list\ndef [FUNC_NAME]():\n dll = deque(['a', 'b', 'c'])\n dll.append('d') # Add to right\n dll.appendleft('z') # Add to left\n return dll" } } # 4. Fallback Data default_data = { "space": "O(N)", "explanation": f"CodeSense Engine Analysis: {ethan_summary}", "improvements": ["Analysis pending for this algorithm."], "optimized_code": "# Recognized Pattern. Specific optimization currently unavailable." } # Handle matching names (e.g. "Linear Search" vs "Linear Iterative" from different models) if algo == "Linear Iterative" and "Linear Search" in complexity_map: algo_key = "Linear Search" elif algo == "Recursive (Exponential)" and "Factorial (Recursive)" in complexity_map: algo_key = "Fibonacci Sequence" # General fallback for exponential recursion else: algo_key = algo result_data = complexity_map.get(algo_key, default_data) # --- YOUR MAGIC VARIABLE REPLACEMENT FOR BOTH CODES --- # 1. Format Optimized Code opt_code = result_data.get("optimized_code", "").replace("[FUNC_NAME]", analyzer.func_name).replace("[ARGS]", analyzer.args_string).replace("[FIRST_ARG]", analyzer.first_arg) # 2. Format Recommended Code (if it exists) rec_code = result_data.get("recommended_code", "") if rec_code: rec_code = rec_code.replace("[FUNC_NAME]", analyzer.func_name).replace("[ARGS]", analyzer.args_string).replace("[FIRST_ARG]", analyzer.first_arg) rec_name = result_data.get("recommended_name", "") # 5. Send EVERYTHING back to VS Code return jsonify({ "algorithm": algo, "confidence": f"{conf_percentage:.1f}%", "dynamic_complexity": dynamic_comp, "space_complexity": result_data.get("space", "O(N)"), "explanation": result_data.get("explanation", ""), "improvements": result_data.get("improvements", []), "optimized_code": opt_code, "recommended_name": rec_name, "recommended_code": rec_code, "safety_net_used": safety_net_triggered }) except Exception as e: import traceback print(traceback.format_exc()) return jsonify({"error": str(e)}), 500 if __name__ == '__main__': app.run(host='0.0.0.0', port=7860)